Problem 18
Question
The functions \(f(x)=\log (x-1)-\log (x-2)\) and \(g(x)=\) \(\log \left(\frac{x-1}{x-2}\right)\) are identical when \(x\) lies in the interval (A) \([1,2]\) (B) \([2, \infty]\) (C) \((2, \infty)\) (D) \((-\infty, \infty)\)
Step-by-Step Solution
Verified Answer
(C) (2, ∞)
1Step 1: Understand the Function f(x)
Start by evaluating the function \( f(x) = \log (x-1) - \log (x-2) \). This can be simplified using the logarithm property \( \log(a) - \log(b) = \log\left(\frac{a}{b}\right) \), leading to \( f(x) = \log\left(\frac{x-1}{x-2}\right) \).
2Step 2: Compare with g(x)
The function \( g(x) = \log \left( \frac{x-1}{x-2} \right) \) is given and is identical to the simplified form of \( f(x) \). Therefore, \( f(x) = g(x) \).
3Step 3: Determine the Domain of f(x) and g(x)
For \( f(x) \) and \( g(x) \) to be defined, the expressions inside the logarithms, \( x-1 \) and \( x-2 \), must be positive. This requires \( x-1 > 0 \rightarrow x > 1 \) and \( x-2 > 0 \rightarrow x > 2 \). Hence, the domain of these functions is \( x > 2 \).
4Step 4: Choose the Correct Interval
Based on the domain determined, these functions are defined when \( x \) lies in the interval \((2, \infty)\). This corresponds to option (C).
Key Concepts
Logarithmic FunctionsFunction DomainInterval Notation
Logarithmic Functions
Logarithmic functions are mathematical expressions involving logarithms, which are the inverse operations of exponential functions. A logarithm answers the question: "To what exponent must we raise a specific base to obtain a given number?" In mathematical terms, if we have a logarithm of the form \[ \log_b(a) = c \]where \( b \) is the base, \( a \) is the argument, and \( c \) is the exponent. This means that \( b^c = a \).
- The base of a logarithm must be a positive number, not equal to one.
- The argument (inside the logarithm) must be positive.
- Common bases are \( e \) (natural logarithm) and 10 (common logarithm).
Function Domain
The domain of a function is the set of all possible input values (usually \( x \)) for which the function is defined. For logarithmic functions, the domain is determined by the condition that the argument inside the logarithm must be greater than zero because a logarithm of zero or a negative number is undefined in real numbers.
In the context of the exercise, to find the domain of the given functions \( f(x) = \log(x-1) - \log(x-2) \) or equivalently \( g(x) = \log \left(\frac{x-1}{x-2}\right) \), the expressions \( x-1 \) and \( x-2 \) must be positive:
In the context of the exercise, to find the domain of the given functions \( f(x) = \log(x-1) - \log(x-2) \) or equivalently \( g(x) = \log \left(\frac{x-1}{x-2}\right) \), the expressions \( x-1 \) and \( x-2 \) must be positive:
- For \( x-1 > 0 \): \( x > 1 \)
- For \( x-2 > 0 \): \( x > 2 \)
Interval Notation
Interval notation is a mathematical shorthand used to describe continuous sets of real numbers, often representing the domain or range of a function. It employs brackets and parentheses to specify which endpoint values are included or excluded.
- "[ ]" brackets signify that the endpoint is included (closed interval).
- "( )" parentheses suggest that the endpoint is not included (open interval).
Other exercises in this chapter
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