Problem 18
Question
The total number of restaurant purchased meals that the average person will eat in a restaurant, in a car, or at home in a year is \(170 .\) The total number of these meals eaten in a car or at home exceeds the number eaten in a restaurant by 14. Twenty more restaurant-purchased meals will be eaten in a restaurant than at home. (Source:The NPD Group) Find the number of restaurant purchased meals eaten in a restaurant, the number eaten in a car, and the number eaten at home.
Step-by-Step Solution
Verified Answer
The number of restaurant-purchased meals eaten in a restaurant is 78, the number eaten in a car is 34, and the number eaten at home is 58.
1Step 1: Define the variables
Let R represent the number of meals eaten in a restaurant, C represent the number of meals eaten in a car, and H represent the number of meals eaten at home.
2Step 2: Write the equations
We are given that the total number of restaurant-purchased meals is 170, so we can write the first equation as:
\(R + C + H = 170\)
The total number of meals eaten in a car or at home exceeds the number eaten in a restaurant by 14. This can be represented as:
\(C + H = R + 14\)
Finally, we are told that twenty more restaurant-purchased meals will be eaten in a restaurant than at home, which can be represented as:
\(R = H + 20\)
3Step 3: Solve the system of equations
We have the following system of equations:
1. \(R + C + H = 170\)
2. \(C + H = R + 14\)
3. \(R = H + 20\)
We can substitute the third equation into the first two equations to eliminate R:
1. \((H + 20) + C + H = 170\)
2. \(C + H = (H + 20) + 14\)
Now, we can solve the first equation for C:
\(C = 170 - 2H - 20\)
\(C = 150 - 2H\)
Next, substitute the expression for C into the second equation:
\(150 - 2H + H = H + 34\)
4Step 4: Solve for H
Simplify and solve the equation:
\(150 - H = H + 34\)
\(116 = 2H\)
\(H = 58\)
5Step 5: Find R and C
Now that we have the value of H, we can find the values of R and C using the equations we found earlier:
\(R = H + 20 = 58 + 20 = 78\)
\(C = 150 - 2H = 150 - 2(58) = 150 - 116 = 34\)
6Step 6: State the solution
The number of restaurant-purchased meals eaten in a restaurant is 78, the number eaten in a car is 34, and the number eaten at home is 58.
Key Concepts
VariablesEquationsSubstitutionSolution
Variables
In the context of a system of equations, variables are symbols that stand for unknown values we aim to determine. In our exercise about meal consumption habits, we define three variables:
- R: Representing the number of meals eaten in a restaurant.
- C: Representing the number of meals eaten in a car.
- H: Representing the number of meals eaten at home.
Equations
Equations are mathematical statements that assert the equality of two expressions. When dealing with a system of equations, we use multiple equations to represent the relationship between different variables. In this exercise:
- The first equation, \(R + C + H = 170\), expresses the total number of meals eaten in different places by summing up all the variables.
- The second equation, \(C + H = R + 14\), tells us that meals eaten in a car or at home together exceed those eaten in a restaurant by 14.
- The third equation, \(R = H + 20\), signifies that there are twenty more meals eaten in a restaurant compared to those at home.
Substitution
Substitution is a method for solving a system of equations wherein we solve one equation for one variable in terms of the others and then substitute this expression into the other equations. This allows us to systematically eliminate variables and solve for one at a time.
In our exercise, using the equation \(R = H + 20\), we can substitute the expression for \(R\) into the other equations:
In our exercise, using the equation \(R = H + 20\), we can substitute the expression for \(R\) into the other equations:
- Replace \(R\) in \(R + C + H = 170\) to obtain: \((H + 20) + C + H = 170\).
- Similarly, substitute in \(C + H = R + 14\) to get: \(C + H = (H + 20) + 14\).
Solution
A solution to a system of equations is a set of values for the variables that make all equations true simultaneously. Finding the solution involves using techniques like substitution to simplify and solve for individual variables.
In our exercise, after substituting and simplifying, we determined:
In our exercise, after substituting and simplifying, we determined:
- From the equation \(150 - H = H + 34\), simplified to \(116 = 2H\), we solved to find \(H = 58\).
- With \(H\) known, we calculated \(R = H + 20\) to find \(R = 78\).
- Finally, using \(C = 150 - 2H\), we found \(C = 34\).
Other exercises in this chapter
Problem 17
Find an equation of the circle with the given center and radius. Center \((4,1) ;\) radius \(=5\)
View solution Problem 17
Solve each system. $$\begin{array}{c} 3 x^{2}+4 y=-1 \\ x^{2}+3 y=-12 \end{array}$$
View solution Problem 18
Solve the exponential equation algebraically. Then check using a graphing calculator. $$e^{-t}=0.04$$
View solution Problem 18
Solve. $$\frac{2}{x^{2}-9}+\frac{5}{x-3}=\frac{3}{x+3}$$
View solution