Problem 18
Question
Solve each system by substitution. $$\begin{aligned}&3 y=5 x+6\\\&x+y=2\end{aligned}$$
Step-by-Step Solution
Verified Answer
The solution is \((x, y) = (0, 2)\).
1Step 1: Express one variable in terms of the other
We start with the equation \(x + y = 2\). Solve for \(y\) in terms of \(x\):\[ y = 2 - x \]
2Step 2: Substitute expression into the other equation
Take the expression for \(y\) from Step 1 and substitute it into the first equation, \(3y = 5x + 6\):\[ 3(2 - x) = 5x + 6 \]
3Step 3: Solve the equation
Distribute and simplify the equation:\[ 6 - 3x = 5x + 6 \]Move \(-3x\) to the right side:\[ 6 = 8x + 6 \]Subtract 6 from both sides:\[ 0 = 8x \]Divide by 8 to solve for \(x\):\[ x = 0 \]
4Step 4: Find the value of the other variable
Use the value of \(x\) from Step 3 in the expression from Step 1:\[ y = 2 - x = 2 - 0 = 2 \]
5Step 5: Verify the solution
Substitute \(x = 0\) and \(y = 2\) back into the original equations to ensure correctness. For \(3y = 5x + 6\):\[ 3(2) = 5(0) + 6 \]\[ 6 = 6 \] (True)For \(x + y = 2\):\[ 0 + 2 = 2 \] (True)
Key Concepts
System of EquationsAlgebraic ManipulationLinear EquationsVerification of Solutions
System of Equations
A system of equations consists of two or more equations with the same set of variables. In this exercise, we are given two equations:
- Equation 1: \(3y = 5x + 6\)
- Equation 2: \(x + y = 2\)
Algebraic Manipulation
Algebraic manipulation is the process of rearranging equations using algebraic properties to simplify them or isolate variables. In the substitution method, algebraic manipulation is essential. Let’s look at how we used it in this exercise:
- **Rearranging Equations**: From Equation 2, \(x + y = 2\), we rearranged it to express \(y\) in terms of \(x\): \(y = 2 - x\).
- **Substituting Values**: We substituted the expression for \(y\) into Equation 1, \(3(2 - x) = 5x + 6\), which involved distributing and combining like terms.
Linear Equations
Linear equations are equations of the first degree, meaning their variables are not raised to any power greater than one. Each linear equation represents a straight line when graphed on a coordinate plane. For example, \(3y = 5x + 6\) can be rewritten as \(y = \frac{5}{3}x + 2\), depicting a line with a slope of \(\frac{5}{3}\) and a y-intercept of 2.
- **Characteristics of Linear Equations**:
- The graph of linear equations is always a straight line.
- They have a constant rate of change, described by the slope.
- There’s a unique intersection point in a consistent system, as seen with our solution \((0, 2)\).
Verification of Solutions
Verification is a crucial step in solving systems of equations to ensure the obtained solution is correct. After solving the equations using substitution, we obtain values for \(x\) and \(y\).
- **Substitute Back**: Replace the variables in the original equations to check if they satisfy both:
- Substituting into \(3y = 5x + 6\): \(3(2) = 5(0) + 6\), which simplifies to \(6 = 6\), a true statement.
- Substituting into \(x + y = 2\): \(0 + 2 = 2\), also a true statement.
Other exercises in this chapter
Problem 18
Perform each operation if possible. $$\left[\begin{array}{rr}9 & 4 \\ -8 & 2\end{array}\right]+\left[\begin{array}{cc}-3 & 2 \\ -4 & 7\end{array}\right]$$
View solution Problem 18
Solve each system analytically. If the equations are dependent, write the solution set in terms of the variable \(z\). $$\begin{aligned} 3 x-2 y-8 z &=1 \\ 9 x-
View solution Problem 19
Find each determinant. $$\operatorname{det}\left[\begin{array}{rrr}1 & -2 & 3 \\\0 & 0 & 0 \\\1 & 10 & -12\end{array}\right]$$
View solution Problem 19
Graph each inequality. $$y
View solution