Problem 18
Question
Five alkenes have the formula \(\mathrm{C}_{7} \mathrm{H}_{14}\) and a seven- carbon chain. Draw their structures and name them.
Step-by-Step Solution
Verified Answer
1-heptene, 2-heptene, 3-heptene, 4-methyl-1-hexene, and 3-methyl-1-hexene.
1Step 1: Introduction to the problem
We need to identify five alkenes with the chemical formula \(\mathrm{C}_7\mathrm{H}_{14}\) that each have a seven-carbon chain. Since each has the same molecular formula, they are structural isomers differing in the position of the double bond.
2Step 2: Identify the first alkene: 1-Heptene
The simplest alkene is obtained by positioning the double bond at the beginning of the carbon chain. Structure: \(CH_2=CH(CH_2)_5CH_3\). The name for this compound is 1-heptene.
3Step 3: Identify the second alkene: 2-Heptene
Move the double bond one carbon inward. Structure: \(CH_3CH=CH(CH_2)_4CH_3\). The name for this compound is 2-heptene.
4Step 4: Identify the third alkene: 3-Heptene
Continue shifting the double bond. Structure: \(CH_3(CH_2)CH=CH(CH_2)_3CH_3\). The name for this compound is 3-heptene.
5Step 5: Identify the fourth alkene: 4-Methyl-1-hexene
Introduce a methyl group branching at the fourth carbon. Structure: \(CH_2=CH(CH_2)_3CH(CH_3)CH_3\). The compound name is 4-methyl-1-hexene.
6Step 6: Identify the fifth alkene: 3-Methyl-1-hexene
Place a methyl group at the third carbon from a terminal double bond. Structure: \(CH_2=CH(CH_2)_2CH(CH_3)CH_2CH_3\). The compound name is 3-methyl-1-hexene.
Key Concepts
Molecular Formula C7H14Structural IsomersOrganic ChemistryDouble Bond Positioning
Molecular Formula C7H14
A molecular formula provides essential information about the types and numbers of atoms present in a compound. In this problem, the molecular formula is \(\mathrm{C}_7\mathrm{H}_{14}\), which represents an alkene. Alkenes are a class of hydrocarbons characterized by a carbon-carbon double bond.
With \(7\) carbon atoms and \(14\) hydrogen atoms, this formula indicates the compound is not a saturated hydrocarbon. Saturated hydrocarbons, like alkanes, contain single bonds only. Adding a double bond leads to the general formula for alkenes, \(\mathrm{C}_n\mathrm{H}_{2n}\). Hence, knowing the formula \(\mathrm{C}_7\mathrm{H}_{14}\) helps us understand we're dealing with an unsaturated hydrocarbon.
This information sets the stage for exploring different structural forms, known as isomers, that can exist with this fixed formula.
With \(7\) carbon atoms and \(14\) hydrogen atoms, this formula indicates the compound is not a saturated hydrocarbon. Saturated hydrocarbons, like alkanes, contain single bonds only. Adding a double bond leads to the general formula for alkenes, \(\mathrm{C}_n\mathrm{H}_{2n}\). Hence, knowing the formula \(\mathrm{C}_7\mathrm{H}_{14}\) helps us understand we're dealing with an unsaturated hydrocarbon.
This information sets the stage for exploring different structural forms, known as isomers, that can exist with this fixed formula.
Structural Isomers
Structural isomers are molecules that have the same molecular formula but differ in the arrangement of atoms. This difference can significantly alter their properties. With alkenes having the formula \(\mathrm{C}_7\mathrm{H}_{14}\), these isomers arise from varying the position of the double bond along the carbon chain.
For instance, 1-heptene features the double bond at the beginning of the seven-carbon chain, while 2-heptene moves it one carbon inward.
The formation of branched isomers like 4-methyl-1-hexene, where a methyl group is present, showcases an additional way to create structural isomers. This type of branching alters the main carbon chain, introducing more structural diversity without changing the overall molecular formula.
For instance, 1-heptene features the double bond at the beginning of the seven-carbon chain, while 2-heptene moves it one carbon inward.
- 1-heptene: introduces a double bond at the first carbon
- 2-heptene: moves the double bond to the second carbon
- 3-heptene: shifts the double bond to the third position
The formation of branched isomers like 4-methyl-1-hexene, where a methyl group is present, showcases an additional way to create structural isomers. This type of branching alters the main carbon chain, introducing more structural diversity without changing the overall molecular formula.
Organic Chemistry
Organic chemistry focuses on the study of carbon-containing compounds and their properties. Alkenes, a major functional group in organic chemistry, are characterized by a carbon-carbon double bond. This double bond is responsible for much of an alkene's reactivity and chemical behavior.
Understanding alkenes involves recognizing how the double bond influences molecular properties and how variants like structural isomers offer diverse physical and chemical characteristics. The versatility of organic compounds arises from their ability to form various isomeric forms, each with unique structural, physical, and chemical properties.
Organic chemists manipulate these structures to suit different needs, from industrial applications to pharmaceuticals, showcasing the expansive applications of these fundamental principles.
Understanding alkenes involves recognizing how the double bond influences molecular properties and how variants like structural isomers offer diverse physical and chemical characteristics. The versatility of organic compounds arises from their ability to form various isomeric forms, each with unique structural, physical, and chemical properties.
Organic chemists manipulate these structures to suit different needs, from industrial applications to pharmaceuticals, showcasing the expansive applications of these fundamental principles.
Double Bond Positioning
Double bond positioning is crucial in defining the characteristics and reactivity of an alkene. As seen in the structural isomers of \(\mathrm{C}_7\mathrm{H}_{14}\), altering the placement of this double bond can result in entirely different molecules. Each position offers unique properties and names to the resulting compounds.
Consider the alkenes:
These subtle changes in the position of a double bond illustrate the intricacies of organic chemistry. They underline why seemingly small modifications can lead to significant differences in molecular behavior and function, pivotal for deeply understanding and innovating within the field.
Consider the alkenes:
- 1-heptene: Located at the start of the chain, this position is straightforward and linear
- 2-heptene: The shift towards the chain’s middle can affect the molecule’s stability and reactivity
- 3-heptene: With the bond further inward, it provides yet another variation
These subtle changes in the position of a double bond illustrate the intricacies of organic chemistry. They underline why seemingly small modifications can lead to significant differences in molecular behavior and function, pivotal for deeply understanding and innovating within the field.
Other exercises in this chapter
Problem 16
What structural requirement is necessary for an alkene to have cis and trans isomers? Can cis and trans isomers exist for an alkane? For an alkyne?
View solution Problem 17
A hydrocarbon with the formula \(\mathrm{C}_{5} \mathrm{H}_{10}\) can be either an alkene or a cycloalkane. (a) Draw a structure for each of the possible isomer
View solution Problem 19
Draw the structure and give the systematic name for the products of the following reactions: (a) \(\mathrm{CH}_{3} \mathrm{CH}=\mathrm{CH}_{2}+\mathrm{Br}_{2} \
View solution Problem 22
The compound 2,3 -dibromo-2-methylhexane is formed by addition of \(\mathrm{Br}_{2}\) to an alkene. Identify the alkene, and write an equation for this reaction
View solution