Problem 18
Question
Identify the center of each ellipse and graph the equation. $$(x+3)^{2}+\frac{(y+4)^{2}}{9}=1$$
Step-by-Step Solution
Verified Answer
The center of the given ellipse, \((x+3)^{2}+\frac{(y+4)^{2}}{9}=1\), is \((-3, -4)\). To graph the ellipse, plot the center point at \((-3, -4)\), draw the major and minor axes by moving 1 unit in the x-direction and 3 units in the y-direction, and then sketch the elongated oval shape using these points as guides.
1Step 1: Identifying the Center of the Ellipse
Comparing the given equation,
\[(x+3)^{2}+\frac{(y+4)^{2}}{9}=1\]
with the standard form of an ellipse (\(\frac{(x - h)^2}{a^2} + \frac{(y - k)^2}{b^2} = 1\)), we can see that the center of the ellipse is the point (h, k) where:
\(h = -3\)
\(k = -4\)
So, the center of the ellipse is \((-3, -4)\).
2Step 2: Graphing the Ellipse and Its Center
Now that we have identified the center of the ellipse, we will proceed to graph the ellipse along with its center. To do this, we first recognize that:
\(a^2 = 1\), so \(a = 1\)
\(b^2 = 9\), so \(b = 3\)
Using these values and the center of the ellipse, we can graph the ellipse as follows:
1. Plot the center point \((-3, -4)\) on the coordinate plane.
2. From the center, move 1 unit in both the positive and negative x-directions to draw the major axis (since it's horizontal in this case).
3. From the center, move 3 units in both the positive and negative y-directions to draw the minor axis.
4. Sketch the ellipse by drawing an elongated oval shape, using the points from steps 2 and 3 as guides.
Now, the ellipse has been graphed along with its center, \((-3, -4)\).
Key Concepts
ellipse equationgraphing ellipsescenter of ellipsealgebraic graphing
ellipse equation
An ellipse is a fascinating geometrical shape that extends along two axes. Its mathematical representation is derived from its standard form equation. The ellipse equation looks like this: \[ \frac{(x - h)^2}{a^2} + \frac{(y - k)^2}{b^2} = 1 \] In this equation:
(h, k)is the center of the ellipse.ais the semi-major axis length.bis the semi-minor axis length.
graphing ellipses
Graphing an ellipse involves plotting it on the coordinate plane based on its equation. First, identify the center, which acts as a reference point for the entire shape. Next, determine the lengths of the major and minor axes using the values under \((x - h)^2\) and \((y - k)^2\) in the standard ellipse equation. Here,
- The major axis aligns with the direction of the larger value among \(a\) and \(b\).
- The minor axis aligns perpendicular to the major axis.
center of ellipse
The center of an ellipse is crucial as it serves as the anchor around which the entire ellipse is graphed. To find the center from the equation: \((x+3)^{2} + \frac{(y+4)^{2}}{9} = 1\), compare it with the standard form \[ \frac{(x - h)^2}{a^2} + \frac{(y - k)^2}{b^2} = 1 \] From this comparison:
hcomes from shifting \(x\), identified by setting \(h = -3\).kcomes from shifting \(y\), identified by setting \(k = -4\).
algebraic graphing
Algebraic graphing is a powerful tool in visualizing mathematical ideas such as ellipses. It involves plotting equations onto a coordinate grid to provide a visual context for abstract concepts. To graph algebraically:
- Start by analyzing the given equation and extracting necessary components like the center, axes length, etc.
- Plot these components accurately on the graph.
- Use these plotted points to form the shape described by the equation.
Other exercises in this chapter
Problem 18
Solve the exponential equation algebraically. Then check using a graphing calculator. $$e^{-t}=0.04$$
View solution Problem 18
Solve. $$\frac{2}{x^{2}-9}+\frac{5}{x-3}=\frac{3}{x+3}$$
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Solve each system. $$\begin{aligned} 2 x^{2}+y &=9 \\ y &=3 x^{2}+4 \end{aligned}$$
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The top three apple growers in the world - China, the United States, and Turkey - grew a total of about 74 billion lb of apples in a recent year. China produced
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