Problem 18
Question
$$ \cot ^{4} A+\cot ^{2} A=\operatorname{cosec}^{4} A-\operatorname{cosec}^{2} A $$
Step-by-Step Solution
Verified Answer
Rewriting the given identity in terms of sine and cosine, we get: \[\frac{\cos^{4} A}{\sin^{4} A}+\frac{\cos^{2} A}{\sin^2 A}= \frac{1}{\sin^{4} A} - \frac{1}{\sin^2 A}\]
After manipulating the expression and using trigonometric identities, we simplify and rewrite the expression in terms of the original functions: \[\cot^2 A = \cosec^2 A - 1\]
Hence, the trigonometric identity \(\cot ^{4} A+\cot ^{2} A=\operatorname{cosec}^{4}
A-\operatorname{cosec}^{2} A\) is proven.
1Step 1: Write the given identity in terms of sine and cosine
We are given the identity: \(\cot ^{4} A+\cot ^{2} A=\operatorname{cosec}^{4} A-\operatorname{cosec}^{2} A\)
Recall that, \(\cot A = \frac{\cos A}{\sin A}\) and \(\cosec A = \frac{1}{\sin A}\)
So, we can rewrite the given identity as:
\[\frac{\cos^{4} A}{\sin^{4} A}+\frac{\cos^{2} A}{\sin^2 A}= \frac{1}{\sin^{4} A} - \frac{1}{\sin^2 A}\]
2Step 2: Manipulate the expression
Now let's work with the expression:
\[\frac{\cos^{4} A}{\sin^{4} A}+\frac{\cos^{2} A}{\sin^2 A}= \frac{1}{\sin^{4} A} - \frac{1}{\sin^2 A}\]
To add and subtract these fractions, we need a common denominator. The common denominator is: \(\sin^{4} A\)
We express each term with this common denominator and simplify:
\[\frac{\cos^{4} A+\cos^{2} A\sin^{2} A}{\sin^{4} A} = \frac{\sin^{4} A - \sin^{2} A}{\sin^{4} A}\]
3Step 3: Factor and simplify both sides
Now, let's factor both sides of the expression:
\[\frac{\cos^{2} A(\cos^{2} A + \sin^{2} A)}{\sin^{4} A} = \frac{\sin^{2} A(\sin^{2} A - 1)}{\sin^{4} A}\]
Using the identity: \(\cos^{2} A + \sin^{2} A = 1\), we can simplify the left-hand side:
\[\frac{\cos^{2} A(1)}{\sin^{4} A} = \frac{\sin^{2} A(\sin^{2} A - 1)}{\sin^{4} A}\]
Now, we can cancel \(\sin^{2} A\) from both sides:
\[\frac{\cos^{2} A}{\sin^{2} A} = \frac{\sin^{2} A - 1}{\sin^{2} A}\]
4Step 4: Rewrite the expression in terms of original functions
Now that we have a simplified expression, let's rewrite it in terms of the original functions.
\[\cot^2 A = \cosec^2 A - 1\]
Thus, we've proven the trigonometric identity:
\[\cot ^{4} A+\cot ^{2} A=\operatorname{cosec}^{4} A-\operatorname{cosec}^{2} A\]
Key Concepts
cotangentcosecantsimplifying expressionstrigonometric equations
cotangent
The cotangent function is an important trigonometric function often represented as \( \cot A \). It's defined as the reciprocal of the tangent function. In terms of sine and cosine, cotangent is expressed as:
Understanding the cotangent function aids in solving various trigonometric equations and simplifying expressions involving other trigonometric identities.
By rewriting the cotangent in terms of sine and cosine, it becomes easier to manipulate and find common ground between different trigonometric expressions.
- \( \cot A = \frac{\cos A}{\sin A} \)
Understanding the cotangent function aids in solving various trigonometric equations and simplifying expressions involving other trigonometric identities.
By rewriting the cotangent in terms of sine and cosine, it becomes easier to manipulate and find common ground between different trigonometric expressions.
cosecant
In trigonometry, the cosecant function, denoted as \( \cosec A \), is a less common but equally crucial function. It's essentially the reciprocal of the sine function:
In the context of the identity \( \cot^4 A+\cot^2 A=\operatorname{cosec}^4 A-\operatorname{cosec}^2 A \), rewriting in terms of sine reveals new ways to reduce the complexity of the expression, making problems easier to solve.
- \( \cosec A = \frac{1}{\sin A} \)
In the context of the identity \( \cot^4 A+\cot^2 A=\operatorname{cosec}^4 A-\operatorname{cosec}^2 A \), rewriting in terms of sine reveals new ways to reduce the complexity of the expression, making problems easier to solve.
simplifying expressions
Simplifying trigonometric expressions is about breaking down complex equations into simpler, more manageable parts. This process involves using fundamental trigonometric identities and algebraic manipulation.
To simplify expressions like \( \frac{\cos^{4} A}{\sin^{4} A} + \frac{\cos^{2} A}{\sin^2 A} \), one can combine fractions with a common denominator, factor expressions, and use identities. For this equation, the identity \( \cos^{2} A + \sin^{2} A = 1 \) plays a significant role.
By understanding these techniques, you can approach simplifying expressions with confidence, converting them into forms that are easier to analyze or equate with other expressions.
To simplify expressions like \( \frac{\cos^{4} A}{\sin^{4} A} + \frac{\cos^{2} A}{\sin^2 A} \), one can combine fractions with a common denominator, factor expressions, and use identities. For this equation, the identity \( \cos^{2} A + \sin^{2} A = 1 \) plays a significant role.
By understanding these techniques, you can approach simplifying expressions with confidence, converting them into forms that are easier to analyze or equate with other expressions.
trigonometric equations
Solving trigonometric equations often requires converting complex expressions into simpler forms using trigonometric identities. The goal is to find values that satisfy equations like \( \cot ^{4} A+\cot ^{2} A=\operatorname{cosec}^{4} A-\operatorname{cosec}^{2} A \).
To approach such problems, rewriting trigonometric functions in terms of sine and cosine can help. From there, simplifying using identities and algebraic steps, like factoring or finding common denominators, becomes manageable.
Successfully tackling trigonometric equations involves understanding the behaviors and properties of trigonometric functions, allowing precise manipulation towards a solution.
To approach such problems, rewriting trigonometric functions in terms of sine and cosine can help. From there, simplifying using identities and algebraic steps, like factoring or finding common denominators, becomes manageable.
Successfully tackling trigonometric equations involves understanding the behaviors and properties of trigonometric functions, allowing precise manipulation towards a solution.
Other exercises in this chapter
Problem 16
$$ (\sin A+\cos A)(\cot A+\tan A)=\sec A+\operatorname{cosec} A $$
View solution Problem 17
$$ \sec ^{4} A-\sec ^{2} A=\tan ^{4} A+\tan ^{2} A $$
View solution Problem 19
$$ \sqrt{\operatorname{cosec}^{2} A-1}=\cos A \operatorname{cosec} A $$
View solution Problem 20
$$ \sec ^{2} A \operatorname{cosec}^{2} A=\tan ^{2} A+\cot ^{2} A+2 $$
View solution