Problem 18
Question
For the following problems, find the least common multiple of given numbers. 4, 5, 21
Step-by-Step Solution
Verified Answer
Answer: The least common multiple of 4, 5, and 21 is 420.
1Step 1: Prime Factorization of the Given Numbers
Prime factorize the given numbers using a factor tree or division method.
4 = 2^2
5 = 5^1
21 = 3^1 * 7^1
2Step 2: Identify the Maximum Exponents for Each Prime Factor
Find the maximum exponent for each prime factor among the given numbers.
For 2: the maximum exponent is 2
For 3: the maximum exponent is 1
For 5: the maximum exponent is 1
For 7: the maximum exponent is 1
3Step 3: Calculate the Least Common Multiple (LCM)
Multiply each prime factor raised to its maximum exponent calculated in the previous step to get the LCM.
LCM = 2^2 * 3^1 * 5^1 * 7^1
LCM = 4 * 3 * 5 * 7
LCM = 420
The least common multiple of 4, 5, and 21 is 420.
Key Concepts
Prime FactorizationFactor Tree MethodExponentMultiplication of Prime Factors
Prime Factorization
Prime factorization is the process of expressing a number as the product of its prime numbers. A prime number is a number that has only two divisors: 1 and itself. For example, when we break down the number 4 using prime factorization, we represent it as \(2^2\). This means 4 is the product of two 2's multiplied together. Similarly:
- 5 is already a prime number, so its factorization is \(5^1\).
- 21 can be broken down into \(3^1 \times 7^1\), both of which are prime numbers.
Factor Tree Method
The factor tree method is a visual way to perform prime factorization. It's like breaking down a number into branches until you reach the prime factors. Here's how it works:
- Start with the number you want to factorize, like 21.
- Draw two branches and write down any pair of factors, such as 3 and 7, which multiply to give 21.
- Continue breaking down the factors until all branches end with prime numbers.
Exponent
In prime factorization, an exponent represents the number of times a prime number is multiplied by itself. For instance, in \(2^2\), 2 is the base (the prime number), and 2 is the exponent showing it is multiplied by itself:
- \(2 \times 2 = 4\)
Multiplication of Prime Factors
Once you've identified the prime factors and their highest exponents, you can calculate the least common multiple by multiplying these factors. For the numbers 4, 5, and 21:
- The factors are \(2^2\), \(3^1\), \(5^1\), and \(7^1\).
- Multiply these together: \(2^2 \times 3^1 \times 5^1 \times 7^1\).
- This results in 4 x 3 x 5 x 7 = 420.
Other exercises in this chapter
Problem 18
For the following problems, convert each decimal to a percent. $$ 5.875 $$
View solution Problem 18
For the following problems, perform each indicated operation. \(\frac{7}{10} \div \frac{10}{7}\)
View solution Problem 18
For the following problems, find the prime factorization of each whole number. Use exponents on repeated factors. 54
View solution Problem 18
For the following problems, expand each product (do not compute the actual value). \(x^{6} \cdot y^{2}\)
View solution