Problem 18
Question
March each function defined in Column I with the appropriate description in Column \(\mathrm{II.}\) Do not use a calculator. I $$y=2 \sin (3 x-4)$$ II A. Amplitude \(=2 ;\) period \(=\frac{\pi}{2} ;\) phase shift \(=\frac{3}{4}\) B. Amplitude \(=3 ;\) period \(=\pi ;\) phase shift \(=2\) C. Amplitude \(=4 ;\) period \(=\frac{2 \pi}{3} ;\) phase shift \(=\frac{2}{3}\) D. Amplitude \(=2 ;\) period \(=\frac{2 \pi}{3} ;\) phase shift \(=\frac{4}{3}\)
Step-by-Step Solution
Verified Answer
Match with D: Amplitude = 2; Period = \(\frac{2\pi}{3}\); Phase Shift = \(\frac{4}{3}\).
1Step 1: Identify Components of the Function
The function is given by \( y = 2 \sin (3x - 4) \). The general form for a sine function is \( y = A \sin(Bx - C) \), where \( A \) is the amplitude, the period is calculated as \( \frac{2\pi}{B} \), and the phase shift is obtained by \( \frac{C}{B} \).
2Step 2: Calculate Amplitude
The amplitude \( A \) is the coefficient in front of the sine function. For the function \( y = 2 \sin (3x - 4) \), \( A = 2 \). This means the amplitude is 2.
3Step 3: Calculate Period
The period of a sine function \( y = A \sin(Bx - C) \) is given by \( \frac{2\pi}{B} \). Here, \( B = 3 \), so the period is \( \frac{2\pi}{3} \).
4Step 4: Calculate Phase Shift
The phase shift of the sine function is given by \( \frac{C}{B} \). For the function \( y = 2 \sin(3x - 4) \), \( C = 4 \) and \( B = 3 \). Therefore, the phase shift is \( \frac{4}{3} \).
5Step 5: Match with Column II
From the calculations: Amplitude \( = 2 \), Period \( = \frac{2\pi}{3} \), Phase Shift \( = \frac{4}{3} \). This matches description D from Column II.
Key Concepts
AmplitudePeriod of Sine FunctionsPhase Shift
Amplitude
In the realm of trigonometric functions, the amplitude of the sine function is a crucial concept. Amplitude refers to the height from the centerline of the wave to its peak. When we talk about the function \( y = A \sin(Bx - C) \), the amplitude is represented by \( A \). This value determines how tall or short the wave is. For instance, in the function \( y = 2 \sin(3x - 4) \), the amplitude is \( 2 \).
- The amplitude is always a positive number, even if it's expressed as a negative in the equation, since it measures a "distance."
- An amplitude of \( 2 \) means the wave oscillates 2 units above and below the central axis.
Period of Sine Functions
The period of a sine function is the length of one complete cycle of the wave, or the distance after which the pattern repeats. It is a key factor in determining how "stretched" out the wave appears horizontally. For the sine function \( y = A \sin(Bx - C) \), the period is calculated as \( \frac{2\pi}{B} \).In the function \( y = 2 \sin(3x - 4) \), \( B \) is \( 3 \). Thus, the period is \( \frac{2\pi}{3} \). This means that every \( \frac{2\pi}{3} \) units, the wave begins to repeat its shape.
- The period tells us how quickly a sine curve returns to its starting point.
- An important property of the period is that it can never be zero, as a wave must be continuous.
Phase Shift
Phase shift refers to the horizontal movement of the graph of a sine function along the x-axis. It's essentially a slide to the left or right. In our sine function model \( y = A \sin(Bx - C) \), the phase shift is determined by \( \frac{C}{B} \). It's the value of \( C \) divided by \( B \).For the function \( y = 2 \sin(3x - 4) \), the phase shift is \( \frac{4}{3} \). This value tells us that the sine wave is shifted \( \frac{4}{3} \) units to the right along the x-axis.
- A positive phase shift indicates a shift to the right, while a negative phase shift results in a move to the left.
- This horizontal movement is crucial, especially when comparing or synchronizing waves.
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