Problem 18
Question
Find \(k\) such that each function is a probability density function over the given interval. Then write the probability density function. $$ f(x)=k, \quad[1,4] $$
Step-by-Step Solution
Verified Answer
The probability density function is \(f(x) = \frac{1}{3}\) over \([1, 4]\).
1Step 1: Understand the Requirements of a Probability Density Function
For a function to qualify as a probability density function over an interval, the total area under the function (when integrated over the specified interval) must equal 1. In our case, the function is constant over the interval \([1,4]\).
2Step 2: Integrate the Function Over the Interval
Since the function is constant, integrating it over the interval \([1,4]\) is straightforward. The integral of \(f(x) = k\) from 1 to 4 is \[\int_{1}^{4} k \, dx = k(x)]_{1}^{4}\].
3Step 3: Evaluate the Definite Integral
Substitute the interval limits into the evaluated integral: \[k(x)]_{1}^{4} = k(4) - k(1) = 3k\].
4Step 4: Set the Integral Equal to 1 and Solve for \(k\)
To satisfy the condition of being a probability density function, set the integral equal to 1: \[3k = 1\]. Solve this equation for \(k\) to get \(k = \frac{1}{3}\).
5Step 5: Write the Probability Density Function
Now that we have determined \(k = \frac{1}{3}\), the probability density function is \[f(x) = \frac{1}{3}\] for the interval \([1,4]\).
Key Concepts
IntegrationDefinite IntegralSolving EquationsCalculus Basics
Integration
Integration is a fundamental concept in calculus that involves calculating the area under a curve. It is essentially the process of finding an integral. In the context of probability density functions, integration helps in determining the likelihood of a random variable falling within a particular range.
When integrating a constant function like in this example, the process simplifies, as constants are easy to handle:
When integrating a constant function like in this example, the process simplifies, as constants are easy to handle:
- Identify the interval over which to integrate. Here, it is \([1,4]\).
- Set up the integral of the function over this interval.
- Evaluate the integral using fundamental calculus rules.
Definite Integral
The definite integral is a type of integral with defined upper and lower limits, representing the total area under the curve within that specific interval. When determining if a function, such as a probability density function, integrates to a particular value, the definite integral is utilized.
In this problem, the definite integral of \(f(x)=k\) is evaluated over \[1,4\]. Substituting these limits of the interval into \[k(x)\biggr|_{1}^{4}=k(4) - k(1)=3k\], we see how we assess the function's behavior:
In this problem, the definite integral of \(f(x)=k\) is evaluated over \[1,4\]. Substituting these limits of the interval into \[k(x)\biggr|_{1}^{4}=k(4) - k(1)=3k\], we see how we assess the function's behavior:
- The result of this definite integral must equal 1 for the function to represent a probability density function.
- Definite integrals are essential for ensuring that cumulative probabilities over an interval meet this requirement.
Solving Equations
A key part of this exercise involves solving an equation derived from the integration process. Once the definite integral is set up and evaluated, the next step is to solve:
- The given equation \(3k=1\) comes from equating the integral to 1 because, for probability density functions, total area = 1.
- Solving simple linear equations such as this involves isolating the variable, leading here to \(k=\frac{1}{3}\).
Calculus Basics
Understanding calculus fundamentals is invaluable for tackling problems involving probability density functions and other mathematical concepts. Basics cover a wide span of ideas that build towards solving our specific issue:
- Grasping basic function properties helps with integrating across intervals, whether constant or variable.
- Recognizing the importance of setting up correct integrals allows solving for unknowns like \(k\) accurately.
- Comprehending linear equations is foundational to finding solutions after integration.
Other exercises in this chapter
Problem 18
(a) find the general solution of each differential equation, and (b) check the solution by substituting into the differential equation. \(\frac{d V}{d t}=1.33 \
View solution Problem 18
Find the volume generated by rotating the area bounded by the graphs of each set of equations around the \(x\) -axis. $$ y=\sqrt{1-x^{2}}, x=-1, x=1 $$
View solution Problem 18
Determine whether each improper integral is convergent or divergent, and find its value if it is convergent. $$ \int_{1}^{\infty} \ln x d x $$
View solution Problem 19
Let \(x\) be a continuous random variable with a standard normal distribution. Using Table A, find each of the following. $$ P(-2.45 \leq x \leq-1.24) $$
View solution