Problem 18
Question
Find a polar representation for the complex number \(z\) and then identify \(\operatorname{Re}(z)\), \(\operatorname{Im}(z),|z|, \arg (z)\) and \(\operatorname{Arg}(z)\). $$ z=-5-2 i $$
Step-by-Step Solution
Verified Answer
\( z = \sqrt{29} ( \cos(\pi + \tan^{-1}(\frac{2}{5})) + i \sin(\pi + \tan^{-1}(\frac{2}{5})) ) \); \( \operatorname{Re}(z) = -5 \), \( \operatorname{Im}(z) = -2 \), \(|z| = \sqrt{29} \), \( \arg(z) = \pi + \tan^{-1}(\frac{2}{5}) \).
1Step 1: Identify Real and Imaginary Parts
The complex number given is \( z = -5 - 2i \). We identify the real part as \( \operatorname{Re}(z) = -5 \) and the imaginary part as \( \operatorname{Im}(z) = -2 \).
2Step 2: Calculate the Magnitude
The magnitude, or modulus, of a complex number \( z = a + bi \) is given as \( |z| = \sqrt{a^2 + b^2} \). Substitute \( a = -5 \) and \( b = -2 \). We have: \[ |z| = \sqrt{(-5)^2 + (-2)^2} = \sqrt{25 + 4} = \sqrt{29} \]
3Step 3: Calculate the Argument
The argument \( \arg(z) \) of a complex number \( a + bi \) is calculated using \( \tan^{-1}\left(\frac{b}{a}\right) \). For \( z = -5 - 2i \), we find: \[ \arg(z) = \tan^{-1}\left(\frac{-2}{-5}\right) = \tan^{-1}\left(\frac{2}{5}\right) \] Since \( z \) is in the third quadrant, add \( \pi \) to the principal value: \[ \arg(z) = \pi + \tan^{-1}\left(\frac{2}{5}\right) \]
4Step 4: Identify the Principal Argument
The principal argument \( \operatorname{Arg}(z) \) is the value of the argument that lies in the interval \(( -\pi, \pi] \). In this case, the same as the calculated \( \arg(z) \), which is \( \pi + \tan^{-1}\left(\frac{2}{5}\right) \).
5Step 5: Write the Polar Representation
The polar form of a complex number is \( z = r (\cos \theta + i \sin \theta) \), where \( r = |z| \) and \( \theta = \arg(z) \). Substitute the values: \[ z = \sqrt{29} \left( \cos\left( \pi + \tan^{-1}\left(\frac{2}{5}\right) \right) + i \sin\left( \pi + \tan^{-1}\left(\frac{2}{5}\right) \right) \right) \]
Key Concepts
Polar RepresentationReal and Imaginary PartsMagnitude of Complex NumbersArgument of Complex Numbers
Polar Representation
Complex numbers can be expressed in a form called polar representation, which is an alternative to the standard form \(a + bi\). In polar representation, a complex number \(z = a + bi\) is written in terms of its magnitude \(|z|\) and its argument \(\theta\), as:
- \( z = |z| (\cos \theta + i \sin \theta) \)
- \( z = |z| e^{i\theta} \)
- \( z = \sqrt{29} (\cos(\pi + \tan^{-1}(\frac{2}{5})) + i \sin(\pi + \tan^{-1}(\frac{2}{5})) \)
Real and Imaginary Parts
Every complex number consists of two key components: a real part and an imaginary part. These are essential for understanding and manipulating complex numbers. A complex number is commonly expressed as \(z = a + bi\), where:
- \(a\) is the real part, denoted as \(\operatorname{Re}(z)\)
- \(b\) is the imaginary part, denoted as \(\operatorname{Im}(z)\)
- The real part \(\operatorname{Re}(z) = -5\)
- The imaginary part \(\operatorname{Im}(z) = -2\)
Magnitude of Complex Numbers
The magnitude or modulus of a complex number measures the distance from the origin of the complex plane to the point represented by the complex number. It's like finding the length of the hypotenuse in a right triangle formed by the axes.The magnitude is denoted by \(|z|\), and for a complex number \(z = a + bi\), it is calculated as:
- \(|z| = \sqrt{a^2 + b^2}\)
- \(|z| = \sqrt{(-5)^2 + (-2)^2} = \sqrt{25 + 4} = \sqrt{29}\)
Argument of Complex Numbers
The argument of a complex number is a measure of the angle (in radians) formed between the positive real-axis and the line connecting the origin of the complex plane to the point represented by the complex number. It gives directionality to the complex number.For a complex number \(z = a + bi\), the argument \(\arg(z)\) is determined using:
- \( \arg(z) = \tan^{-1}\left(\frac{b}{a}\right) \)
- First quadrant: \(\arg(z)\) remains as calculated.
- Second or third quadrant: add \(\pi\).
- Fourth quadrant: typically subtract \(2\pi\) if needed to stay within \((-\pi, \pi]\).
- \( \arg(z) = \pi + \tan^{-1}\left(\frac{2}{5}\right) \)
Other exercises in this chapter
Problem 18
Find the component form of the vector \(\vec{v}\) using the information given about its magnitude and direction. Give exact values. \(\|\vec{v}\|=5 \sqrt{6}\);
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In Exercises \(1-20\), plot the graph of the polar equation by hand. Carefully label your graphs. Limaçon: \(r=2+7 \sin (\theta)\)
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The hour hand on my antique Seth Thomas schoolhouse clock in 4 inches long and the minute hand is \(5.5\) inches long. Find the distance between the ends of the
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Convert the point from polar coordinates into rectangular coordinates. $$ \left(2, \frac{\pi}{3}\right) $$
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