Problem 18
Question
In Exercises 5-20, find the determinant of the matrix. \(\left[ \begin{array}{r} 0 && 6 \\ -3 && 2 \end{array} \right]\)
Step-by-Step Solution
Verified Answer
The determinant of the matrix is 18.
1Step 1: Identify the elements in the diagonal and auxiliary diagonal
In our matrix, the elements in the main diagonal are 0 and 2. The elements in the auxiliary diagonal are 6 and -3.
2Step 2: Apply the determinant formula
We multiply the elements in the main diagonal and do the same for the auxiliary diagonal. Then we subtract the second result from the first one. This gives us: \( (0*2) - (6*-3) \)
3Step 3: Solve the calculation
After performing the multiplication and subtraction, we get:\( (0) - (-18) = 18 \)
Key Concepts
2x2 MatrixMain DiagonalAuxiliary DiagonalDeterminant Calculation
2x2 Matrix
A 2x2 matrix is a simple rectangular array with two rows and two columns. It is one of the most basic structures in linear algebra. You can think of each element as occupying a cell within this 2x2 grid. For any 2x2 matrix:\[\begin{pmatrix}a && b \c && d \end{pmatrix}\]Each letter represents a number or variable placed in a specific position.
- Here, "a" and "b" form the first row.
- "c" and "d" form the second row.
Main Diagonal
The main diagonal of a matrix encompasses the elements stretching from the top-left to the bottom-right. For a 2x2 matrix, it includes just two elements. Consider the matrix:\[\begin{pmatrix}0 && 6 \-3 && 2 \end{pmatrix}\]In this specific case, the main diagonal elements are 0 and 2.
- These elements are crucial for several matrix operations.
- They affect how we calculate the determinant of the matrix.
Auxiliary Diagonal
The auxiliary diagonal in a matrix runs opposite to the main diagonal, from the top-right to the bottom-left. In our matrix:\[\begin{pmatrix}0 && 6 \-3 && 2 \end{pmatrix}\]The auxiliary diagonal consists of the elements 6 and -3.
- It's essential for determining the cross-product you need for calculating the determinant.
- Understanding this helps complete the second half of the determinant formula.
Determinant Calculation
Calculating the determinant of a 2x2 matrix is straightforward once you identify the elements in both the main and auxiliary diagonals. The formula for the determinant of a 2x2 matrix is given by:\[ ext{Det} = (a \cdot d) - (b \cdot c)\]Applying this to our matrix, where "a" is 0, "b" is 6, "c" is -3, and "d" is 2, we perform the calculation:\[(0 \cdot 2) - (6 \cdot -3) = 0 - (-18) = 18\]
- The multiplication of the main diagonal elements gives 0.
- The multiplication of the auxiliary diagonal elements gives -18.
- The subtraction of these results in a determinant of 18.
Other exercises in this chapter
Problem 17
In Exercises 15-20, write the augmented matrix for the system of linear equations. \( \left\\{ \begin{array}{l} x + 10y - 2z = 2 \\ 5x - 3y + 4z = 0 \\ 2x + y =
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In Exercises 17-20, use a graphing utility and Cramer's Ruleto solve (if possible) the system of equations. \(\begin{cases} x + 2y - z = -7 \\ 2x - 2y - 2z = -8
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In Exercises 13-24, find the inverse of the matrix (if it exists). \(\left[ \begin{array}{r} 4 & -1 \\ -3 & 1 \end{array} \right]\)
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In Exercises 15-20, write the augmented matrix for the system of linear equations. \( \left\\{ \begin{array}{l} -x - 8y - 5z = 8 \\ -7x - 15z = -38 \\ 3x - y +
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