Problem 18
Question
For the following problems, the first quantity represents the product and the second quantity a factor. Find the other factor. $$ 8 a^{2}+4 a, 4 a $$
Step-by-Step Solution
Verified Answer
Answer: The other factor is \(2a + 1\).
1Step 1: Set up the division
We start by setting up the division as follows:
$$
\frac{8a^2 + 4a}{4a}
$$
2Step 2: Divide the product by the factor
Next, we divide each term in the product by the factor:
$$
\frac{8a^2}{4a} + \frac{4a}{4a}
$$
3Step 3: Simplify the division
Finally, we simplify each term in the division:
$$
2a + 1
$$
So, the other factor is \(2a + 1\).
Key Concepts
Polynomial DivisionFactoringSimplification
Polynomial Division
Polynomial division is a method used to divide polynomials, similar to the way long division is used with numbers. This process is often employed to simplify expressions or find missing factors. In the given exercise, the goal is to determine the remaining factor when dividing a polynomial by a known factor.
To set up polynomial division, place the polynomial you want to divide as the 'numerator' and the divisor, which is the known factor, as the 'denominator'. For example, in our problem, we have
\[\frac{8a^2 + 4a}{4a}\]
This setup simulates the division process, allowing us to divide each term in the polynomial individually by the divisor.
To set up polynomial division, place the polynomial you want to divide as the 'numerator' and the divisor, which is the known factor, as the 'denominator'. For example, in our problem, we have
\[\frac{8a^2 + 4a}{4a}\]
This setup simulates the division process, allowing us to divide each term in the polynomial individually by the divisor.
- The numerator consists of the terms \(8a^2\) and \(4a\).
- The denominator is the factor \(4a\).
Factoring
Factoring involves breaking down a complex expression into a product of simpler expressions. This is essential in solving algebraic equations, simplifying expressions, or finding roots. In our exercise, it helps identify the other factor when one factor is already known.
To factor an expression, you search for common terms that can be 'factored out'. In the polynomial \(8a^2 + 4a\), notice that \(4a\) can be factored out from both terms. This common factor is crucial as it forms part of the solution.
\[8a^2 + 4a = 4a(2a + 1)\]
This result shows the expression's factorized form, revealing the other factor \(2a + 1\).
To factor an expression, you search for common terms that can be 'factored out'. In the polynomial \(8a^2 + 4a\), notice that \(4a\) can be factored out from both terms. This common factor is crucial as it forms part of the solution.
- Look for the greatest common factor (GCF) among the terms.
- Factor out the GCF.
\[8a^2 + 4a = 4a(2a + 1)\]
This result shows the expression's factorized form, revealing the other factor \(2a + 1\).
Simplification
Simplification is the process of rewriting expressions in their simplest form. This makes them easier to understand and work with, which is especially important when solving equations.
In our provided solution, simplification occurs after dividing each term. Here, we take \(\frac{8a^2}{4a} + \frac{4a}{4a}\) and simplify each component:
\[2a + 1\]
Simplification leads us to clear and concise results, like identifying the other factor in multiplication problems. Mastering this skill is key in solving algebra problems effectively.
In our provided solution, simplification occurs after dividing each term. Here, we take \(\frac{8a^2}{4a} + \frac{4a}{4a}\) and simplify each component:
- The term \(\frac{8a^2}{4a}\) simplifies to \(2a\).
- The term \(\frac{4a}{4a}\) simplifies to \(1\), since any number divided by itself is 1.
\[2a + 1\]
Simplification leads us to clear and concise results, like identifying the other factor in multiplication problems. Mastering this skill is key in solving algebra problems effectively.
Other exercises in this chapter
Problem 18
For the following problems, factor the binomials. $$ y^{2}-49 $$
View solution Problem 18
For the following problems, use the grouping method to factor the polynomials. Some polynomials may not. be factorable using the grouping method. $$ x^{2}+4 x-3
View solution Problem 18
In the following problems, the first quantity represents the product and the second quantity represents a factor of that product. Find the other factor. $$ 22 b
View solution Problem 19
For the following problems, factor the trinomials when possible. $$ x^{2}-4 x-21 $$
View solution