Problem 18
Question
Solve each of the following for the indicated variable. \(A=l w\) for \(l\) (Area of a rectangle)
Step-by-Step Solution
Verified Answer
\( l = \frac{A}{w} \)
1Step 1: Understand the Equation
The equation given is for the area of a rectangle, which is represented as \( A = lw \), where \( A \) is the area, \( l \) is the length, and \( w \) is the width of the rectangle. Our task is to solve for \( l \), the length.
2Step 2: Isolate the Variable
To find \( l \), we need to isolate it on one side of the equation \( A = lw \). We can do this by dividing both sides of the equation by \( w \), the width. This gives us the formula \( l = \frac{A}{w} \), which expresses the length in terms of the area and the width.
3Step 3: Confirm the Solution
After isolating \( l \), the formula \( l = \frac{A}{w} \) should make logical sense: the length is the area divided by the width. This formula is now correctly solved for the variable \( l \).
Key Concepts
Area of a RectangleIsolating VariablesLength and Width Calculations
Area of a Rectangle
The concept of the area of a rectangle is foundational in both geometry and algebra. It tells us about the space contained within a rectangle's boundaries. To calculate this area, one multiplies the rectangle's length (denoted as \( l \)) by its width (denoted as \( w \)). The resulting expression is given by the formula: \[ A = lw \] where \( A \) is the area. This simple formula allows us to determine how much surface a rectangle covers. Understanding this concept helps solve numerous real-world problems, from calculating floor spaces to determining the amount of paint needed for a wall. Knowing the area allows us to rearrange this formula to solve for other unknowns, such as length or width, if the other dimensions are known.
Isolating Variables
Isolating a variable is a crucial skill in algebra. It involves rearranging an equation to solve for a specific variable. In the equation \( A = lw \), if we are tasked to find the length \( l \), we must isolate it. This is done by manipulating the equation to express \( l \) in terms of \( A \) and \( w \). We need to get \( l \) alone on one side of the equation:
- Start with the formula for the area: \( A = lw \).
- Divide both sides by \( w \) to isolate \( l \): \( l = \frac{A}{w} \).
Length and Width Calculations
Length and width calculations are essential for practical applications. With the formula \( l = \frac{A}{w} \), we can determine the length of a rectangle when its area and width are known. This calculation is directly derived from the basic principle of isolating variables.Consider a problem where we know a rectangle's area is 50 square units, and its width is 5 units. Using our derived formula:
- Substitute \( A = 50 \) and \( w = 5 \) into the formula \( l = \frac{A}{w} \).
- This gives \( l = \frac{50}{5} \).
- Calculate to find \( l = 10 \) units.
Other exercises in this chapter
Problem 18
Solve each of the inequalities and express the solution sets in interval notation. \(x \geq 2.1+0.3 x\)
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Express each interval as an inequalit using the variable \(x\). For example, we can express the inter val \([5, \infty)\) as \(x \geq 5\). \(x+2
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Solve each equation. \(0.3(2 n-5)=11-0.65 n\)
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Solve each equation. \(\frac{2 x+1}{3}-\frac{x+1}{7}=-\frac{1}{3}\)
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