Problem 18
Question
Simplify. $$ \left(x^{3}-27\right) \div(x-3) $$
Step-by-Step Solution
Verified Answer
\(x^2 + 3x + 9\)
1Step 1: Recognize the Polynomial Identity
Notice that the expression \(x^3 - 27\) is a difference of cubes. Recall the formula for factoring a difference of cubes: \(a^3 - b^3 = (a-b)(a^2 + ab + b^2)\). In this case, \(a = x\) and \(b = 3\).
2Step 2: Apply the Difference of Cubes Formula
Using the identity from Step 1, factor \(x^3 - 27\) into \((x-3)(x^2 + 3x + 9)\). Thus, the expression becomes \((x-3)(x^2 + 3x + 9) \div (x-3)\).
3Step 3: Simplify the Expression
Since \((x-3)\) is a common factor in both the numerator and the divisor, you can cancel it out. You're left with the simplified expression \(x^2 + 3x + 9\).
4Step 4: Verify the Result
Finally, verify the result by substituting a sample value for \(x\) in both the original and simplified expressions to ensure they yield the same value. This confirms the simplification is correct.
Key Concepts
Difference of CubesFactoring PolynomialsSimplifying Expressions
Difference of Cubes
In algebra, a "difference of cubes" refers to an expression where two cubed terms are subtracted. The general formula for factoring a difference of cubes is given by \(a^3 - b^3 = (a-b)(a^2 + ab + b^2)\). This formula is a powerful tool for simplifying such expressions.Consider the expression \(x^3 - 27\). This is a classic example of a difference of cubes, where \(a = x\) and \(b = 3\) (since \(27 = 3^3\)). Applying the difference of cubes formula helps us rewrite the expression as \((x-3)(x^2 + 3x + 9)\).
- Quick Tip: Identifying the terms \(a\) and \(b\) is crucial for applying the formula correctly.
- Remember: The middle term \(ab\) in \((a^2 + ab + b^2)\) often helps consolidate understanding.
Factoring Polynomials
Factoring polynomials involves breaking down a polynomial into simpler, multiplicative expressions known as factors. These factors, when multiplied together, yield the original polynomial.In the context of our example, we factored \(x^3 - 27\) into \((x-3)(x^2 + 3x + 9)\). The first factor, \(x-3\), corresponds to one of the simple roots of the polynomial, while the trinomial \(x^2 + 3x + 9\) completes the factorization.
- Helpful Hint: Always look for common identities like difference or sum of cubes to make factoring easier.
- Goal: Factoring simplifies the polynomial, making it easier to divide or solve.
Simplifying Expressions
Simplifying an expression means reducing it to its simplest form. This often involves canceling common factors, combining like terms, or employing algebraic identities.In our example, after factoring \(x^3 - 27\), the expression becomes \((x-3)(x^2 + 3x + 9) \div (x-3)\). With \(x-3\) appearing in both the numerator and the divisor, it can be cancelled out. This leaves us with the simplified form \(x^2 + 3x + 9\).
- Important Note: Cancel only common factors present across the entire numerator or denominator.
- Verification: Checking your final expression with sample values ensures the simplification is legitimate.
Other exercises in this chapter
Problem 18
Find \(p(4)\) and \(p(-2)\) for each function. \(p(x)=2-x\)
View solution Problem 18
Determine whether each expression is a polynomial. If it is a polynomial, state the degree of the polynomial. $$ \sqrt{m-5} $$
View solution Problem 18
Simplify. Assume that no variable equals 0. $$ \frac{3 a^{5} b^{3} c^{3}}{9 a^{3} b^{7} c} $$
View solution Problem 19
Given a polynomial and one of its factors, find the remaining factors of the polynomial. Some factors may not be binomials. $$ x^{3}-x^{2}-10 x-8 ; x+1 $$
View solution