Problem 18
Question
For the following exercises, solve the inequality involving absolute value. Write your final answer in interval notation. $$ |2 x+1|+1 \leq 6 $$
Step-by-Step Solution
Verified Answer
The solution in interval notation is \([-3, 2]\).
1Step 1: Isolate the Absolute Value
The first step is to isolate the absolute value expression. Start by moving 1 to the other side of the inequality: \[ |2x + 1| + 1 \leq 6 \] Subtract 1 from both sides:\[ |2x + 1| \leq 5 \]
2Step 2: Set Up Compound Inequality
When dealing with an inequality involving an absolute value, we create a compound inequality representing both possible scenarios for the absolute value. Therefore, we consider: \[ -5 \leq 2x + 1 \leq 5 \]
3Step 3: Solve Left Side of Inequality
Solve the left side of the inequality: \[ -5 \leq 2x + 1 \] Subtract 1 from both sides: \[ -6 \leq 2x \] Divide both sides by 2: \[ -3 \leq x \]
4Step 4: Solve Right Side of Inequality
Now solve the right side of the inequality: \[ 2x + 1 \leq 5 \] Subtract 1 from both sides:\[ 2x \leq 4 \] Divide both sides by 2:\[ x \leq 2 \]
5Step 5: Combine Solutions
Combine the solutions obtained from the left and right sides of the compound inequality: \[ -3 \leq x \leq 2 \] This represents the interval for the solution.
Key Concepts
Interval NotationCompound InequalitySolving InequalitiesAlgebraic Expressions
Interval Notation
Interval notation is a method of writing the set of solutions to an inequality in a concise and clear way. In interval notation, we describe a range of values for which an inequality holds true, using brackets and parentheses.
For example, the solution obtained in the step-by-step process, \(-3 \leq x \leq 2\), means that \(x\) can take any value from \(-3\) to \(2\), inclusive. In interval notation, this is written as:\[[-3, 2]\]This means our solution set is the continuous range of numbers starting from \(-3\) to \(2\), where both endpoints are included. This format is widely used because it is clean, efficient, and visually shows the range of solutions.
- Square brackets \([\ ]\) denote inclusive boundaries, meaning the endpoint is part of the solution set.
- Parentheses \((\ )\) indicate that the endpoint is not included in the solution set.
For example, the solution obtained in the step-by-step process, \(-3 \leq x \leq 2\), means that \(x\) can take any value from \(-3\) to \(2\), inclusive. In interval notation, this is written as:\[[-3, 2]\]This means our solution set is the continuous range of numbers starting from \(-3\) to \(2\), where both endpoints are included. This format is widely used because it is clean, efficient, and visually shows the range of solutions.
Compound Inequality
A compound inequality combines two inequalities into one statement using the word 'and' or 'or'. In the context of absolute value inequalities, we examine both the positive and negative scenarios of the expression inside the absolute value.
For the inequality \(|2x + 1| \leq 5\), we set up a compound inequality because the absolute value expression can be equal to either the positive 5 or negative 5 values:
\[-5 \leq 2x + 1 \leq 5 \]This compound inequality requires that \(2x + 1\) falls between \(-5\) and \(5\).
Solving this type of inequality involves transforming it into two separate inequalities and then solving each one individually. What's unique about a compound inequality like this is that the solutions from both parts will be combined into one continuous set, helping to maintain both conditions simultaneously.
For the inequality \(|2x + 1| \leq 5\), we set up a compound inequality because the absolute value expression can be equal to either the positive 5 or negative 5 values:
\[-5 \leq 2x + 1 \leq 5 \]This compound inequality requires that \(2x + 1\) falls between \(-5\) and \(5\).
Solving this type of inequality involves transforming it into two separate inequalities and then solving each one individually. What's unique about a compound inequality like this is that the solutions from both parts will be combined into one continuous set, helping to maintain both conditions simultaneously.
Solving Inequalities
Solving inequalities involves finding the set of all possible values that satisfy the given inequality. For absolute value inequalities, this process includes handling two potential scenarios: one for the expression inside the absolute value being positive and one for it being negative.
Here’s the step-by-step breakdown for solving an inequality:
Here’s the step-by-step breakdown for solving an inequality:
- Isolate the absolute value expression: Begin by moving all other terms to the other side of the inequality.
- Set up a compound inequality: Reflect the two scenarios—the expression inside the absolute value could be either negative or positive.
- Solve each part: Solve the separate inequalities like regular equations, maintaining the inequality direction unless you multiply or divide by a negative number, which flips the inequality.
- Combine the results: Compile the solutions to form the solution in interval format.
Algebraic Expressions
Algebraic expressions are combinations of letters and numbers along with operational symbols like plus, minus, multiply, and divide. They form the foundation of solving inequalities and equations.
An expression like \(2x + 1\) is an algebraic expression that shows multiplication of a variable \(x\) by 2, followed by an addition of 1.These expressions become central when solving inequalities because:
An expression like \(2x + 1\) is an algebraic expression that shows multiplication of a variable \(x\) by 2, followed by an addition of 1.These expressions become central when solving inequalities because:
- They have to be manipulated carefully during steps to isolate variables.
- Understanding how to adjust these expressions correctly determines whether the inequality remains true.
- Each part impacts how the entire inequality is represented when rewritten.
Other exercises in this chapter
Problem 17
For each of the following exercises, find the distance between the two points. Simplify your answers, and write the exact answer in simplest radical form for ir
View solution Problem 17
Solve each rational equation for x. State all x-values that are excluded from the solution set. \(2-\frac{3}{x+4}=\frac{x+2}{x+4}\)
View solution Problem 18
For the following exercises, solve the following polynomial equations by grouping and factoring. $$ 2 x^{3}-14 x^{3}=0 $$
View solution Problem 18
Solve the inequality involving absolute value. Write your final answer in interval notation. $$ |2 x+1|+1 \leq 6 $$
View solution