Problem 18
Question
Evaluate each expression for ( \(\boldsymbol{a}\) ) \(x=4\) and \((\boldsymbol{b}) x=6\). \(\frac{x+2}{5}\)
Step-by-Step Solution
Verified Answer
For \(x=4\), the result is \(1.2\). For \(x=6\), the result is \(1.6\).
1Step 1: Understand the Expression
The expression given is \(\frac{x+2}{5} \). We are tasked with evaluating this expression for two values: \(x=4 \) and \(x=6\).
2Step 2: Substitute and Simplify for \( a \) \(x=4\)
Substitute \(x=4\) into the expression: \( \frac{4+2}{5}\). Simplify the numerator: \(4 + 2 = 6\). Now we have: \( \frac{6}{5} = 1.2\).
3Step 3: Substitute and Simplify for \( b \) \(x=6\)
Substitute \(x=6\) into the expression: \( \frac{6+2}{5}\). Simplify the numerator: \(6 + 2 = 8\). Now we have: \( \frac{8}{5} = 1.6\).
Key Concepts
Substitution in AlgebraSimplifying FractionsNumerical Evaluation
Substitution in Algebra
Substitution in algebra means replacing variables with their given numerical values. In our example, we substitute the value of x into the expression \(\frac{x+2}{5} \). We have two cases to evaluate: when \(x=4\) and when \(x=6\).
First, let's do the substitution for \(x=4\). Place 4 in place of x: \(\frac{4+2}{5}\).
For our second scenario with \(x=6\), substitute 6 where x is: \(\frac{6+2}{5}\).
Substitution helps convert the algebraic expression into a numerical one that we can then simplify further.
First, let's do the substitution for \(x=4\). Place 4 in place of x: \(\frac{4+2}{5}\).
For our second scenario with \(x=6\), substitute 6 where x is: \(\frac{6+2}{5}\).
Substitution helps convert the algebraic expression into a numerical one that we can then simplify further.
Simplifying Fractions
Simplifying fractions is crucial when working with algebraic expressions. Our goal is to reduce the fraction to its simplest form for easier interpretation.
After substitution, the original expression \(\frac{x+2}{5}\) becomes \(\frac{6}{5}\) when \(x=4\) and \(\frac{8}{5}\) when \(x=6\).
Both fractions are already in their simplest forms since the numerator and the denominator have no common factors other than 1.
When simplified, fractions give us a clearer, more manageable answer which allows us to easily identify the value.
After substitution, the original expression \(\frac{x+2}{5}\) becomes \(\frac{6}{5}\) when \(x=4\) and \(\frac{8}{5}\) when \(x=6\).
Both fractions are already in their simplest forms since the numerator and the denominator have no common factors other than 1.
When simplified, fractions give us a clearer, more manageable answer which allows us to easily identify the value.
Numerical Evaluation
Numerical evaluation involves computing the final value of an expression once the variables have been substituted.
Let's evaluate our substituted expressions. For \(x = 4\), we get \(\frac{6}{5} = 1.2\). For \(x = 6\), we have \(\frac{8}{5} = 1.6\).
These numerical evaluations give us definite numbers that represent the value of the original algebraic expression for given values of x.
This final step in the process turns abstract expressions into concrete numbers, making understanding much easier.
Let's evaluate our substituted expressions. For \(x = 4\), we get \(\frac{6}{5} = 1.2\). For \(x = 6\), we have \(\frac{8}{5} = 1.6\).
These numerical evaluations give us definite numbers that represent the value of the original algebraic expression for given values of x.
This final step in the process turns abstract expressions into concrete numbers, making understanding much easier.
Other exercises in this chapter
Problem 18
Find each sum. $$ 3+(-7) $$
View solution Problem 18
Simplify each expression. \(-12+(7-8 x)+6\)
View solution Problem 18
Find each product. 3(-15)
View solution Problem 19
Use a commutative or an associative property to complete each statement. State which property is used. \((3+6)+7=3+\)( ____ +7)
View solution