Problem 18
Question
For every \(x \in \mathbb{R}^{n}\) and every \(\delta>0\) define the "rectangle" \(R(x, \delta):=\left(x_{1}-\delta, x_{1}+\delta\right) \times\left(x_{2}-\right.\) \(\left.\delta, x_{2}+\delta\right) \times \cdots \times\left(x_{n}-\delta, x_{n}+\delta\right) .\) Show that these sets generate the same open sets as the balls in standard metric. That is, show that a set \(U \subset \mathbb{R}^{n}\) is open in the sense of the standard metric if and only if for every point \(x \in U,\) there exists \(a \delta>0\) such that \(R(x, \delta) \subset U\)
Step-by-Step Solution
Verified Answer
Open sets in rectangles and balls in \(\mathbb{R}^n\) are equivalent definitions of openness.
1Step 1: Understanding Open Sets in Standard Metric
An open set in the standard metric on \(\mathbb{R}^n\) is defined such that for every point \(x \in U\), there exists an \(\epsilon > 0\) such that the open ball \(B(x, \epsilon) = \{y \in \mathbb{R}^n : \| y - x \| < \epsilon \}\) is contained within \(U\). We aim to show that rectangles \(R(x, \delta)\) can serve the same purpose.
2Step 2: Showing Rectangle Can Contain Ball
Consider a point \(x \in U\). There exists an \(\epsilon > 0\) such that \(B(x, \epsilon) \subset U\) because \(U\) is open. The rectangle \(R(x, \delta)\) can be chosen such that it fits inside \(B(x, \epsilon)\) by selecting \(\delta < \frac{\epsilon}{\sqrt{n}}\). This ensures that the rectangle, with its boundaries tightly hugging the ball, is contained within \(U\).
3Step 3: Showing Ball Can Contain Rectangle
If \(R(x, \delta) \subset U\), then for a small enough positive \(\delta\), we can fit a ball inside \(R(x, \delta)\). Specifically, choose \(\epsilon = \delta\). The ball \(B(x, \epsilon)\) is contained within the rectangle because every component \(x_i\) satisfies \(x_i - \delta < y_i < x_i + \delta\), ensuring \(\| y - x \| < \delta \) and thus \(B(x, \delta) \subset R(x, \delta)\).
4Step 4: Concluding Open Set Definition Equivalence
Since a rectangle \(R(x, \delta)\) can contain a ball and a ball can be contained within a rectangle, we have established that for every \(x \in U\) there exists a \(\delta > 0\) ensuring \(R(x, \delta) \subset U\) when \(U\) is open. Conversely, if \(R(x, \delta) \subset U\), a ball \(B(x, \epsilon)\) exists such that \(B(x, \epsilon) \subset U\), confirming that \(U\) is open.
Key Concepts
Open SetsStandard MetricRectangles in Euclidean SpaceOpen Balls
Open Sets
In the realm of metric spaces, an open set is a versatile concept that helps in understanding topology, especially in Euclidean spaces, like \(\mathbb{R}^n\). Let's break this down:
- An open set contains its boundary, which means if you pick any point \(x\) from the open set \(U\), you can find a small neighborhood or space around \(x\) that also lies completely within \(U\).
- In the context of standard metrics, any point in an open set \(U\) means there's always an open ball around \(x\), with some radius \(\epsilon\) that remains inside \(U\).
Standard Metric
The standard metric, often experienced in everyday life, is the Euclidean distance. It's how we typically measure distance and how we determine the size of spaces and sets in the Euclidean space \(\mathbb{R}^n\).
- The standard metric is calculated as \(\| x - y \| = \sqrt{(x_1-y_1)^2 + (x_2-y_2)^2 + \cdots + (x_n-y_n)^2}\), which is essentially the Pythagorean theorem extended to multiple dimensions.
- This metric helps in forming what's known as 'open balls'. The idea is that within this defined distance, or radius \(\epsilon\), you can create a round area centered at point \(x\) where every point inside maintains a distance lesser than \(\epsilon\) from \(x\).
Rectangles in Euclidean Space
Rectangles in Euclidean space offer a fascinating alternative to understanding open sets. Unlike open balls, rectangles are defined as Cartesian products of intervals. This makes them slightly box-shaped, rather than circular.
- A rectangle \(R(x, \delta)\) itself is defined by intervals around each coordinate \(x_i\), stretching from \(x_i - \delta\) to \(x_i + \delta\).
- These rectangles are important because they can encompass or be encompassed by open balls by appropriately choosing \(\delta\). For example, by setting \(\delta\) quite small, a rectangle can snugly fit within an open ball.
Open Balls
Open balls are an essential concept in comprehending open sets within metric spaces. In the standard metric, an open ball \(B(x, \epsilon)\) creates a perfectly rounded boundary.
- The open ball is defined around a center point \(x\) and extends in every direction with radius \(\epsilon\), such that every point \(y\) within this ball is at a distance less than \(\epsilon\) from \(x\).
- This structure of an open ball ensures that it comfortably nests entirely within an open set \(U\) if \(x \in U\).
Other exercises in this chapter
Problem 17
Let \((X, d)\) be an incomplete metric space. Show that there exists a closed and bounded set \(E \subset X\) that is not compact.
View solution Problem 17
Define $$ f(x, y):=\left\\{\begin{array}{ll} \frac{2 x y}{x^{2}+y^{2}} & \text { if }(x, y) \neq(0,0) \\ 0 & \text { if }(x, y)=(0,0) \end{array}\right. $$ a) S
View solution Problem 18
Let \((X, d)\) be a metric space and \(K \subset X .\) Prove that \(K\) is compact as a subset of \((X, d)\) if and only if \(K\) is compact as a subset of itse
View solution Problem 20
Let \((X, d)\) be a complete metric space. We say a set \(S \subset X\) is relatively compact if the closure \(\bar{S}\) is compact. Prove that \(S \subset X\)
View solution