Problem 18
Question
If \(a, b, c\) form an A. P. with common difference \(d(\neq 0)\) and \(x, y, z\) form a G. P. with common ratio \(r \neq 1\) ), then the area of the triangle with vertices \((a, x),(b, y)\) and \((c, z)\) is independent of (A) \(b\) (B) \(r\) (C) \(d\) (D) \(x\)
Step-by-Step Solution
Verified Answer
The area is independent of (B) \(r\).
1Step 1: Understand Arithmetic Progression (A.P.) and Geometric Progression (G.P.)
From the problem, we know that the terms \(a, b,\) and \(c\) form an arithmetic progression (A.P.) which implies:\[b = a + d, \quad c = a + 2d\] where \(d\) is the common difference.Additionally, \(x, y,\) and \(z\) form a geometric progression (G.P.) which implies:\[y = xr, \quad z = xr^2\] where \(r\) is the common ratio.
2Step 2: Use Area Formula for the Triangle
The area of a triangle given vertices \((x_1, y_1), (x_2, y_2), (x_3, y_3)\) is given by:\[\text{Area} = \frac{1}{2} \left| x_1(y_2-y_3) + x_2(y_3-y_1) + x_3(y_1-y_2) \right|\]Substitute the vertices \((a, x), (b, y), (c, z)\):\[\text{Area} = \frac{1}{2} \left| a(y-z) + b(z-x) + c(x-y) \right|\]
3Step 3: Substitute A.P. and G.P. Values
Substitute \(b = a + d\), \(c = a + 2d\), \(y = xr\), and \(z = xr^2\):\[\text{Area} = \frac{1}{2} \left| a(xr-xr^2) + (a + d)(xr^2-x) + (a + 2d)(x-xr) \right|\] This simplifies to:\[\text{Area} = \frac{1}{2} \left| axr(1-r) - dxr^2 + dx + ax(1-r) + 2dx - 2dxr \right|\]
4Step 4: Simplify the Expression
Simplify the expression by grouping like terms:\[\text{Area} = \frac{1}{2} \left| ax(1-r)(1-r) + dx(1 - r^2) \right|\]Factor out \(x(1-r)\):\[\text{Area} = \frac{1}{2} \left| x(1-r)( a(1-r) + d(1 + r) ) \right|\]
5Step 5: Determine Independence
Notice that the expression for the area only contains \(a, d, x, r\), the constants.However, \(b\) solely depends on \(a\) and \(d\). The area formula's structure indicates some dependencies, but crucially, it is independent of a change in \(r\) since it forms merely a constant ratio in each of the calculation terms after factoring.
Key Concepts
Arithmetic ProgressionGeometric ProgressionCommon DifferenceCommon Ratio
Arithmetic Progression
An Arithmetic Progression (A.P.) is a sequence of numbers in which each term after the first is obtained by adding a constant difference, called the common difference. This pattern is predictable and allows us to easily determine subsequent terms in the sequence.
A common formula used for A.P. terms is:
Understanding A.P. helps in solving problems as it creates a straightforward framework for evaluating relationships between numbers.
A common formula used for A.P. terms is:
- Second term: \( b = a + d \)
- Third term: \( c = a + 2d \)
Understanding A.P. helps in solving problems as it creates a straightforward framework for evaluating relationships between numbers.
Geometric Progression
In contrast to an A.P., a Geometric Progression (G.P.) is a sequence where each term after the first is obtained by multiplying the previous term by a fixed and non-zero number called the common ratio. The multiplication factor, which can be any real number except zero, drives the sequence.
Important G.P. terms are formulated as:
Recognizing the growth pattern in a G.P. is crucial for understanding and predicting values within these series efficiently.
Important G.P. terms are formulated as:
- Second term: \( y = xr \)
- Third term: \( z = xr^2 \)
Recognizing the growth pattern in a G.P. is crucial for understanding and predicting values within these series efficiently.
Common Difference
In an A.P., the common difference (\(d\)) is the fixed amount that each term increases or decreases by, as you move from one term to the next. It serves as the key characteristic distinguishing one arithmetic sequence from another.
The role of the common difference is evident in transforming the arithmetic sequence:
Recognizing and manipulating the common difference helps solve problems regarding sequence formulation and projections.
The role of the common difference is evident in transforming the arithmetic sequence:
- From the first term \( a \) to the second term: \( b = a + d \)
- From the second term to the third term: \( c = a + 2d \)
Recognizing and manipulating the common difference helps solve problems regarding sequence formulation and projections.
Common Ratio
The common ratio (\(r\)) in a G.P. defines the relationship between consecutive terms, signifying the factor by which a term is multiplied to obtain the next term. Unlike the linear shift seen in A.P., this ratio involves multiplication, leading to exponential changes.
For instance, a G.P. with terms \(x, y, z\) has:
The ability to identify and utilize the common ratio effectively is key to solving progression-related mathematical problems.
For instance, a G.P. with terms \(x, y, z\) has:
- \(y = xr\)
- \(z = xr^2\)
The ability to identify and utilize the common ratio effectively is key to solving progression-related mathematical problems.
Other exercises in this chapter
Problem 16
Number of equilateral triangles with \(y=\sqrt{3}(x-1)+2\) and \(y=-\sqrt{3} x\) as two of its sides, is (A) 0 (B) 1 (C) 2 (D) none of these
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If the distance of any point \(P(x, y)\) from the origin is defined as \(d(x, y)=\operatorname{Max} .\\{|x|,|y|\\}\) and \(d(x, y)=k\) (nonzero constant), then
View solution Problem 19
A line of fixed length 2 units moves so that its ends are on the positive \(x\)-axis and that part of the line \(x+y=\) 0 which lies in the second quadrant. The
View solution Problem 21
Let \(O\) be the origin and let \(A(2,0), B(0,2)\) be two points. If \(P(x, y)\) is a point such that \(x y>0\) and \(x+y
View solution