Problem 18
Question
In \(15-26,\) find and graph the solution set of each inequality. $$ |2-4 b| \leq 6 $$
Step-by-Step Solution
Verified Answer
The solution set is \(-1 \leq b \leq 2\).
1Step 1: Identify the Absolute Value Inequality
The absolute value inequality given is \(|2 - 4b| \leq 6\). The goal is to find the values of \(b\) (the solution set) that satisfy this inequality.
2Step 2: Formulate Two Inequalities
For the absolute value \(|x| \leq a\), it translates to \(-a \leq x \leq a\). Apply this to the expression:\[-6 \leq 2 - 4b \leq 6\].
3Step 3: Solve the Left Inequality
Start by solving the inequality \(-6 \leq 2 - 4b\):1. Subtract 2 from both sides to get \(-8 \leq -4b\).2. Divide each side by \(-4\) (remember to flip the inequality sign when dividing by a negative) to get \(2 \geq b\).
4Step 4: Solve the Right Inequality
Now solve the inequality \(2 - 4b \leq 6\):1. Subtract 2 from both sides to obtain \(-4b \leq 4\).2. Divide each side by \(-4\) (flip the inequality sign again) to get \(b \geq -1\).
5Step 5: Combine the Inequalities
The combined inequalities from the previous steps are:\[-1 \leq b \leq 2\].This represents the solution set for \(b\).
6Step 6: Graph the Solution Set
Graph the inequality on a number line:- Draw a number line with points at \(-1\) and \(2\).- Use closed circles at \(-1\) and \(2\) because these points are included in the solution (they satisfy the \(\leq\) inequality).- Shade the region between \(-1\) and \(2\) to represent all values of \(b\) that satisfy the inequality.
Key Concepts
Understanding Inequality SolutionsGraphing InequalitiesNumber Line Representation of Inequalities
Understanding Inequality Solutions
Absolute value inequalities, like \(|2 - 4b| \leq 6\), are solved by breaking them into two separate inequalities. This involves understanding that the expression inside the absolute value can be both positive and negative, so we must consider both cases.
To solve \(|2 - 4b| \leq 6\), you set up two inequalities:
To solve \(|2 - 4b| \leq 6\), you set up two inequalities:
- -6 ≤ 2 - 4b
- 2 - 4b ≤ 6
Graphing Inequalities
Once you have found the solution set, graphing these solutions helps visualize the range of values \(b\) can take. Graphing inequalities on a number line is straightforward. Here’s how you can accomplish that:
Next, you need to represent all the potential values \(b\) could take, which is shaded in the interval between these marked points.
- Begin by drawing a horizontal line as your number line.
- Mark distinct points on the number line for each boundary, \(-1\) and \(2\), corresponding to the solution set \(-1 \leq b \leq 2\).
- Choose closed circles, also known as solid dots, since the inequality includes equal to (\( \leq \)).
Next, you need to represent all the potential values \(b\) could take, which is shaded in the interval between these marked points.
Number Line Representation of Inequalities
The number line representation of inequalities provides a visual cue that helps in understanding and interpreting solutions.
To represent the solution \(-1 \leq b \leq 2\) on a number line:
If you imagine walking from point \(-1\) to point \(2\), all your possible steps cover every valid solution in the inequality's context. This visualization often makes inequalities more intuitive and easier to grasp.
To represent the solution \(-1 \leq b \leq 2\) on a number line:
- Draw the number line and slightly exaggerate distances for clarity.
- Mark and label the key points \(-1\) and \(2\).
- Use closed circles on \(-1\) and \(2\) because these values are included in your solution set.
- Shade the segment of the number line that lies between \(-1\) and \(2\) to indicate all possible values for \(b\).
If you imagine walking from point \(-1\) to point \(2\), all your possible steps cover every valid solution in the inequality's context. This visualization often makes inequalities more intuitive and easier to grasp.
Other exercises in this chapter
Problem 18
In \(3-29\) write each quotient in simplest form. Variables in the radicand with an even index are non-negative. Variables occurring in the denominator of a fra
View solution Problem 18
In \(3-38\) , write each radical in simplest radical form. Variables in the radicand of an even index are non-negative. Variables occurring in the denominator o
View solution Problem 19
In \(3-41\) , express each product in simplest form. Variables in the radicand with an even index are non-negative. $$ 7 \sqrt{a} \cdot 5 \sqrt{\frac{a}{9}} $$
View solution Problem 19
In \(3-38,\) solve each equation for the variable, check, and write the solution set. $$ x=\sqrt{4 x+5} $$
View solution