Problem 18
Question
Identify the conic section represented by each equation by writing the equation in standard form. For a parabola, give the vertex. For a circle, give the center and the radius. For an ellipse or a hyperbola, give the center and the foci. Sketch the graph. \(x^{2}+y^{2}+14 y=-13\)
Step-by-Step Solution
Verified Answer
The given equation represents a circle with the center at (0, -7) and a radius of 6.
1Step 1: Rearrange the equation into a standard form
Given the equation \(x^{2}+y^{2}+14 y=-13\), we can rearrange it. The equation can be rewritten as \(x^{2}+(y+7)^{2}=36\) by completing the square on the y terms. Now, this is the standard form equation of a circle, which is \((x-a)^{2}+(y-b)^{2}=r^{2}\).
2Step 2: Identify the conic section and its properties
In the standard form \((x-a)^{2}+(y-b)^{2}=r^{2}\), 'a' and 'b' are the x and y coordinates of the center of the circle and 'r' is the radius. We can see that in our equation \(x^{2}+(y+7)^{2}=36\), the center of the circle is at (0, -7) and the radius is \(\sqrt{36}\), which equals 6.
3Step 3: Sketch the graph
To draw the graph, first mark the center of the circle at (0, -7) on the graph. Then draw a circle with a radius of 6 units. The circle will touch the y-axis at points (0, -1) and (0, -13).
Key Concepts
Standard Form EquationCircle PropertiesCompleting the Square
Standard Form Equation
The standard form equation of a conic section is essential in identifying the particular type of conic and its key properties. For circles, the standard form is written as: \[(x-a)^{2} + (y-b)^{2} = r^{2}\] where
- \(a\) and \(b\) are the x and y coordinates of the circle's center
- \(r\) is the radius of the circle
Circle Properties
Circles have unique characteristics that differentiate them from other conic sections. Understanding these properties can help you recognize and work with circles more effectively. Key properties include:
- **Center**: The fixed point around which the circle is drawn. In a standard form equation like \((x-a)^{2} + (y-b)^{2} = r^{2}\), the center is \((a, b)\).
- **Radius**: The distance from the center to any point on the circle. It is given by \(r\) in the equation, which is the square root of the value on the right-hand side.
Completing the Square
Completing the square is a method used to transform quadratic expressions into a form that makes solving equations simpler. It is particularly useful when dealing with conic sections like circles. ### How to Complete the Square:1. **Identify the Quadratic Expression**: Look for expressions of the form \(ax^2 + bx\).2. **Half the Coefficient of x**: Take \(b\), halve it and square the result. This is called the "square term."3. **Adjust the Equation**: Add and subtract the "square term" inside the equation to help reorganize it into a perfect square trinomial.For example, in the equation \(x^{2} + y^{2} + 14y = -13\), focusing on \(y\):
- The constant term with \(y\) is 14. Half of it is 7, and 7 squared is 49.
- Reorganize. Add 49 inside the equation where appropriate to complete the square: \(x^{2} + (y + 7)^{2} = 36\).
Other exercises in this chapter
Problem 17
Identify the focus and the directrix of the graph of each equation. $$ y=x^{2} $$
View solution Problem 18
Find the foci for each equation of an ellipse. Then graph the ellipse. $$ \frac{x^{2}}{4}+\frac{y^{2}}{9}=1 $$
View solution Problem 18
Find the foci of each hyperbola. Then draw the graph. $$ 14 y^{2}-28 x^{2}=448 $$
View solution Problem 18
Identify the focus and the directrix of the graph of each equation. $$ y=-\frac{1}{8} x^{2} $$
View solution