Problem 18
Question
Evaluate each expression, given that \(a=-2\) \(b=3,\) and \(c=-4\). $$a^{2}-|b c|$$
Step-by-Step Solution
Verified Answer
The expression evaluates to -8.
1Step 1: Substitute Values
Start by substituting the given values of \(a\), \(b\), and \(c\) into the expression \(a^2 - |bc|\). Here, \(a = -2\), \(b = 3\), and \(c = -4\). The expression becomes \((-2)^2 - |3 \times (-4)|\).
2Step 2: Calculate the Square
Calculate \((-2)^2\). The square of \(-2\) is \((-2) \times (-2) = 4\). Thus, \((-2)^2 = 4\).
3Step 3: Calculate the Product
Next, calculate the product \(b \times c\), which is \(3 \times (-4) = -12\).
4Step 4: Evaluate Absolute Value
Find the absolute value of the product calculated in Step 3. The absolute value of \(-12\) is 12, so \(|3 \times (-4)| = 12\).
5Step 5: Complete the Expression
Substitute the results from Step 2 and Step 4 into the expression: \(4 - 12\). Simplify this to find the final value: \(4 - 12 = -8\).
Key Concepts
Substitution in ExpressionsAbsolute ValueBasic Algebra
Substitution in Expressions
Substitution in expressions is a fundamental technique in algebra and arithmetic that simplifies solving problems by replacing variables with their known values. In our original exercise, we are given specific values for the variables \(a\), \(b\), and \(c\). We need to substitute these into the given expression \(a^2 - |bc|\). This step transforms the abstract expression into a concrete calculation.
- Why substitute? Substitution removes uncertainty by turning an equation with variables into one with numbers, making it easier to calculate.
- How to substitute: Each variable is replaced with its given numeric value. For instance, replace \(a\) with \(-2\), \(b\) with \(3\), and \(c\) with \(-4\).
- Example: The original expression \(a^2 - |bc|\) becomes \((-2)^2 - |3 \times (-4)|\) after substitution.
Absolute Value
Absolute value is a concept in mathematics that represents the non-negative value of a number, regardless of its sign. In simpler terms, it's how far a number is from zero, on the number line, without considering the direction. This concept is frequently used when solving arithmetic expressions to simplify calculations involving negative numbers.Consider the expression part \(|3 \times (-4)|\):
- The product of \(3\) and \(-4\) equals \(-12\).
- The absolute value of \(-12\) is \(12\), represented as \(|-12| = 12\).
Basic Algebra
Basic algebra is the branch of mathematics that deals with simplifying expressions and solving equations involving variables. It forms the foundation for understanding more advanced mathematics.In the context of our exercise, basic algebra involves:
- Applying arithmetic operations: This includes addition, subtraction, multiplication, and raising numbers to a power, as seen when we calculate \((-2)^2 = 4\).
- Simplifying expressions: After applying substitution and calculating absolute values, the expression \(a^2 - |bc|\) is simplified step-by-step to arrive at the final answer \(4 - 12 = -8\).
Other exercises in this chapter
Problem 18
find the midpoint of the line segment joining points \(P\) and \(Q\) (a) \(P(12,0)\) and \(Q(12,8)\) (b) \(P\left(\frac{3}{5},-\frac{2}{3}\right)\) and \(Q(0,0)
View solution Problem 18
Solve each equation. $$\frac{1}{x-5}+\frac{1}{x+5}=\frac{2 x+1}{x^{2}-25}$$
View solution Problem 19
Write an equation of: (a) a vertical line passing through the given point; (b) a horizontal line passing through the given point. $$(-3,4)$$
View solution Problem 19
Determine any \(x\) - or \(y\) -intercepts for the graph of the equation. Note: You're not asked to draw the graph. (a) \(y=x^{2}+x-1\) (b) \(y=x^{2}+x+1\)
View solution