Problem 18
Question
Evaluate the definite integral of the algebraic function. Use a graphing utility to verify your result. $$ \int_{0}^{4}\left|x^{2}-4 x+3\right| d x $$
Step-by-Step Solution
Verified Answer
The solution to the definite integral \(\int_{0}^{4}\left|x^{2}-4 x+3\right| dx\) is 2. To verify this, use a graphing utility to plot the absolute function and calculate the area under the curve.
1Step 1: Partition the Function into Distinct Intervals
The expression within the absolute value brackets \(x^{2}-4x+3\) can be factored into \((x-1)(x-3)\). Then, set each factor equal to zero to determine the x-values of 1 and 3 where the expression inside the absolute value changes the sign. As such, the integral can be partitioned into three intervals: [0,1], [1,3], and [3,4].
2Step 2: Set up the Integral for Each Interval
Set up an integral for each interval according to the sign of the expression inside the absolute value in that particular interval: \[ \int_{0}^{1} -(x^{2} - 4x + 3) dx , \int_{1}^{3} (x^{2} - 4x + 3) dx , \int_{3}^{4} -(x^{2} - 4x + 3) dx \]
3Step 3: Evaluate Each Definite Integral
For each of the definite integrals, apply the power rule for antidifferentiation: \( -[\frac{1}{3}x^{3} - 2x^{2} + 3x]_{0}^{1} , [\frac{1}{3}x^{3} - 2x^{2} + 3x]_{1}^{3} , -[\frac{1}{3}x^{3} - 2x^{2} + 3x]_{3}^{4} \)
4Step 4: Calculate the Results of Each Definite Integral
Substitute the limits of the integral into the antiderivative and subtract the results. Afterwards, sum all the results.
5Step 5: Verify With a Graphing Utility
Use a graphing utility to plot the absolute function and calculate the area under the curve, ensuring it agrees with the result obtained.
Other exercises in this chapter
Problem 18
Find the derivative of the function. \(g(x)=\ln (\cosh x)\)
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Evaluate the integral. $$ \int_{\sqrt{3}}^{3} \frac{1}{9+x^{2}} d x $$
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Find the indefinite integral and check the result by differentiation. $$ \int(1+3 t) t^{2} d t $$
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Find the indefinite integral by \(u\) -substitution. (Hint: Let \(u\) be the denominator of the integrand.) $$ \int \frac{\sqrt[3]{x}}{\sqrt[3]{x}-1} d x $$
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