Problem 18
Question
For the following exercises, use the Binomial Theorem to expand each binomial. $$ (3 x-2 y)^{4} $$
Step-by-Step Solution
Verified Answer
The expanded form of \((3x - 2y)^4\) is \(81x^4 - 216x^3y + 216x^2y^2 - 96xy^3 + 16y^4\).
1Step 1: Understand the Binomial Theorem
The Binomial Theorem provides a way to expand expressions of the form \((a + b)^n\) into a sum involving terms of the form \(a^k b^{n-k}\). The general expansion formula is \((a + b)^n = \sum_{k=0}^{n} \binom{n}{k} a^{n-k} b^k\).
2Step 2: Identify Components
In the binomial \((3x - 2y)^4\), identify \(a = 3x\), \(b = -2y\), and \(n = 4\). The goal is to expand using these components.
3Step 3: Compute Binomial Coefficients
Use the binomial coefficient formula \(\binom{n}{k}\), where \(k\) ranges from 0 to \(n\). Compute each coefficient for \(n = 4\):- \(\binom{4}{0} = 1\)- \(\binom{4}{1} = 4\)- \(\binom{4}{2} = 6\)- \(\binom{4}{3} = 4\)- \(\binom{4}{4} = 1\)
4Step 4: Expand the Expression
Apply the Binomial Theorem expansion:\[(3x - 2y)^4 = \sum_{k=0}^{4} \binom{4}{k} (3x)^{4-k} (-2y)^k\]This gives us:- For \(k = 0\), the term is \(1 \cdot (3x)^4 \cdot (-2y)^0 = 81x^4\)- For \(k = 1\), the term is \(4 \cdot (3x)^3 \cdot (-2y)^1 = -216x^3y\)- For \(k = 2\), the term is \(6 \cdot (3x)^2 \cdot (-2y)^2 = 216x^2y^2\)- For \(k = 3\), the term is \(4 \cdot (3x)^1 \cdot (-2y)^3 = -96xy^3\)- For \(k = 4\), the term is \(1 \cdot (3x)^0 \cdot (-2y)^4 = 16y^4\)
5Step 5: Write the Final Expanded Expression
Combine all terms to write the final expanded form:\[(3x - 2y)^4 = 81x^4 - 216x^3y + 216x^2y^2 - 96xy^3 + 16y^4\]
Key Concepts
Binomial coefficientPolynomial expansionAlgebraic expressions
Binomial coefficient
The binomial coefficient is a crucial part of the binomial theorem, used to determine the coefficients in the expansion of a binomial expression. When you see a binomial raised to a power, as in \((a + b)^n\), the binomial coefficients are found using the combination formula: \(\binom{n}{k} = \frac{n!}{k!(n-k)!}\), where \(n\) is the power and \(k\) is a specific term in the series.
Here's how you can break it down:
Here's how you can break it down:
- \(n!\) ("n factorial") is the product of all positive integers up to \(n\).
- The formula \(\binom{n}{k}\) tells you how many ways you can pick \(k\) elements from a set of \(n\) elements.
Polynomial expansion
Polynomial expansion involves writing a binomial expression raised to a power as a polynomial. This means expressing it as a sum of multiple terms.
The binomial theorem guides the expansion process by using the formula for each term:\(a^{n-k}b^k\) multiplied by its corresponding binomial coefficient, \(\binom{n}{k}\).
When expanding \((3x - 2y)^4\), you break the task:
The binomial theorem guides the expansion process by using the formula for each term:\(a^{n-k}b^k\) multiplied by its corresponding binomial coefficient, \(\binom{n}{k}\).
When expanding \((3x - 2y)^4\), you break the task:
- Compute each term by substituting \(a = 3x\), \(b = -2y\), and \(n = 4\).
- Calculate the specific power for each term according to the decreasing powers of \(a\) and increasing powers of \(b\).
- Adjust the signs of each term if necessary, based on the term's part in the binomial.
Algebraic expressions
Algebraic expressions are combinations of numbers, variables, and operators (like plus and minus signs). These expressions can represent real-world quantities and allow complex problem solving.
In our exercise, \((3x - 2y)^4\) is an algebraic expression where:
Understanding these expansions enables handling more complex algebraic tasks by breaking them into simpler parts.
In our exercise, \((3x - 2y)^4\) is an algebraic expression where:
- \(3x\) and \(-2y\) are individual terms.
- The expression involves a subtraction and multiplication as key operations.
- It's raised to a power, meaning it needs expansion for simplification.
Understanding these expansions enables handling more complex algebraic tasks by breaking them into simpler parts.
Other exercises in this chapter
Problem 17
For the following exercises, write the first eight terms of the piecewise sequence. \(a_{n}=\left\\{\begin{array}{ll}\frac{n^{2}}{2 n+1} & \text { if } n \quad
View solution Problem 18
For the following exercises, four coins are tossed. What is the sample space?
View solution Problem 18
For the following exercises, compute the value of the expression. $$ P(9,6) $$
View solution Problem 18
For the following exercises, express each geometric sum using summation notation. \(-\frac{1}{6}+\frac{1}{12}-\frac{1}{24}+\ldots+\frac{1}{768}\)
View solution