Problem 18
Question
If two events \(A\) and \(B\) are such that \(P\left(A^{2}\right)=0.3, P(B)\) \(=0.4\) and \(P\left(A B^{\circ}\right)=0.5\), then \(P\left[B \backslash\left(A \cup B^{c}\right)\right]=\) (A) \(\frac{1}{2}\) (B) \(\frac{1}{3}\) (C) \(\frac{1}{4}\) (D) none of these
Step-by-Step Solution
Verified Answer
\( P(B \mid A \cup B') = \frac{1}{4} \). Answer: (C).
1Step 1: Given data
\( P(A') = 0.3 \Rightarrow P(A) = 0.7 \), \( P(B) = 0.4 \), \( P(A \cap B') = 0.5 \). Find \( P(B \mid A \cup B') \).
2Step 2: Find P(A ∩ B)
\( P(A \cap B) = P(A) - P(A \cap B') = 0.7 - 0.5 = 0.2 \).
3Step 3: Find P(A ∪ B')
\( P(A \cup B') = P(A) + P(B') - P(A \cap B') = 0.7 + 0.6 - 0.5 = 0.8 \).
4Step 4: Simplify B ∩ (A ∪ B')
\( B \cap (A \cup B') = (B \cap A) \cup (B \cap B') = A \cap B \). So \( P = 0.2 \).
5Step 5: Answer
\( P(B \mid A \cup B') = 0.2/0.8 = 1/4 \). Answer: (C) \( \frac{1}{4} \).
Key Concepts
Set theoryConditional probabilityJoint probabilitySet operations
Set theory
Set theory is a mathematical framework for understanding collections of objects or elements typically called "sets." A set can be visualized like a container that holds multiple objects, things, or numbers. In probability theory, sets represent events or outcomes from an experiment.
For example, in our exercise, events denoted by sets like \(A\) and \(B\). Sets can undergo various operations, like intersections, unions, and complements. These operations help us understand complex probabilistic interactions. Understanding set theory is fundamental to analyzing probabilities, as it shows how different events relate to each other.
For example, in our exercise, events denoted by sets like \(A\) and \(B\). Sets can undergo various operations, like intersections, unions, and complements. These operations help us understand complex probabilistic interactions. Understanding set theory is fundamental to analyzing probabilities, as it shows how different events relate to each other.
- An intersection (\(A \cap B\)) involves elements common to both sets \(A\) and \(B\).
- A union (\(A \cup B\)) contains all elements from either \(A\) or \(B\) or both.
- The complement (\(B^c\)) comprises elements not in \(B\).
- The set difference (\(B \backslash A\)) includes elements in \(B\) but not in \(A\).
Conditional probability
Conditional probability is a measure that calculates the probability of one event occurring, given that another event has already occurred. This concept captures how the occurrence of one event alters the likelihood of another.
In mathematical terms, the conditional probability of event \(A\) given event \(B\) is represented as \(P(A|B)\). It is calculated using the formula: \[P(A|B) = \frac{P(A \cap B)}{P(B)}\] This expresses the likelihood of \(A\) happening, assuming \(B\) happens as well.
Conditional probability helps understand dependent events, where one outcome affects the other.
For example, if you have information that someone is walking with an umbrella, the probability that it is raining might be higher. Understanding this concept is crucial for comprehensively solving problems in probability theory where event dependencies need to be considered.
In mathematical terms, the conditional probability of event \(A\) given event \(B\) is represented as \(P(A|B)\). It is calculated using the formula: \[P(A|B) = \frac{P(A \cap B)}{P(B)}\] This expresses the likelihood of \(A\) happening, assuming \(B\) happens as well.
Conditional probability helps understand dependent events, where one outcome affects the other.
For example, if you have information that someone is walking with an umbrella, the probability that it is raining might be higher. Understanding this concept is crucial for comprehensively solving problems in probability theory where event dependencies need to be considered.
Joint probability
Joint probability considers the probability of two or more events occurring simultaneously. It's vital in problems where the likelihood of multiple outcomes happening at the same time is analyzed.
For instance, joint probability calculates the chance of drawing a card from a deck that is both red and a queen, capturing the intersection of both conditions.
In mathematical notation, joint probability of events \(A\) and \(B\) is written as \(P(A \cap B)\).
This probability measures the concurrence of two occurring events.
For instance, joint probability calculates the chance of drawing a card from a deck that is both red and a queen, capturing the intersection of both conditions.
In mathematical notation, joint probability of events \(A\) and \(B\) is written as \(P(A \cap B)\).
This probability measures the concurrence of two occurring events.
- Independence: If \(A\) and \(B\) are independent, \(P(A \cap B) = P(A) \cdot P(B)\).
- Dependence: Joint probability requires knowing how the occurrence of one event affects another if they are not independent.
Set operations
Set operations are crucial tools in the analysis of probability problems, as they allow manipulation and combination of different sets to examine complex relationships.
In probability theory, sets often represent different events, and operations on these sets help evaluate probabilities involving relationships like intersection, union, complement, and difference.
The most common operations include:
Mastering set operations allows for nuanced solutions to probability problems, offering a clearer picture of how individual events relate within a broader system.
In probability theory, sets often represent different events, and operations on these sets help evaluate probabilities involving relationships like intersection, union, complement, and difference.
The most common operations include:
- Intersection (\(\cap\)) - Represents outcomes present in both sets.
- Union (\(\cup\)) - Includes all outcomes present in either of the sets.
- Complement (\(^c\)) - Contains outcomes not present in the set.
- Set difference (\(\backslash\)) - Consists of outcomes in one set but not in the other.
Mastering set operations allows for nuanced solutions to probability problems, offering a clearer picture of how individual events relate within a broader system.
Other exercises in this chapter
Problem 16
Sixteen players \(S_{1}, S_{2}, \ldots S_{16}\) play in a tournament. They are divided into eight pairs at random. From each pair a winner is decided on the bas
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An unbiased coin is tossed. If the result is a head, a pair of unbiased dice is rolled and the number obtained by adding the numbers on the two faces is noted.
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An unbiased die with faces marked \(1,2,3,4,5\) and 6 is rolled four times. Out of four face values obtained, the probabiity that the minimum face value is not
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