Problem 18
Question
Find an antiderivative for each function. Do as many as you can mentally. Check your answers by differentiation. a. \(\sec x \tan x\) b. \(4 \sec 3 x \tan 3 x\) c. \(\sec \frac{\pi x}{2} \tan \frac{\pi x}{2}\)
Step-by-Step Solution
Verified Answer
a. \(\sec x + C\); b. \(\frac{4}{3} \sec 3x + C\); c. \(\frac{2}{\pi} \sec \frac{\pi x}{2} + C\).
1Step 1: Understanding Antiderivatives
An antiderivative of a function is a function whose derivative is the original function. In this exercise, we are finding an antiderivative of each given function. We'll identify the basic antiderivatives and use properties of integration.
2Step 2: Finding an Antiderivative for \( \sec x \tan x \)
Recognizing that the derivative of \( \sec x \) is \( \sec x \tan x \), the antiderivative of \( \sec x \tan x \) is \( \sec x + C \), where \( C \) is the constant of integration.
3Step 3: Check by Differentiation for \( \sec x \tan x \)
Differentiate \( \sec x + C \). The derivative of \( \sec x \) is \( \sec x \tan x \). Hence, \( \frac{d}{dx}(\sec x + C) = \sec x \tan x \), which confirms our antiderivative is correct.
4Step 4: Finding an Antiderivative for \( 4 \sec 3x \tan 3x \)
Recognize that the derivative of \( \sec 3x \) is \( 3\sec 3x \tan 3x \). The antiderivative of \( 4\sec 3x \tan 3x \) is \( \frac{4}{3} \sec 3x + C \).
5Step 5: Check by Differentiation for \( 4 \sec 3x \tan 3x \)
Differentiate \( \frac{4}{3} \sec 3x + C \). Using the chain rule, the derivative is \( 4\sec 3x \tan 3x \). This confirms our antiderivative \( \frac{4}{3} \sec 3x + C \) is correct.
6Step 6: Finding an Antiderivative for \( \sec \frac{\pi x}{2} \tan \frac{\pi x}{2} \)
Recognize that the derivative of \( \sec \frac{\pi x}{2} \) is \( \frac{\pi}{2} \sec \frac{\pi x}{2} \tan \frac{\pi x}{2} \). The antiderivative is thus \( \frac{2}{\pi} \sec \frac{\pi x}{2} + C \).
7Step 7: Check by Differentiation for \( \sec \frac{\pi x}{2} \tan \frac{\pi x}{2} \)
Differentiate \( \frac{2}{\pi} \sec \frac{\pi x}{2} + C \). Again, using the chain rule, the derivative is \( \sec \frac{\pi x}{2} \tan \frac{\pi x}{2} \). This confirms our antiderivative \( \frac{2}{\pi} \sec \frac{\pi x}{2} + C \) is correct.
Key Concepts
IntegrationDifferentiationTrigonometric Functions
Integration
Integration is a fundamental concept in calculus, and it's often referred to as the reverse of differentiation. It involves finding a function whose derivative is given, which is known as finding an antiderivative. The primary goal of integration is to determine the area under a curve or to reverse the process of differentiation to find the original function from its derivative. It's particularly useful in physics, engineering, and economics.
Some key points about integration include:
Some key points about integration include:
- Indefinite integral: This represents a family of functions whose derivative is the original function. The notation for this is \( \int f(x) \, dx \), which reads "integral of \( f(x) \) with respect to \( x \)."
- Definite integral: This involves integrating within specified limits, providing the area under the curve from one point to another.
- Antiderivative: Also known as the indefinite integral, it involves finding a function whose derivative is the given function.
- Constant of integration \( C \): When finding an indefinite integral, you must always add \( C \), representing an infinite number of vertical shifts.
Differentiation
Differentiation is the process of finding the derivative of a function. The derivative represents the rate of change of a function with respect to a variable. When you differentiate, you are essentially determining how a function changes at each point. Derivatives are used to find slopes of curves, optimize functions, and solve problems involving motion and rates.
Important aspects of differentiation include:
Important aspects of differentiation include:
- Basic derivative rules: Familiarity with rules like the power, product, quotient, and chain rules helps simplify the process of differentiation.
- Chain rule: This is used when differentiating composite functions, crucial for functions involving products of trigonometric functions like \( \sec x \tan x \).
- Check by differentiation: When finding an antiderivative, checking your work involves taking the derivative of your solution to see if you arrive back at the original function.
Trigonometric Functions
Trigonometric functions extend beyond their geometric origins and are crucial in calculus, particularly for finding derivatives and antiderivatives. They include sine, cosine, tangent, secant, cosecant, and cotangent. These functions are periodic and play a key role in modeling cyclical phenomena such as sound waves, light waves, and mechanical vibrations.
Some essential points about trigonometric functions are:
Some essential points about trigonometric functions are:
- Common derivatives: Knowing the derivatives of basic trigonometric functions (e.g., derivative of \( \sin x \) is \( \cos x \); derivative of \( \tan x \) is \( \sec^2 x \)) helps in finding antiderivatives found in exercises.
- Common antiderivatives: Recognizing that the antiderivative of a derivative involves reversing these processes, such as realizing \( \sec x \tan x \) is the derivative of \( \sec x \).
- Chain rule with trigonometric functions: Often requires using the chain rule to accommodate within more complex argument expressions like \( \sec 3x \) or \( \sec \rac{\pi x}{2} \).
Other exercises in this chapter
Problem 17
Designing a suitcase \(\quad\) A 24 -in.-by- 36 -in. sheet of cardboard is folded in half to form a 24 -in.-by-18-in. rectangle as shown in the accompanying fig
View solution Problem 18
Sketch the graph of each function and determine whether the function has any absolute extreme values on its domain. Explain how your answer is consistent with T
View solution Problem 18
Identify the coordinates of any local and absolute extreme points and inflection points. Graph the function. $$y=-x^{4}+6 x^{2}-4=x^{2}\left(6-x^{2}\right)-4$$
View solution Problem 18
Suppose that \(f^{\prime \prime}\) is continuous on \([a, b]\) and that \(f\) has three zeros in the interval. Show that \(f^{\prime \prime}\) has at least one
View solution