Problem 18
Question
Sketch the angle. Then find its reference angle. \(-370^{\circ}\)
Step-by-Step Solution
Verified Answer
The equivalent positive angle for -370 degrees is 350 degrees. The reference angle for this is 10 degrees.
1Step 1: Converting the Negative Angle into Positive
If the angle is negative, add 360 degrees to the angle until the answer lies between 0 and 360 degrees.\n\( -370^{\circ} + 360^{\circ} = -10^{\circ} \)\nAgain we add 360 to -10 degrees.\n\-10^{\circ} + 360^{\circ} = 350^{\circ}\nSo, -370 degrees is the same as 350 degrees.
2Step 2: Sketching the Angle
Place the angle in the appropriate quadrant on a graph and make a sketch. The positive equivalent angle of \(350^{\circ}\) will be in the IV quadrant.
3Step 3: Finding the Reference Angle
The reference angle is the acute angle formed with the x-axis. For angles in the IV quadrant, the reference angle \(\Theta'\) is measured clockwise from the x-axis and is calculated by subtracting the angle from 360 degrees.\n\(\Theta' = 360^{\circ} - \Theta = 360^{\circ} - 350^{\circ} = 10^{\circ}\)\nSo, the reference angle for -370 degrees is 10 degrees.
Key Concepts
Negative Angle ConversionQuadrants in TrigonometryAngle Sketching
Negative Angle Conversion
In trigonometry, angles can be positive or negative. A negative angle typically means it is measured clockwise from the positive x-axis. To work with negative angles, it's often useful to convert them into positive angles by adding or subtracting full circles (360 degrees) until the angle falls into a standard range, usually between 0 and 360 degrees. Let's look at the example of \(-370^{\circ}\).
- First, you add 360 degrees to the negative angle: \(-370^{\circ} + 360^{\circ} = -10^{\circ}\)This doesn't yet give a positive angle, so we add 360 degrees again:
- \(-10^{\circ} + 360^{\circ} = 350^{\circ}\) With these calculations, we've transformed a negative angle of \(-370^{\circ}\) into a positive angle of \(350^{\circ}\).
Quadrants in Trigonometry
In trigonometry, the coordinate plane is divided into four quadrants. Understanding these quadrants helps in determining the sine, cosine, and other trigonometric function values of angles:
- **Quadrant I:** All trigonometric functions are positive here, consisting of angles from \(0^{\circ}\) to \(90^{\circ}\).
- **Quadrant II:** Sine is positive, others are negative. This quadrant covers angles from \(90^{\circ}\) to \(180^{\circ}\).
- **Quadrant III:** Tangent is positive, the others are negative, with angles between \(180^{\circ}\) and \(270^{\circ}\).
- **Quadrant IV:** Cosine is positive, others are negative. Angles here range from \(270^{\circ}\) to \(360^{\circ}\).
Angle Sketching
Sketching an angle involves placing its terminal side in the correct quadrant on a coordinate plane. The terminal side is determined by the angle's standard position, which initially has its vertex at the origin and its initial side along the positive x-axis. From there, the angle opens up according to its magnitude:- For \(350^{\circ}\), we imagine starting from the positive x-axis and rotating clockwise to the right into Quadrant IV.- The angle just falls short of a full circle by \(10^{\circ}\), as it is \(10^{\circ}\) shy of \(360^{\circ}\).By sketching this angle, it becomes easier to identify the reference angle. A reference angle is always measured between the terminal side and the x-axis, ensuring it's the smallest angle possible.In this sketch, the reference angle for \(350^{\circ}\) is calculated as:\[ \Theta' = 360^{\circ} - 350^{\circ} = 10^{\circ}\] making it evident that the reference angle fits neatly against the x-axis in Quadrant IV.Visualizing via sketches helps deepen understanding of angles and their placements on the plane.
Other exercises in this chapter
Problem 18
\(\cot \theta=\frac{16}{11}\)
View solution Problem 18
Simplify the expression. \(\cos \left(x-\frac{\pi}{2}\right)\)
View solution Problem 18
\(g(x)=2 \csc x\)
View solution Problem 19
Identify the amplitude and period of the function. Then graph the function and describe the graph of \(g\) as a transformation of the graph of its parent functi
View solution