Problem 18
Question
Evaluate the given integral by means of the indicated change of variables. \(\begin{aligned} &\iint_{R}\left(x^{2}+y^{2}\right) \sin x y d A, \text { where } R \text { is the region bounded by the }\\\ &\text { graphs of } x^{2}-y^{2}=1, x^{2}-y^{2}=9, x y=2, x y=-2\\\ &u=x^{2}-y^{2}, v=x y \end{aligned}\)
Step-by-Step Solution
Verified Answer
Transform using the variables and integrate over 1 to 9 for \( u \) and -2 to 2 for \( v \).
1Step 1: Define the change of variables
Let \( u = x^2 - y^2 \) and \( v = xy \). We will change variables from \( (x, y) \) to \( (u, v) \). This requires finding \( x \) and \( y \) in terms of \( u \) and \( v \).
2Step 2: Express x and y in terms of u and v
Solve the system of equations: \( u = x^2 - y^2 \) and \( v = xy \). These can be expressed as \( x = r \cosh(\theta) \) and \( y = r \sinh(\theta) \) for appropriate \( r \). Use the identity \( x^2 - y^2 = u \) and \( xy = v \) to find expressions for \( x \) and \( y \) in terms of \( u \) and \( v \).
3Step 3: Compute the Jacobian of the transformation
Find the Jacobian \( J \) of the transformation from \( (x, y) \) to \( (u, v) \). Calculate the partial derivatives \( \frac{\partial(x, y)}{\partial(u, v)} \). The Jacobian, \( J = \left| \frac{\partial(x, y)}{\partial(u, v)} \right| \), should be calculated as \( \det \begin{pmatrix} \frac{\partial x}{\partial u} & \frac{\partial x}{\partial v} \ \frac{\partial y}{\partial u} & \frac{\partial y}{\partial v} \end{pmatrix} \).
4Step 4: Determine the transformed region
The original bounds given are \( x^2 - y^2 = 1 \) to \( x^2 - y^2 = 9 \) and \( xy = 2 \) to \( xy = -2 \). In \( (u, v) \) coordinates, the region is \( 1 \leq u \leq 9 \) and \( -2 \leq v \leq 2 \).
5Step 5: Rewrite the integral in terms of u and v
Rewrite the integrand \( (x^2 + y^2) \sin(xy) \) in terms of \( u \) and \( v \). The term \( x^2 + y^2 = \sqrt{u^2 + 4v^2} \) and \( \sin(xy) = \sin(v) \). The integral becomes \( \iint_{1 \leq u \leq 9, -2 \leq v \leq 2} \sqrt{u^2 + 4v^2} \sin(v) \cdot J \cdot dudv \), where \( J \) is the Jacobian.
6Step 6: Evaluate the integral
Substitute the bounds and the integrand expressed in terms of \( u \) and \( v \) into the double integral and evaluate. This step involves performing the integration over \( v \) first from \( -2 \) to \( 2 \), and then over \( u \) from \( 1 \) to \( 9 \). Simplify the expression and solve the integral, noting that if the integrand is complex, numerical methods might be used.
Key Concepts
Jacobian MatrixTransformation of CoordinatesMultiple Integrals
Jacobian Matrix
The Jacobian Matrix is crucial when performing a change of variables in double integrals. It links the differentials of the original coordinates to the new transformed ones, ensuring that the integral's value remains consistent.
A Jacobian Matrix is constituted by partial derivatives and is of the form:
A Jacobian Matrix is constituted by partial derivatives and is of the form:
- For a transformation from \((x, y)\) to \((u, v)\), the Jacobian Matrix is \( J = \begin{pmatrix} \frac{\partial x}{\partial u} & \frac{\partial x}{\partial v} \ \frac{\partial y}{\partial u} & \frac{\partial y}{\partial v} \end{pmatrix}\)
- The determinant of this matrix, \( \left| J \right| \), quantifies the area adjustment needed when transitioning between coordinate systems.
Transformation of Coordinates
Transformation of coordinates is a method utilized to simplify complex integrals by changing the variables in a coherent manner. Here's how it works:
- The process begins with determining new variables, say \(u\) and \(v\), that simplify the region of integration or the integrand itself.
- For example, in the exercise, the transformation \(u = x^2 - y^2\) and \(v = xy\) was used. This specific choice might align with the geometrical properties of the region \(R\), simplifying the integral bounds and the integrand.
Multiple Integrals
Multiple Integrals extend the idea of integration to functions of multiple variables. They allow computation over a defined region, often in two or three dimensions.
Here's a breakdown of how they work:
Here's a breakdown of how they work:
- Double integrals, such as \(\iint_R f(x, y) \,dA\), involve integrating a function \(f(x, y)\) over a region \(R\).
- The result is affected by both changes within \(R\) and by transformations of \(f(x, y)\) alone.
Other exercises in this chapter
Problem 17
Find the curvature of an elliptical helix that is described by \(\mathbf{r}(t)=a \cos t \mathbf{i}+b \sin t \mathbf{j}+c t \mathbf{k}, a>0, b>0, c>0 .\)
View solution Problem 17
Find \(\mathbf{r}^{\prime}(t)\) and \(\mathbf{r}^{\prime \prime}(t)\) for the given vector function. $$ \mathbf{r}(t)=\ln t \mathbf{i}+\mathbf{j}, t>0 $$
View solution Problem 18
Consider the surface integral \(\iint_{S}\) (curl \(\left.\mathbf{F}\right) \cdot \mathbf{n} d S\), where \(\mathbf{F}=x y z \mathbf{k}\) and \(S\) is that port
View solution Problem 18
Sketch the region \(D\) whose volume \(V\) is given by the iterated integral. $$ \int_{0}^{2} \int_{0}^{\sqrt{4-x^{2}}} \int_{x^{2}+y^{2}}^{4} d z d y d x $$
View solution