Problem 18
Question
For the following exercises, use function composition to verify that \(f(x)\) and \(g(x)\) are inverse functions. $$ f(x)=-3 x+5 \text { and } g(x)=\frac{x-5}{-3} $$
Step-by-Step Solution
Verified Answer
The functions are inverses because \(f(g(x)) = x\) and \(g(f(x)) = x\).
1Step 1: Understanding Function Composition
To verify that two functions are inverses, we must show that their compositions equal the identity function. This means we compute \(f(g(x))\) and \(g(f(x))\), and both should simplify to \(x\).
2Step 2: Compute \(f(g(x))\)
Substitute \(g(x) = \frac{x-5}{-3}\) into \(f(x) = -3x + 5\). \[ f(g(x)) = f\left(\frac{x-5}{-3}\right) = -3\left(\frac{x-5}{-3}\right) + 5 \]Simplifying this:\[ f(g(x)) = (-3) \cdot \frac{x-5}{-3} + 5 = (x-5) + 5 = x \].Thus, \(f(g(x)) = x\).
3Step 3: Compute \(g(f(x))\)
Substitute \(f(x) = -3x + 5\) into \(g(x) = \frac{x-5}{-3}\).\[ g(f(x)) = g(-3x + 5) = \frac{(-3x+5) - 5}{-3} \]Simplifying this:\[ g(f(x)) = \frac{-3x}{-3} = x \].Thus, \(g(f(x)) = x\).
4Step 4: Conclusion
Since both compositions \(f(g(x)) = x\) and \(g(f(x)) = x\) hold true, functions \(f(x)\) and \(g(x)\) are indeed inverse functions.
Key Concepts
Understanding Function CompositionIdentity Function and Its RoleExploring Algebraic Functions
Understanding Function Composition
Function composition is a fundamental concept in mathematics that helps determine how functions interact with one another. It involves plugging one function into another. This can be thought of as a function eating another function! To check if two functions, say \( f(x) \) and \( g(x) \), are inverses, we use function composition. The key here is that when you compose the two functions, both \( f(g(x)) \) and \( g(f(x)) \) should return back to the original input \( x \).
- If \( f(g(x)) = x \), the result tells us that \( g(x) \) effectively "undoes" the work of \( f(x) \), returning us to the starting point.
- Similarly, if \( g(f(x)) = x \), it means \( f(x) \) "undoes" \( g(x)\) in the same way.
Identity Function and Its Role
The identity function, denoted usually by \( I(x) = x \), is like a pure reflection in math; it returns any input exactly as it is. When examining the inverse nature of two functions, function compositions should yield the identity function.
In simpler terms, if you feed the identity function with a number, it spits out the same number. It's the 'do-nothing' function but essential for determining inverses. If we compute both \( f(g(x)) \) and \( g(f(x)) \) using function composition and get \( x \) each time, this demonstrates the functions act as each other's inverse.
In simpler terms, if you feed the identity function with a number, it spits out the same number. It's the 'do-nothing' function but essential for determining inverses. If we compute both \( f(g(x)) \) and \( g(f(x)) \) using function composition and get \( x \) each time, this demonstrates the functions act as each other's inverse.
- The identity function's role here boosts our confidence that we've correctly computed the compositions.
- It assures us that the original functions get nullified to the initial input \( x \).
Exploring Algebraic Functions
Algebraic functions, like those given in the exercise \( f(x) = -3x + 5 \) and \( g(x) = \frac{x-5}{-3} \), are made up of polynomials and rational expressions that follow set rules in their operations. When determining if they are inverses, algebraic manipulation is key.
To solve and confirm the inverse relationship, we substitute one function inside the other and simplify using standard algebra techniques. This involves operations like:
To solve and confirm the inverse relationship, we substitute one function inside the other and simplify using standard algebra techniques. This involves operations like:
- Adding and subtracting constants.
- Multiplying and dividing terms.
- Simplifying fractions by canceling common terms.
Other exercises in this chapter
Problem 17
For the following exercises, find the domain of each function using interval notation. $$ f(x)=\frac{x-3}{x^{2}+9 x-22} $$
View solution Problem 17
For the following exercises, determine whether the relation represents \(y\) as a function of \(x\). $$ y=\frac{3 x+5}{7 x-1} $$
View solution Problem 18
For the following exercises, describe how the graph of the function is a transformation of the graph of the original function \(f\). $$ y=f(x-2)+3 $$
View solution Problem 18
For the following exercises, graph the absolute value function. Plot at least five points by hand for each graph. $$ y=|x|+1 $$
View solution