Problem 18
Question
Suppose curl \(\mathbf{F}=0\) and div \(\mathbf{F}=0 .\) (a) Why is \(\mathbf{F}\) the gradient of a potential? (b) Why does the potential satisfy Laplace's equation \(f_{x x}+f_{y y}+f_{z z}=0^{2}\)
Step-by-Step Solution
Verified Answer
(a) \(\mathbf{F}\) is the gradient of a potential because curl is zero. (b) The potential satisfies Laplace's equation because divergence is zero.
1Step 1: Understand the Condition curl 𝐹 = 0
The condition \(abla \times \mathbf{F} = 0\) indicates that the vector field \(\mathbf{F}\) is irrotational. This means that \(\mathbf{F}\) has no circulation and is locally the gradient of some scalar function. Thus, \(\mathbf{F}\) can be expressed as \(abla f\), where \(f\) is a scalar potential function.
2Step 2: Interpret div 𝐹 = 0
The condition \(abla \cdot \mathbf{F} = 0\) implies that the vector field \(\mathbf{F}\) is divergence-free. This signifies that there is no net flow out of any region in the field, consistent with \(\mathbf{F}\) being expressible as the curl of another vector field.
3Step 3: Show 𝐹 as Gradient of a Potential Function
Since \(\mathbf{F}\) is irrotational (curl-free), it can be expressed as the gradient of a potential function \(f\) such that \(\mathbf{F} = abla f\). This is directly derived from the fundamental theorem for gradients, which states a vector field is the gradient of a scalar potential if and only if it is irrotational.
4Step 4: Explain Why Potential Satisfies Laplace's Equation
Given \(\mathbf{F} = abla f\) and \(abla \cdot \mathbf{F} = 0\), substitute to get \(abla \cdot abla f = 0\). This equation is equivalent to the Laplace’s equation \(abla^2 f = 0\), meaning the potential function \(f\) must satisfy Laplace's equation.
Key Concepts
CurlDivergencePotential FunctionLaplace's Equation
Curl
In vector calculus, the concept of _curl_ helps us understand the rotational aspects of a vector field. A vector field, denoted as \( \mathbf{F} \), is often seen as an arrow field representing velocities or forces.
The curl operation shows how much, and in what direction, the vector field rotates around a point. Mathematically, the curl is expressed as \( abla \times \mathbf{F} \).
The curl operation shows how much, and in what direction, the vector field rotates around a point. Mathematically, the curl is expressed as \( abla \times \mathbf{F} \).
- If the result is zero, \( abla \times \mathbf{F} = 0 \), it indicates an _irrotational_ field. This means there is no rotation or vortex-like structure within the field.
- In our exercise, since \( \text{curl} \, \mathbf{F} = 0 \), it tells us that \( \mathbf{F} \) is irrotational, meaning \( \mathbf{F} \) can be expressed as the gradient of some scalar potential function.
Divergence
Another fundamental concept in vector fields is _divergence_, captured by the operation \( abla \cdot \mathbf{F} \). This measures the magnitude of a source or sink at a given point. In simpler terms, divergence denotes how much a vector field spreads out or converges at that point.
- If \( abla \cdot \mathbf{F} = 0 \), the field is _divergence-free_. This implies there is no local "outflow" or "inflow" at any given point, similar to an incompressible fluid with constant density.
- Our exercise states \( \text{div} \, \mathbf{F} = 0 \), suggesting no net flow is exiting or entering any region in the field.
Potential Function
A _potential function_, commonly denoted \( f \), is a scalar field from which a vector field can be derived. When a vector field \( \mathbf{F} \) is known to have zero curl, it is often the gradient of such a potential function.
- The gradient of \( f \), written as \( abla f \), produces the vector field \( \mathbf{F} \) in this situation.
- The essence lies in the fundamental theorem for gradients, which tells us a vector field is irrotational if and only if it is the gradient of some scalar potential. This links the concept of a potential function directly to the idea of an irrotational vector field.
Laplace's Equation
_Laplace's Equation_ is a critical equation in mathematical physics, expressed as \( abla^2 f = 0 \). It represents a harmonic function, typically implying that the function \( f \) does not change "on average" around any small region.
- In our scenario, because \( abla \cdot \mathbf{F} = 0 \) and \( \mathbf{F} = abla f \), it simplifies to \( abla \cdot abla f = abla^2 f = 0 \).
- Thus, the potential function \( f \), derived from \( \mathbf{F} \), satisfies Laplace's equation, ensuring it is _harmonic_.
Other exercises in this chapter
Problem 17
Explain why \(\iint\) curl \(\mathbf{F} \cdot \mathbf{n} d S=0\) over the closed boundary of any solid \(V\).
View solution Problem 17
Compute \(\partial f / \partial x\) and \(\partial f / \partial y\) in \(11-18\). Draw the gradient field \(\mathbf{F}=\) grad \(f\) and the equipotentials \(f(
View solution Problem 18
Compute the surface integrals \(\iint g(x, y, z) d S\). \(g=x\) on the cylinder \(x^{2}+y^{2}=4\) between \(z=0\) and \(z=3\).
View solution Problem 19
Find a potential \(f\) if it exists. $$\mathbf{F}=z \mathbf{i}+\mathbf{j}+x \mathbf{k}$$
View solution