Problem 18
Question
Evaluate the trigonometric limits. $$ \lim _{x \rightarrow 0} \frac{1-\cos (x / 2)}{x} $$
Step-by-Step Solution
Verified Answer
The limit is 0.
1Step 1: Recognize Standard Limit
You need to evaluate the limit \( \lim _{x \rightarrow 0} \frac{1-\cos (x / 2)}{x} \). Recall the standard trigonometric limit: \( \lim_{u \to 0} \frac{1-\cos(u)}{u^2} = \frac{1}{2} \). To use this, we need to rewrite the expression to match this form.
2Step 2: Substitute Variable
Set \( u = \frac{x}{2} \) so that when \( x \to 0 \), \( u \to 0 \) as well. Note that \( x = 2u \), so rewrite the limit in terms of \( u \): \( \lim_{u \to 0} \frac{1 - \cos(u)}{2u} \).
3Step 3: Factor Out Scalar
Take \( \frac{1}{2} \) outside the limit since it is a constant multiplier: \[ \frac{1}{2} \lim_{u \to 0} \frac{1 - \cos(u)}{u} \].
4Step 4: Use Trigonometric Identity
Apply the trigonometric limit \( \lim_{u \to 0} \frac{1-\cos(u)}{u^2} = \frac{1}{2} \). Here, we need \( u \) in the denominator squared. Rewrite the limit expression as \( \frac{1}{2} \cdot \lim_{u \to 0} \left( \frac{1 - \cos(u)}{u^2} \cdot u \right) \).
5Step 5: Evaluate the Limit
Using the trigonometric limit identity: \( \lim_{u \to 0} \frac{1-\cos(u)}{u^2} = \frac{1}{2} \), therefore, \( \frac{1}{2} \lim_{u \to 0} \frac{1 - \cos(u)}{u^2} \cdot u = \frac{1}{2} \cdot \frac{u}{u^2} = \frac{1}{2} \cdot \frac{1}{u} \). As \( u \to 0 \), this gives \( 0 \).
6Step 6: Conclusion
Combine the results of the previous steps to conclude that: \( \lim _{x \rightarrow 0} \frac{1-\cos (x / 2)}{x} = 0 \).
Key Concepts
Standard Trigonometric LimitLimit EvaluationSubstitution MethodTrigonometric Identity
Standard Trigonometric Limit
One of the essential tools for evaluating limits involving trigonometric functions is the standard trigonometric limit. This is particularly useful for expressions that tend to a limit as the variable approaches zero. The key standard limit in this context is:
Recognizing the form of this standard limit is often the first step in solving the given problem.
- \( \lim_{u \to 0} \frac{1 - \cos(u)}{u^2} = \frac{1}{2} \).
Recognizing the form of this standard limit is often the first step in solving the given problem.
Limit Evaluation
Evaluating the limit requires understanding how the function behaves as the variable approaches a specific value, in this case, zero. In our problem, we need to evaluate:\( \lim _{x \rightarrow 0} \frac{1-\cos (x / 2)}{x} \).This involves rewriting or manipulating the expression into a form that reflects standard limits. Here, recognizing the '1 - cos(u)' pattern was crucial, so we could use it appropriately. By utilizing known limits, we can more easily determine the behavior of complex trigonometric expressions as they approach specific values.
Both algebraic manipulation and knowledge of trigonometric characteristics are essential for evaluating such limits effectively.
Both algebraic manipulation and knowledge of trigonometric characteristics are essential for evaluating such limits effectively.
Substitution Method
The substitution method is a powerful technique for simplifying limit problems. In this exercise, we used the substitution:\( u = \frac{x}{2} \).This substitution gives us several benefits:
- It transforms the variable \( x \) into a simpler form \( u \), which handles half-angles effectively.
- It simplifies the limit expression into \( \lim_{u \to 0} \frac{1 - \cos(u)}{2u} \).
- It allows us to apply standard limit evaluations conveniently.
Trigonometric Identity
Using trigonometric identities can greatly simplify the process of evaluating limits. In our solution, the expression was rewritten using the identity that relates the square of the denominator:\( \frac{1}{2} \cdot \lim_{u \to 0} \left( \frac{1 - \cos(u)}{u^2} \cdot u \right) \).Understanding and applying identities such as these are crucial in trigonometry because they transform complicated expressions into more manageable ones. In this case, the trigonometric identity allowed us to apply the standard limit directly and complete the limit evaluation effectively.
In sum, these identities bridge the gap between abstract trigonometric concepts and practical solutions, simplifying the process of limit evaluation.
In sum, these identities bridge the gap between abstract trigonometric concepts and practical solutions, simplifying the process of limit evaluation.
Other exercises in this chapter
Problem 17
In Problems \(15-24\), find the values of \(x \in \mathbf{R}\) for which the given functions are continuous. $$ f(x)=\frac{x^{2}+1}{x-1} $$
View solution Problem 17
Evaluate the limits in problems. $$ \lim _{x \rightarrow-\infty} \exp [x] $$
View solution Problem 18
Use the formal definition of limits to prove each statement. $$ \lim _{x \rightarrow \infty} e^{-x}=0 $$
View solution Problem 18
In Problems 1-32, use a table or a graph to investigate each limit. $$ \lim _{x \rightarrow 0} \frac{1}{x^{2}-1} $$
View solution