Problem 18
Question
In \(\triangle A B C, \angle C\) is a right angle. Find the remaining sides and angles. Round your answers to the nearest tenth. \(b=5, c=10\)
Step-by-Step Solution
Verified Answer
The remaining side a of the triangle is approximately 8.7 units, angle A is 30 degrees, and angle B is 60 degrees.
1Step 1: Find side a
First, find the remaining side using the Pythagorean theorem, \(a^2 + b^2 = c^2\). Given \(b = 5\) and \(c = 10\), we get \(a^2 + 5^2 = 10^2\), or \(a^2 = 75\). Taking the square root of both sides, \(a = \sqrt{75} \approx 8.7\), rounding to the nearest tenth.
2Step 2: Find angle A
Use the sine function to find angle A. The sine of an angle in a right triangle is defined as the length of the side opposite the angle divided by the length of the hypotenuse. Therefore, \(\sin(A) = \frac{b}{c} = \frac{5}{10} = 0.5\). Use the inverse sine function to find the measure of angle A. \(\sin^{-1}(0.5) = 30^\circ\)
3Step 3: Find angle B
The third angle of a triangle is found by subtracting the other two angles from 180 degrees. So, \(\angle B = 180^\circ - 90^\circ - 30^\circ = 60^\circ\)
4Step 4: Summary
All the sides and angles of the triangle are now known. Side a is approximately 8.7 units, \(\angle A\) is \(30^\circ\), and \(\angle B\) is \(60^\circ\).
Key Concepts
Pythagorean TheoremInverse Trigonometric FunctionsAngle Sum of a Triangle
Pythagorean Theorem
A right triangle has one angle at 90 degrees, which makes it unique in many ways. One of the key properties of right triangles is that they adhere to the Pythagorean Theorem. This theorem is essential for finding the lengths of sides in right triangles. It states that in a right triangle, the square of the length of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the lengths of the other two sides. The formula is written as:\[ a^2 + b^2 = c^2 \]where \(c\) is the hypotenuse, and \(a\) and \(b\) are the other two sides. In our example with \(b = 5\) and \(c = 10\), you can plug these values into the equation to find \(a\).
- Calculate \(b^2 = 25\).
- Substitute \(b^2\) and \(c^2 = 100\) into the equation: \(a^2 + 25 = 100\).
- Solve for \(a^2\): \(a^2 = 75\).
- Take the square root of both sides: \(a = \sqrt{75} \approx 8.7\).
Inverse Trigonometric Functions
Inverse trigonometric functions are used to find angles when one of the trigonometric ratios like sine, cosine, or tangent is known. They are the reverse operations of these trigonometric functions, allowing us to calculate an angle from a ratio.In this exercise, we used the inverse sine function, which is written as \( \sin^{-1} \) or arc\(\sin\). It takes a ratio as its input and gives the angle whose sine is that ratio. This is particularly useful in right triangles when you have the opposite side and the hypotenuse.Given that \( \sin(A) = \frac{5}{10} = 0.5 \), the inverse sine function helps us find \( \angle A \). By calculating \( \sin^{-1}(0.5) \), you achieve the angle for \(\angle A\) which is:
- \( \sin^{-1}(0.5) = 30^\circ \)
Angle Sum of a Triangle
The sum of all angles in any triangle is always 180 degrees. This is a fundamental rule in geometry that applies to all triangles, including right triangles. Knowing this, you can find unknown angles if you have at least two angle measures.For a right triangle, one angle is always 90 degrees. Using this knowledge simplifies finding the other angles. In the example given, we already know \( \angle C = 90^\circ \) and \(\angle A = 30^\circ \). To find \(\angle B\), use the angle sum property:
- Add the known angles: \(90^\circ + 30^\circ = 120^\circ\)
- Subtract this sum from 180 degrees: \(180^\circ - 120^\circ = 60^\circ\)
Other exercises in this chapter
Problem 18
Solve each equation for \(0 \leq \theta
View solution Problem 18
Mental Math Find the value of each trigonometric expression. $$ \sin 80^{\circ} \cos 35^{\circ}-\cos 80^{\circ} \sin 35^{\circ} $$
View solution Problem 18
Simplify each trigonometric expression. $$ \sin \theta \sec \theta \cot \theta $$
View solution Problem 19
Given \(\cos \theta=-\frac{4}{5}\) and \(90^{\circ}
View solution