Problem 18
Question
Determine whether the given vectors are perpendicular. $$\mathbf{u}=2 \mathbf{i}, \quad \mathbf{v}=-7 \mathbf{j}$$
Step-by-Step Solution
Verified Answer
The vectors are perpendicular because their dot product is zero.
1Step 1: Understanding Perpendicular Vectors
Two vectors are perpendicular if their dot product is zero. The dot product of two vectors \( \mathbf{u} = a\mathbf{i} + b\mathbf{j} \) and \( \mathbf{v} = c\mathbf{i} + d\mathbf{j} \) is \( \mathbf{u} \cdot \mathbf{v} = ac + bd \).
2Step 2: Identifying Components of the Vectors
For \( \mathbf{u} = 2 \mathbf{i} \), the components are \( a=2 \) and \( b=0 \). For \( \mathbf{v} = -7 \mathbf{j} \), the components are \( c=0 \) and \( d=-7 \).
3Step 3: Calculate the Dot Product
Substitute the components into the dot product formula: \[ \mathbf{u} \cdot \mathbf{v} = (2)(0) + (0)(-7) = 0 + 0 = 0 \]
4Step 4: Conclusion
Since the dot product \( \mathbf{u} \cdot \mathbf{v} = 0 \), vectors \( \mathbf{u} \) and \( \mathbf{v} \) are perpendicular.
Key Concepts
Dot ProductVector ComponentsVector Notation
Dot Product
In mathematics, the dot product is an important operation when dealing with vectors. It is a way to multiply two vectors, resulting in a scalar value—this means the result is just a number, not a vector. To calculate the dot product for vectors in two-dimensional space, you use their components.
- For two vectors \(\mathbf{u} = a\mathbf{i} + b\mathbf{j}\) and \(\mathbf{v} = c\mathbf{i} + d\mathbf{j} \), the dot product is given by the formula: \( \mathbf{u} \cdot \mathbf{v} = ac + bd \).
- To find out if two vectors are perpendicular, compute their dot product. If the result is zero, the vectors are perpendicular to each other.
Vector Components
Vectors are often broken down into components to simplify calculations.
- Each vector can be represented by its components along the axis in a coordinate system. For example, a vector \( \mathbf{u} = 2 \mathbf{i} \) has a component of 2 in the direction of the horizontal axis often denoted by \( \mathbf{i} \).
- Similarly, \( \mathbf{v} = -7 \mathbf{j} \) has no component in the horizontal direction and a component of -7 in the vertical direction, denoted by \( \mathbf{j} \).
- These components are like the building blocks of the vector, as they tell you precisely how far and in what direction the vector extends along each axis.
Vector Notation
Vector notation is a universal way to write vectors, making it easier to perform calculations and convey information. In standard vector notation,
- Vectors are indicated by boldface letters, such as \( \mathbf{u} \) and \( \mathbf{v} \).
- Unit vectors \( \mathbf{i} \) and \( \mathbf{j} \) denote the directions of the horizontal and vertical axes. A vector \( \mathbf{u} = 2 \mathbf{i} \) means it goes twice as far in the direction of the \( \mathbf{i} \) unit vector.
- This notation clearly distinguishes between the magnitude and direction components of a vector, allowing simpler calculations such as adding vectors or finding the dot product.
Other exercises in this chapter
Problem 18
A plane has normal vector \(n\) and passes through the point \(P\). (a) Find an equation for the plane. (b) Find the intercepts and sketch a graph of the plane.
View solution Problem 18
Find the vectors \(\mathbf{u}+\mathbf{v}, \mathbf{u}-\mathbf{v},\) and \(3 \mathbf{u}-\frac{1}{2} \mathbf{v}\) $$\mathbf{u}=(a, 2 b, 3 c), \mathbf{v}=\langle- 4
View solution Problem 18
Show that the equation represents a sphere, and find its center and radius. $$x^{2}+y^{2}+z^{2}=14 y-6 z$$
View solution Problem 18
Express the vector with initial point \(P\) and terminal point \(Q\) in component form. $$P(-8,-6), \quad Q(-1,-1)$$
View solution