Problem 18
Question
For the following exercises, write the first eight terms of the piecewise sequence. \(a_{n}=\left\\{\begin{array}{ll}(2 n+1)^{2} & \text { if } n \text { is divisible by } 4 \\ \frac{2}{n} & \text { if } n \text { is not divisible by } 4\end{array}\right.\)
Step-by-Step Solution
Verified Answer
The first eight terms are: 2, 1, \(\frac{2}{3}\), 81, \(\frac{2}{5}\), \(\frac{1}{3}\), \(\frac{2}{7}\), 289.
1Step 1: Understand the Piecewise Function
We need to generate the first eight terms of the sequence given by a piecewise function. The function provides two different expressions depending on the divisibility of \(n\) by 4.
2Step 2: Calculate Terms for n Divisible by 4
For values of \(n\) that are divisible by 4 (such as 4 and 8 in our range), we use the expression \((2n+1)^2\).
3Step 3: Calculate Terms for n Not Divisible by 4
For values of \(n\) not divisible by 4 (1, 2, 3, 5, 6, 7 in our range), we use the expression \(\frac{2}{n}\).
4Step 4: Compute Terms 1 to 4
- For \(n = 1\), since 1 is not divisible by 4, use \(\frac{2}{1} = 2\).- For \(n = 2\), use \(\frac{2}{2} = 1\).- For \(n = 3\), use \(\frac{2}{3}\).- For \(n = 4\), use \((2\cdot4+1)^2 = 81\).
5Step 5: Compute Terms 5 to 8
- For \(n = 5\), use \(\frac{2}{5}\).- For \(n = 6\), use \(\frac{2}{6} = \frac{1}{3}\).- For \(n = 7\), use \(\frac{2}{7}\).- For \(n = 8\), use \((2\cdot8+1)^2 = 289\).
6Step 6: Write the First Eight Terms
The first eight terms of the sequence are: 2, 1, \(\frac{2}{3}\), 81, \(\frac{2}{5}\), \(\frac{1}{3}\), \(\frac{2}{7}\), 289.
Key Concepts
Sequence TermsDivisibilityExpression EvaluationPiecewise Expressions
Sequence Terms
In mathematics, a sequence is an ordered list of numbers that follow a particular pattern or rule. Each value in the sequence is known as a "term." Each term of a sequence can be described using a mathematical expression, which allows us to calculate the term based on its position in the sequence.
In the exercise, the task is to find the first eight sequence terms. These terms are determined by a piecewise function, meaning they arise from different expressions depending on their position.
In the exercise, the task is to find the first eight sequence terms. These terms are determined by a piecewise function, meaning they arise from different expressions depending on their position.
- The first term corresponds to when the position, denoted by \(n\), is 1.
- The second term corresponds to \(n = 2\), and so on, up to \(n = 8\).
Divisibility
Divisibility determines whether one integer can be divided by another integer without leaving a remainder. It is especially important in sequence problems that include expressions conditioned by divisibility.
In the given piecewise sequence, we need to check the divisibility of \(n\) by 4:
In the given piecewise sequence, we need to check the divisibility of \(n\) by 4:
- If \(n\) is divisible by 4, it means dividing \(n\) by 4 leaves no remainder. For instance, 4 and 8 are divisible by 4.
- If \(n\) is not divisible by 4, there will be a remainder left when dividing \(n\) by 4. Numbers like 1, 2, 3, 5, 6, and 7 are not divisible by 4 in our range.
Expression Evaluation
Evaluating an expression means calculating its value based on given conditions and inputs. For a piecewise sequence, we sometimes need to evaluate different expressions to find the specific term.
To evaluate the terms of this sequence, follow:
To evaluate the terms of this sequence, follow:
- For \(n\) divisible by 4: Use the expression \((2n+1)^2\). For example, for \(n = 4\), replace \(n\) with 4 in the expression to get \((2 \cdot 4 + 1)^2 = 81\).
- For \(n\) not divisible by 4: Use \(\frac{2}{n}\). So, when \(n = 2\), substitute \(n\) with 2 in the expression to find \(\frac{2}{2} = 1\).
Piecewise Expressions
Piecewise functions use different expressions based on certain conditions. A single function consists of multiple "pieces," allowing it to manage different rules under different circumstances.
The current exercise uses a piecewise-defined sequence where:
The current exercise uses a piecewise-defined sequence where:
- One piece, \((2n+1)^2\), is used when \(n\) is divisible by 4.
- The other, \(\frac{2}{n}\), is used when \(n\) is not divisible by 4.
Other exercises in this chapter
Problem 18
For the following exercises, express each geometric sum using summation notation. \(-\frac{1}{6}+\frac{1}{12}-\frac{1}{24}+\ldots+\frac{1}{768}\)
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For the following exercises, find the specified term for the geometric sequence, given the first term and common ratio. The first term is \(2,\) and the common
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For the following exercises, four coins are tossed. Find the probability of tossing exactly two heads.
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For the following exercises, use the Binomial Theorem to expand each binomial. $$ (4 x-3 y)^{5} $$
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