Problem 18
Question
Solve each equation. You will need to use the factoring techniques that we discussed throughout this chapter. $$1-x^{2}=0$$
Step-by-Step Solution
Verified Answer
The solutions are \(x = 1\) and \(x = -1\).
1Step 1: Recognize the Equation Type
The equation given is \(1 - x^2 = 0\). This is a quadratic equation which can be rewritten as \(-x^2 + 1 = 0\) or \(1 - x^2 = 0\). We notice that this equation is a difference of squares.
2Step 2: Apply Difference of Squares Formula
The difference of squares formula is \(a^2 - b^2 = (a-b)(a+b)\). In our equation, we have \(1 - x^2 = (1)^2 - (x)^2\). Therefore, it factors into \((1-x)(1+x) = 0\).
3Step 3: Solve Each Factor
Set each factor equal to zero: 1. \((1-x) = 0\)2. \((1+x) = 0\)Solve for \(x\) in each equation.
4Step 4: Solve for x in (1-x)=0
For the equation \(1-x = 0\), add \(x\) to both sides to get \(1 = x\). So, one solution is \(x = 1\).
5Step 5: Solve for x in (1+x)=0
For the equation \(1+x = 0\), subtract 1 from both sides to get \(x = -1\). Thus, the other solution is \(x = -1\).
6Step 6: Final Solution
The solutions to the equation \(1-x^{2}=0\) are \(x = 1\) and \(x = -1\).
Key Concepts
Factoring TechniquesDifference of SquaresSolving Equations Step by Step
Factoring Techniques
Understanding factoring techniques is crucial for solving quadratic equations efficiently. Factoring is simply the process of breaking down an expression into simpler terms, or factors, that, when multiplied together, give the original expression. The key to successful factoring is recognizing different patterns or using specific techniques.
- Recognize Patterns: A common pattern is the difference of squares, where the expression looks like \(a^2 - b^2\).
- Utilize Common Factors: First, always look for a greatest common factor (GCF) that can be factored out of an equation. This can simplify the equation and make further factoring easier.
Difference of Squares
The difference of squares is a specific factoring technique used for expressions of the form \(a^2 - b^2\). This pattern is unique because it can be easily factored into a pair of binomials:(a-b)(a+b).This works due to the relationship between squares, where the middle terms cancel each other out:
- The expanded form \((a-b)(a+b)\) results in \(a^2 - b^2\) because the \(-ab\) and \(+ab\) terms cancel.
- This makes the equation easier to solve as it provides two simpler linear equations after factoring.
Solving Equations Step by Step
Solving quadratic equations using factoring involves a clear, step-by-step process. This ensures no steps are missed and results are accurate. Here are the typical steps:1. Identify the equation type: Determine if the equation can be factored using a recognizable pattern, such as the difference of squares in our example.2. Apply the appropriate factorization technique: Depending on the pattern, rewrite the equation in its factored form. For \(1-x^2=0\), we used the difference of squares.3. Set each factor to zero: Break down the factored equation into simpler parts. For \((1-x)(1+x)=0\), split into two equations: \(1-x=0\) and \(1+x=0\).4. Solve each equation:
- For \(1-x=0\), adding \(x\) to both sides gives \(x=1\).
- For \(1+x=0\), subtracting \(1\) from both sides results in \(x=-1\).
Other exercises in this chapter
Problem 17
Find each product. $$\left(-\frac{3}{4} a b\right)\left(\frac{1}{5} a^{2} b^{3}\right)$$
View solution Problem 17
Add the given polynomials. \(12 a^{2} b^{2}-9 a b\) and \(5 a^{2} b^{2}+4 a b\)
View solution Problem 18
Factor completely each of the polynomials and indicate any that are not factorable using integers. $$a^{2}+2 a b-63 b^{2}$$
View solution Problem 18
Use the difference-of-squares pattern to factor each of the following. $$16 s^{2}-(3 t+1)^{2}$$
View solution