Problem 18
Question
Granite has a mass density of \(2650 \mathrm{~kg} / \mathrm{m}^{3}\). Find its weight density in \(\mathrm{lb} / \mathrm{ft}^{3}\).
Step-by-Step Solution
Verified Answer
The weight density of granite is approximately \(1621.47 \mathrm{~lb/ft}^{3}\).
1Step 1: Understand the Relationship between Mass Density and Weight Density
To find the weight density, we need to multiply the mass density by the acceleration due to gravity. The mass density (\(\rho\)) is given in kilograms per cubic meter \(\frac{\mathrm{kg}}{\mathrm{m}^3}\). The acceleration due to gravity \(g\) is \(9.81 \, \mathrm{m/s^2}\). The weight density \(w\) is defined as \(w = \rho \times g\), and is typically given in newtons per cubic meter \(\mathrm{N/m^3}\).
2Step 2: Convert Mass Density to Weight Density in SI Units
Calculate the weight density in \(\mathrm{N/m^3}\) using the formula: \[ w = 2650 \, \frac{\mathrm{kg}}{\mathrm{m}^3} \times 9.81 \, \mathrm{m/s^2} \]This calculation gives the weight density in newtons per cubic meter.
3Step 3: Calculate Weight Density in SI Units
Multiply the given mass density by the gravity constant:\[ w = 2650 \times 9.81 = 25960.5 \, \mathrm{N/m^3} \]The weight density of granite in newtons per cubic meter is \(25960.5 \, \mathrm{N/m^3}\).
4Step 4: Conversion of Units from SI to Imperial
To convert from \(\mathrm{N/m^3}\) to \(\mathrm{lb/ft^3}\), use the conversion factor: 1 \(\mathrm{N/m^2} = 0.020885 \mathrm{lb/ft^2}\) and for volumes, 1 \(\mathrm{m^3} = 35.3147 \mathrm{ft^3}\).Therefore, 1 \(\mathrm{N/m^3} = 0.020885 \times 35.3147 = 0.06243 \mathrm{lb/ft^3}\).
5Step 5: Calculate Granite's Weight Density in Imperial Units
Using the conversion factor calculated, convert the weight density:\[ \text{Weight Density in Imperial} = 25960.5 \, \mathrm{N/m^3} \times 0.06243 \, \frac{\mathrm{lb}}{\mathrm{ft^3}} = 1621.47 \, \mathrm{lb/ft^3} \]The weight density of granite in \(\mathrm{lb/ft^3}\) is approximately \(1621.47\).
Key Concepts
Mass Density of GraniteAcceleration Due to GravitySI to Imperial Unit Conversion
Mass Density of Granite
Granite is a common and dense igneous rock, with a notable mass density of approximately 2650 kilograms per cubic meter (kg/m³). Mass density is a crucial property, as it refers to the mass of material per unit volume. It indicates how heavy granite is for its size.
- Granite's mass density: The figure of 2650 kg/m³ tells us that a cubic meter of granite weighs 2650 kilograms.
- Physical implications: Higher mass density often corresponds to a more compact and solid material, making granite a preferred choice for building and construction.
Acceleration Due to Gravity
Acceleration due to gravity, symbolized as \( g \), is a constant that represents the acceleration of an object due to Earth's gravitational pull, with a standard value of 9.81 meters per second squared (m/s²). This constant is pivotal when converting mass density into weight density.
- Role in conversions: By multiplying the mass density by gravity, you get the weight density, determining how much force is exerted by a substance due to gravity.
- In scientific terms: Weight is defined as the gravitational force exerted on an object, hence weight density (N/m³) can be derived by the product of mass density (kg/m³) and gravity (m/s²).
SI to Imperial Unit Conversion
Conversion between the International System of Units (SI) and Imperial units is a fundamental skill in science and engineering. In this exercise, the task is to convert weight density from newtons per cubic meter (N/m³) to pounds per cubic foot (lb/ft³), which involves multiple conversion factors.
- Basic conversions: 1 N/m² equals 0.020885 lb/ft², and 1 m³ equals 35.3147 ft³. These factors are used to bridge the gap between metric and imperial measurements.
- Practical relevance: Engineers and architects often need to convert units to accommodate different measurement systems prevalent in varying geographic regions.
Other exercises in this chapter
Problem 16
A firefighter weighs 725 N. She wears shoes that each cover an area of \(206 \mathrm{~cm}^{2}\). (a) What is the average stress she applies to the ground on whi
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View solution Problem 18
The cross-sectional area of a wire is \(2.50 \times 10^{-3} \mathrm{~cm}^{2}\) and its tensile strength is \(1.00 \times 10^{5} \mathrm{~N} / \mathrm{cm}^{2}\).
View solution Problem 19
Find the mass density of a metal block \(18.0 \mathrm{~cm} \times 24.0 \mathrm{~cm} \times 8.00 \mathrm{~cm}\) with mass \(9.76 \mathrm{~kg}\)
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