Problem 18
Question
$$\left[4 \sqrt{2}\left(\cos \frac{\pi}{4}+i \sin \frac{\pi}{4}\right)\right]\left[\sqrt{2}\left(\cos \frac{3 \pi}{4}+i \sin \frac{3 \pi}{4}\right)\right]=8\left[\cos \left(\frac{\pi}{4}+\frac{3 \pi}{4}\right)+i \sin \left(\frac{\pi}{4}+\frac{3 \pi}{4}\right)\right]=-8$$
Step-by-Step Solution
Verified Answer
-8
1Step 1: Understand the Given Expression
We have the expression \( \left[4 \sqrt{2}(\cos \frac{\pi}{4} + i \sin \frac{\pi}{4})\right]\left[\sqrt{2}(\cos \frac{3\pi}{4} + i \sin \frac{3\pi}{4})\right] \) which is in polar form for complex numbers, taking advantage of Euler's formula \( e^{i\theta} = \cos \theta + i\sin \theta \).
2Step 2: Multiply Moduli
In polar form, multiplying two complex numbers involves multiplying their moduli: \( 4\sqrt{2} \times \sqrt{2} = 4 \times 2 = 8 \).
3Step 3: Add Angles
For the angle part, we add the angles of the two complex numbers: \( \frac{\pi}{4} + \frac{3\pi}{4} = \pi \).
4Step 4: Reconstruct the Product
Now, reconstruct the product as \( 8 \left( \cos \pi + i \sin \pi \right) \). Known trigonometric values are \( \cos \pi = -1 \) and \( \sin \pi = 0 \).
5Step 5: Simplify the Expression
Substitute the trigonometric values: \( 8 \times \left( -1 + 0i \right) = -8 \).
6Step 6: Conclude the Solution
The final result of the given expression is \(-8\), as the operations confirm this value as stated in the problem.
Key Concepts
Euler's formulaPolar FormTrigonometric ValuesMultiplication of Complex Numbers
Euler's formula
Euler's formula is a cornerstone in understanding complex numbers and their behavior. It establishes a profound connection between trigonometry and complex exponential functions. This formula states that for any real number \( \theta \), the equation \( e^{i\theta} = \cos \theta + i \sin \theta \) holds true. Here's what each part means:
- \( e^{i\theta} \) can be understood as a rotation in the complex plane by an angle \( \theta \).
- \( \cos \theta \) and \( \sin \theta \) represent the projections onto the real and imaginary axes of a circle of radius 1.
- The imaginary unit \( i \) signifies a 90-degree rotation, so \( i \sin \theta \) adds the imaginary component.
Polar Form
The polar form of a complex number provides an alternative way to express it, focusing on its magnitude and direction. Given a complex number \( z \), it can be written as \( r ( \cos \theta + i \sin \theta ) \) or alternatively as \( r e^{i\theta} \), thanks to Euler's formula. Here's how to understand it:
- \( r \) is the modulus of the complex number, indicating its distance from the origin in the complex plane.
- \( \theta \) is the argument or angle, showing the direction of the line connecting the origin to the point in the plane.
Trigonometric Values
Understanding trigonometric values is crucial when working with complex numbers in both Cartesian and polar forms. Key angles like \( \frac{\pi}{4} \) and \( \pi \) appear often due to their simplicity and their significant roles in geometry. To break it down:
- \( \frac{\pi}{4} \) corresponds to a 45-degree angle, where \( \cos \frac{\pi}{4} = \sin \frac{\pi}{4} = \frac{\sqrt{2}}{2} \). These values are equal because the angle lies along the angle bisector in the unit circle's first quadrant.
- \( \pi \) or 180 degrees represents a point directly on the negative real axis, leading to \( \cos \pi = -1 \) and \( \sin \pi = 0 \). This tells us that the associated vector is pointing in the negative x-direction.
Multiplication of Complex Numbers
Multiplying complex numbers becomes much simpler when they are in polar form. Here's a step-by-step on how it works:
- First, multiply their moduli (the magnitudes of the vectors representing the complex numbers). For example, if \( |z_1| = a \) and \( |z_2| = b \), then the modulus of the product is \( a \times b \).
- Next, add their angles (arguments). If \( z_1 \) has an angle \( \alpha \) and \( z_2 \) has an angle \( \beta \), the resulting angle is \( \alpha + \beta \).
- The product is then given by \( (a \cdot b)( \cos(\alpha + \beta) + i \sin(\alpha + \beta) ) \).
Other exercises in this chapter
Problem 17
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