Problem 18
Question
In Exercises 5–24, analyze and sketch a graph of the function. Label any intercepts, relative extrema, points of inflection, and asymptotes. Use a graphing utility to verify your results. $$ y=(x+1)^{2}-3(x+1)^{2 / 3} $$
Step-by-Step Solution
Verified Answer
The analysis and sketching of the function involve finding its intercepts, extrema, inflection points and checking for asymptotes. The intercepts are computed by equating y to zero, extrema are found utilizing first derivative and second derivative for inflection points. Verification of results will be done with a graphical representation.
1Step 1: Finding the Intercepts
To find the intercepts, first set \(y = 0\) and solve for \(x\). So, \(0 = (x+1)^{2} - 3(x+1)^{2/3}\). The roots from this equation represents the x-intercepts of the function.
2Step 2: Finding the Extrema
By differentiation, the relative extrema can be found. Extrema occur where the derivative either equals zero or is undefined. The first derivative of the function is: \(y' = 2(x+1) - 2(x+1)^{-1/3}\). Set \(y' = 0\), and find the solutions for \(x\), these represent locations of potential relative extrema.
3Step 3: Finding Points of Inflection
Inflection points can be found by utilizing the second derivative test. These are the points where concavity changes. The second derivative of the function is: \(y'' = 2 + 2/3(x+1)^{-4/3}\). Set \(y'' = 0\) and find the solutions for \(x\), these points are potential points of inflection.
4Step 4: Verification with Graphing Utility
By using a graphing utility, verify all the calculations done in previous steps. This will allow visual confirmation of the intercepts, relative extrema and points of inflection previously obtained. Check if there are any asymptotes present in the graph.
Key Concepts
InterceptsRelative ExtremaPoints of InflectionAsymptotes
Intercepts
Intercepts are the points where the graph crosses the axes. To find the x-intercepts, we set the function equal to zero, and solve for x. In other words, we solve the equation \(0 = (x+1)^{2} - 3(x+1)^{2/3}\). These x-values, where the function equals zero, are where the graph touches or crosses the x-axis. If we also want the y-intercept, which is the point where the graph crosses the y-axis, we substitute \(x = 0\) into the function and solve for y. This will give us a point in the form of (0, y).
A quick recap of the steps:
A quick recap of the steps:
- For x-intercepts, solve \((x+1)^{2} - 3(x+1)^{2/3} = 0\).
- For the y-intercept, calculate \(y\) when \(x = 0\).
Relative Extrema
Relative extrema are points where the function reaches a local maximum or minimum, meaning the graph changes direction at these points. To find them, you'll need to calculate the first derivative of the function. Once you have the derivative, you'll set it equal to zero or look for where it is undefined. Solving these conditions will give you the x-values of potential extrema.
For our function:
For our function:
- The first derivative is \(y' = 2(x+1) - 2(x+1)^{-1/3}\).
- Set \(y' = 0\) and solve for x to find potential points of relative extrema.
Points of Inflection
Points of inflection are critical in understanding the nature of a graph as they are where the concavity changes. A change in concavity means the graph switches from being 'smiley' to 'frowny' or vice versa. To find these points, calculate the second derivative of the function, and solve \(y'' = 0\).
For the given function, the second derivative is
For the given function, the second derivative is
- \(y'' = 2 + \frac{2}{3}(x+1)^{-4/3}\).
- Set \(y'' = 0\) and solve for \(x\) to find the x-values of potential inflection points.
Asymptotes
Asymptotes are lines that a graph approaches but never truly meets. They are more common in certain types of functions, such as rational functions, but it's useful to check for both vertical and horizontal asymptotes in most graphs.
While our specific function does not inherently result in vertical asymptotes due to its polynomial nature, it's still a good practice to inspect potential horizontal asymptotes. Using limits as \(x\) approaches infinity or negative infinity, we can discern whether the function flattens out in any direction.
Here’s how you break it down:
While our specific function does not inherently result in vertical asymptotes due to its polynomial nature, it's still a good practice to inspect potential horizontal asymptotes. Using limits as \(x\) approaches infinity or negative infinity, we can discern whether the function flattens out in any direction.
Here’s how you break it down:
- Check for vertical asymptotes by finding values of \(x\) that make the function undefined.
- Inspect horizontal asymptotes by evaluating the limits of the function as \(x\) goes to infinity or negative infinity.
Other exercises in this chapter
Problem 18
Finding Limits at Infinity In Exercises \(15-18\) , find each limit, if possible. $$ \begin{array}{l}{\text { (a) } \lim _{x \rightarrow \infty} \frac{5 x^{3 /
View solution Problem 18
Apply Newton's Method to approximate the \(x\) -value(s) of the indicated point(s) of intersection of the two graphs. Continue the process until two successive
View solution Problem 18
Finding Points of Inflection In Exercises \(15-30\) , find the points of inflection and discuss the concavity of the graph of the function. $$ f(x)=4-x-3 x^{4}
View solution Problem 18
Finding Extrema on a Closed Interval In Exercises \(17-36\) , find the absolute extrema of the function on the closed interval. $$ f(x)=\frac{3}{4} x+2,[0,4] $$
View solution