Problem 18
Question
Find the \(x\) -intercept and the \(y\) -intercept of the graph of each equation. Do not graph the equation. $$2 x=4 y-13$$
Step-by-Step Solution
Verified Answer
So, the x-intercept is -6.5 and the y-intercept is 3.25
1Step 1: Finding the x-intercept
Set y to 0 in the given equation: \(2x = 4(0) - 13\). Simplify and solve the equation to find the value of x.
2Step 2: Finding the y-intercept
Set x to 0 in the given equation: \(2(0) = 4y -13\). Simplify and solve the equation to find the value of y.
Key Concepts
Algebra: Understanding InterceptsLinear Equations: Basic Form and InterceptsGraphing Equations: Visualizing Linear Relationships
Algebra: Understanding Intercepts
In algebra, intercepts are key concepts when dealing with linear equations. They represent the points where the line crosses the axes on a graph. There are two main types of intercepts:
By understanding intercepts, you're learning to decode the relationship between algebraic equations and their graphic representations. This decoding helps in visualizing how numbers behave under various mathematical situations. It's like finding the basic building blocks of the equation.
- x-intercept: The point where the line crosses the x-axis. This occurs when the value of y is zero.
- y-intercept: The point where the line crosses the y-axis. This happens when the value of x is zero.
By understanding intercepts, you're learning to decode the relationship between algebraic equations and their graphic representations. This decoding helps in visualizing how numbers behave under various mathematical situations. It's like finding the basic building blocks of the equation.
Linear Equations: Basic Form and Intercepts
Linear equations form the backbone of many algebraic concepts. A linear equation in its simplest form is expressed as \[ y = mx + b \], where \( m \) is the slope and \( b \) is the y-intercept.
This equation represents a straight line when graphed on a coordinate plane.In a typical linear equation like the one given: \[ 2x = 4y - 13 \], you can rearrange this to make it more recognizable. Rearranging helps identify the intercepts more easily.
By isolating either variable, you simply set the other to zero to uncover the intercepts.
Linear equations thus serve as a clear method to describe a direct relationship between two quantities.
This equation represents a straight line when graphed on a coordinate plane.In a typical linear equation like the one given: \[ 2x = 4y - 13 \], you can rearrange this to make it more recognizable. Rearranging helps identify the intercepts more easily.
By isolating either variable, you simply set the other to zero to uncover the intercepts.
- For the x-intercept, set \( y = 0 \) and solve for \( x \).
- For the y-intercept, set \( x = 0 \) and solve for \( y \).
Linear equations thus serve as a clear method to describe a direct relationship between two quantities.
Graphing Equations: Visualizing Linear Relationships
Graphing equations is an essential skill in understanding algebra's practical side. When you graph a linear equation, you visually represent the relationship between x and y. This direct visual allows you to grasp abstract concepts more concretely. Using the intercepts provides an easy way to plot these equations.
When you derive the intercepts from an equation, you determine two key points that the graph passes through:
This method is both simple and effective, making it a favorite technique for students new to graphing. By consistently using intercepts to plot graphs, you develop a clearer understanding of how equations translate into visual forms. It's a powerful skill illustrating the practical utility of algebra.
When you derive the intercepts from an equation, you determine two key points that the graph passes through:
- x-intercept: Located at (x,0)
- y-intercept: Located at (0,y)
This method is both simple and effective, making it a favorite technique for students new to graphing. By consistently using intercepts to plot graphs, you develop a clearer understanding of how equations translate into visual forms. It's a powerful skill illustrating the practical utility of algebra.
Other exercises in this chapter
Problem 18
Write the point-slope form of the equation of the line satisfying each of the conditions in Exercises \(1-28 .\) Then use the point-slope form of the equation t
View solution Problem 18
In Exercises \(13-26,\) begin by solving the linear equation for \(y .\) This will put the equation in slope-intercept form. Then find the slope and the \(y\) -
View solution Problem 18
Plot the given point in a rectangular coordinate system. $$\left(\frac{7}{2}, \frac{5}{2}\right)$$
View solution Problem 19
Write the point-slope form of the equation of the line satisfying each of the conditions in Exercises \(1-28 .\) Then use the point-slope form of the equation t
View solution