Problem 18
Question
Find the amplitude, the period, and the phase shift and sketch the graph of the equation. \(y=3 \cos (3 x-\pi)\)
Step-by-Step Solution
Verified Answer
Amplitude: 3, Period: \(\frac{2\pi}{3}\), Phase shift: Right \(\frac{\pi}{3}\).
1Step 1: Identify the Amplitude
The amplitude of a trigonometric function like cosine is given by the absolute value of the coefficient in front of the cosine function. For the equation \(y = 3 \cos(3x - \pi)\), the coefficient is 3. Thus, the amplitude is \(|3| = 3\).
2Step 2: Determine the Period
The period of a cosine function is found using the formula \(\frac{2\pi}{b}\), where \(b\) is the coefficient of \(x\) inside the cosine function. In the equation \(y = 3 \cos(3x - \pi)\), \(b = 3\). Therefore, the period is \(\frac{2\pi}{3}\).
3Step 3: Calculate the Phase Shift
The phase shift of a trigonometric function in the form \(y = a \cos(bx - c)\) is calculated as \(\frac{c}{b}\). For our equation, \(c = \pi\) and \(b = 3\). The phase shift is \(\frac{\pi}{3}\). Since the \(c\) term is \(3x - \pi\), which is negative, it indicates a shift to the right by \(\frac{\pi}{3}\).
4Step 4: Sketch the Graph
To sketch the graph, start by plotting the basic cosine graph. Adjust for the amplitude by scaling the height to 3. Then, compress the wave horizontally due to the shorter period \(\frac{2\pi}{3}\). Finally, shift the entire graph to the right by \(\frac{\pi}{3}\). The wave will repeat every \(\frac{2\pi}{3}\) units along the x-axis, with peaks reaching a height of 3 and troughs at -3.
Key Concepts
Understanding AmplitudeDetermining the PeriodGrasping Phase Shift
Understanding Amplitude
Amplitude in trigonometric functions refers to the height from the centerline to the peak (or trough) of the wave. In mathematical terms, it is the
For a cosine function represented by the general form \(y = a \cos(bx - c)\), amplitude is determined by the absolute value of \(a\).
So, if you have \(y = 3 \cos(3x - \pi)\), you simply take the coefficient in front of the cosine, which is 3, thus the amplitude is
An easy way to visualize this is: Imagine a straight line running through the middle of your sine or cosine wave; the amplitude is how much the wave bounces away from this line, both upwards and downwards. The greater the amplitude, the taller the wave crest and the deeper the trough, but
Understanding amplitude is crucial when sketching graphs of trigonometric functions as it helps you determine how tall the wave will be.
- "maximum vertical distance"
- from the equilibrium position of the wave.
For a cosine function represented by the general form \(y = a \cos(bx - c)\), amplitude is determined by the absolute value of \(a\).
So, if you have \(y = 3 \cos(3x - \pi)\), you simply take the coefficient in front of the cosine, which is 3, thus the amplitude is
- \(|3| = 3\).
An easy way to visualize this is: Imagine a straight line running through the middle of your sine or cosine wave; the amplitude is how much the wave bounces away from this line, both upwards and downwards. The greater the amplitude, the taller the wave crest and the deeper the trough, but
- it doesn't affect the length of one complete cycle.
Understanding amplitude is crucial when sketching graphs of trigonometric functions as it helps you determine how tall the wave will be.
Determining the Period
The period of a trigonometric function is the horizontal length required for the function to complete one full cycle before repeating. It determines how stretched or compressed a wave looks along the x-axis.
This is crucial for illustrating the function accurately on a coordinate plane.
For functions of the form \(y = a \cos(bx - c)\), the period is calculated using the formula:
so the period is \(\frac{2\pi}{3}\).
A smaller period indicates that the graph repeats more frequently within a given range on the x-axis, making the wave look more
When plotting, knowing the period helps you allocate the right amount of space on the x-axis for each cycle, allowing for a visually accurate representation of how the wave behaves over time.
This is crucial for illustrating the function accurately on a coordinate plane.
For functions of the form \(y = a \cos(bx - c)\), the period is calculated using the formula:
- \(\frac{2\pi}{b}\)
so the period is \(\frac{2\pi}{3}\).
A smaller period indicates that the graph repeats more frequently within a given range on the x-axis, making the wave look more
- "squished"
- or "compressed"
When plotting, knowing the period helps you allocate the right amount of space on the x-axis for each cycle, allowing for a visually accurate representation of how the wave behaves over time.
Grasping Phase Shift
Phase shift involves the horizontal translation of a wave along the x-axis. This concept comes into play in equations like \(y = a \cos(bx - c)\), where the phase shift is determined by the part of the function \(c\).
To find out the exact shift, use the formula:
Because it’s negative \(3x - \pi\), the graph will shift to the right.
Consider this: if you're looking at a cosine wave, usually, it starts at a peak when \(x = 0\). With a phase shift, this familiar starting point moves left or right, altering the x-value that the wave appears to start its cycle.
In our example, the graph's initial peaks, troughs, and midpoints all move \(\frac{\pi}{3}\) units to the right on the x-axis.
Phase shift changes when and where the wave-like pattern begins without affecting the actual shape or height of the wave itself; it merely "slides" the whole function horizontally.
To find out the exact shift, use the formula:
- \(\frac{c}{b}\)
Because it’s negative \(3x - \pi\), the graph will shift to the right.
Consider this: if you're looking at a cosine wave, usually, it starts at a peak when \(x = 0\). With a phase shift, this familiar starting point moves left or right, altering the x-value that the wave appears to start its cycle.
In our example, the graph's initial peaks, troughs, and midpoints all move \(\frac{\pi}{3}\) units to the right on the x-axis.
Phase shift changes when and where the wave-like pattern begins without affecting the actual shape or height of the wave itself; it merely "slides" the whole function horizontally.
Other exercises in this chapter
Problem 17
Find the exact values of the trigonometric functions for the acute angle \(\theta\). $$\sin \theta=\frac{3}{5}$$
View solution Problem 18
Given the indicated parts of triangle \(A B C\) with \(\gamma=90^{\circ},\) express the third part in terms of the first two. $$\beta, c ; \quad b$$
View solution Problem 18
Use a formula for negatives to find the exact value. $$\text { (a) } \sin \left(-\frac{3 \pi}{2}\right) \quad \text { (b) } \cos \left(-225^{\circ}\right) \quad
View solution Problem 18
Find the period and sketch the graph of the equation. Show the asymptotes. $$y=-3 \tan \left(\frac{1}{3} x-\frac{\pi}{3}\right)$$
View solution