Problem 18
Question
Sketch the graph of each function and determine whether the function has any absolute extreme values on its domain. Explain how your answer is consistent with Theorem 1. $$h(x)=\left\\{\begin{array}{ll} \frac{1}{x}, & -1 \leq x < 0 \\ \sqrt{x}, & 0 \leq x \leq 4 \end{array}\right.$$
Step-by-Step Solution
Verified Answer
The function has an absolute minimum of 0 at \(x=0\) and an absolute maximum of 2 at \(x=4\).
1Step 1: Analyze the Piecewise Function
The given function \( h(x) \) is a piecewise function. For \( -1 \leq x < 0 \), it is defined as \( \frac{1}{x} \), which is a hyperbolic shape that increases negatively toward infinity as \( x \) approaches 0. For \( 0 \leq x \leq 4 \), it is defined as \( \sqrt{x} \), which is a square root function beginning at \( (0, 0) \) and increasing to \( (4, 2) \).
2Step 2: Sketch the Graph
On a coordinate plane, sketch the graph of \( h(x) \). Start by plotting the curve \( \frac{1}{x} \) for \( -1 \leq x < 0 \), which will asymptotically approach the y-axis without touching it. Then plot \( \sqrt{x} \) from \( (0, 0) \) to \( (4, 2) \), forming a curved line that starts from the origin and curves upward to the point \( (4, 2) \). The graph does not define \( h(0) \) for \( \frac{1}{x} \); thus, there is a gap at \( x = 0 \).
3Step 3: Identify Absolute Extreme Values
For the subdomain \( -1 \leq x < 0 \), note that \( \frac{1}{x} \) approaches negative infinity as \( x \to 0^- \). There is no maximum or minimum here. For \( 0 \leq x \leq 4 \), \( \sqrt{x} \) has an absolute minimum at \( x = 0 \) where \( h(0) = 0 \) and an absolute maximum at \( x = 4 \) where \( h(4) = 2 \). Thus, in the domain as a whole, the function has an absolute minimum of 0 at \( x=0 \) and an absolute maximum of 2 at \( x=4 \).
4Step 4: Consistency with Theorem 1
Theorem 1 states that if a function is continuous on a closed interval, then it must have both a maximum and a minimum on that interval. \( h(x) \) is continuous on its closed subdomain \( [0, 4] \), and it does attain absolute extreme values there. However, \( h(x) \) is not continuous over the entire domain \([-1, 4]\) due to the discontinuity at \( x = 0^{-} \), which explains the absence of maximum in that portion.
Key Concepts
Hyperbolic FunctionsSquare Root FunctionsAbsolute Extreme Values
Hyperbolic Functions
Hyperbolic functions arise in various mathematical contexts, defined similarly to traditional trigonometric functions but for the hyperbola. A hyperbolic function can appear in a piecewise function like in our analysis of the function \( h(x) \). In this case, we have \( f(x) = \frac{1}{x} \) as our hyperbolic component, which behaves characteristically with certain features:
- As \( x \) approaches 0 from the negative side, \( \frac{1}{x} \) sharply decreases, moving toward negative infinity.
- This creates a vertical asymptote at \( x = 0 \), meaning the graph comes infinitely close to the axis but never actually reaches it.
- This feature is typical for hyperbolic functions, which often describe hyperbolic growth or decay, common in physics and engineering.
Square Root Functions
Square root functions are another elementary function form, often paired in exercises like these to demonstrate different growth behaviors. In the piecewise function provided, the segment \( \sqrt{x} \) covers the interval \( 0 \leq x \leq 4 \):
- Starting from the origin (0,0), the graph of \( \sqrt{x} \) shows a gentle curve upwards, reaching the point (4,2).
- Each value of \( x \) in its domain corresponds to a non-negative \( y \)-value, making this function strictly increasing.
- The gentle curve is an essential characteristic of square root functions, representing slower growth rates compared to linear ones.
Absolute Extreme Values
Absolute extreme values are important in analyzing a function's behavior within its domain—pinpointing where the function hits its highest and lowest points. For this piecewise function:
- The absolute minimum occurs at \( x = 0 \) with \( h(0) = 0 \), marking where the function hits its lowest point on the graph.
- The absolute maximum happens at \( x = 4 \) with \( h(4) = 2 \), noting the highest point.
- In detailing this, we're consistent with Theorem 1, which states there must be a max and min in continuous intervals.
Other exercises in this chapter
Problem 18
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