Problem 18
Question
Solve the proportion. Check for extraneous solutions. $$\frac{4}{2 x}=\frac{7}{3}$$
Step-by-Step Solution
Verified Answer
The solution to the proportion is \(x = 0.857\).
1Step 1: Cross-Multiply
Cross-multiply the two fractions which means multiply the numerator of the first fraction by the denominator of the second fraction and the denominator of the first fraction by the numerator of the second fraction. The equation becomes \(4 * 3 = 2x * 7\), which simplifies to \(12 = 14x\).
2Step 2: Solve the Equation
Divide both sides of the equation by 14 to solve for x. So, \(x = 12/14\) which simplifies to \(x = 0.857\).
3Step 3: Check for Extraneous Solutions
Substitute the value of x obtained in the original proportion to check if it is a correct solution or an extraneous solution. Plugging in \(0.857\) for x, we get \(\frac{4}{2 * 0.857} \approx \frac{7}{3}\). Both sides of the equation are approximately equal, verifying our solution.
Key Concepts
Cross-MultiplicationExtraneous SolutionsEquation Solving
Cross-Multiplication
Cross-multiplication is a powerful tool that allows you to solve proportions easily. A proportion is an equation that states two ratios are equal. In simple terms, if you have a fraction on each side of the equation, you can solve the proportion using cross-multiplication.
Here's how it works: multiply the numerator of the first fraction by the denominator of the second fraction, and the denominator of the first fraction by the numerator of the second fraction. For the equation \(\frac{4}{2x} = \frac{7}{3}\), you would do the following steps:
Here's how it works: multiply the numerator of the first fraction by the denominator of the second fraction, and the denominator of the first fraction by the numerator of the second fraction. For the equation \(\frac{4}{2x} = \frac{7}{3}\), you would do the following steps:
- Multiply 4 by 3, getting 12.
- Multiply 2x by 7, getting 14x.
Extraneous Solutions
When solving equations, especially involving proportions, you need to be mindful of extraneous solutions. These are values that emerge during the solving process but do not satisfy the original equation.
An extraneous solution often appears when you're dealing with fractions or square roots because of the operations used to eliminate these terms. To detect if a solution is extraneous, plug the result back into the original equation. If both sides of the equation match up or are nearly equal, your solution is likely correct.
In our proportion \(\frac{4}{2x} = \frac{7}{3}\), after finding that \(x = 0.857\), we substitute it back. Both sides approximate the same value, confirming it’s not an extraneous solution. Always make sure to cross-check, as this verification step is crucial in confirming your results.
An extraneous solution often appears when you're dealing with fractions or square roots because of the operations used to eliminate these terms. To detect if a solution is extraneous, plug the result back into the original equation. If both sides of the equation match up or are nearly equal, your solution is likely correct.
In our proportion \(\frac{4}{2x} = \frac{7}{3}\), after finding that \(x = 0.857\), we substitute it back. Both sides approximate the same value, confirming it’s not an extraneous solution. Always make sure to cross-check, as this verification step is crucial in confirming your results.
Equation Solving
Equation solving involves finding the unknown variable that makes the equation true. After cross-multiplying, you'll usually end up with a linear equation, which is much easier to tackle.
From our cross-multiplication, we derived \(12 = 14x\). To solve for \(x\), divide both sides by 14:
Remember to solve equations systematically:\
From our cross-multiplication, we derived \(12 = 14x\). To solve for \(x\), divide both sides by 14:
- \(x = \frac{12}{14}\)
Remember to solve equations systematically:\
- Isolate the variable.
- Simplify each step as much as possible.
- Check your solution by substituting back into the original equation.
Other exercises in this chapter
Problem 18
Simplify the expression. $$\frac{9}{5 x}-\frac{2}{x^{2}}$$
View solution Problem 18
Solve the equation by cross multiplying. $$\frac{6}{x+2}=\frac{x}{4}$$
View solution Problem 18
Simplify the expression if possible. $$\frac{x^{2}+25}{2 x+10}$$
View solution Problem 18
Divide. Divide \(9 m^{3}+4 m^{2}-8 m\) by \(m\).
View solution