Problem 18
Question
An inner product defined on the vector space \(P_{2}\) of all polynomials of degree less than or equal to 2 , is given by $$ (p, q)=\int_{-1}^{1} p(x) q(x) d x $$ Use the Gram-Schmidt orthogonalization process to transform the given basis \(B\) for \(P_{2}\) into an orthogonal basis \(B^{\prime}\). $$ B=\left\\{x^{2}-x, x^{2}+1,1-x^{2}\right\\} $$
Step-by-Step Solution
Verified Answer
Use Gram-Schmidt to find orthogonal \( u_i \) and then normalize to get \( B' \).
1Step 1: Compute the Gram-Schmidt Process for Basis Element 1
We start with the first basis vector, \( v_1 = x^2 - x \). Since \( v_1 \) is the first vector, it's automatically orthogonal to itself. We have \( u_1 = v_1 = x^2 - x \).
2Step 2: Orthogonalize the Second Basis Element
Next, take the second basis vector \( v_2 = x^2 + 1 \) and make it orthogonal to \( u_1 \). The formula used is \( \text{proj}_{u_1}(v_2) = \frac{(v_2, u_1)}{(u_1, u_1)} u_1 \). Calculate these integrals:1. \( (v_2, u_1) = \int_{-1}^{1} (x^2 + 1)(x^2 - x) dx \)2. \( (u_1, u_1) = \int_{-1}^{1} (x^2 - x)^2 dx \)After computing, subtract the projection from \( v_2 \) to obtain \( u_2 = v_2 - \text{proj}_{u_1}(v_2) \).
3Step 3: Orthogonalize the Third Basis Element
Proceeding to the third basis vector \( v_3 = 1 - x^2 \), make \( v_3 \) orthogonal to both \( u_1 \) and \( u_2 \). Apply Gram-Schmidt:1. Compute \( \text{proj}_{u_1}(v_3) = \frac{(v_3, u_1)}{(u_1, u_1)} u_1 \)2. Compute \( \text{proj}_{u_2}(v_3) = \frac{(v_3, u_2)}{(u_2, u_2)} u_2 \)Now calculate \( u_3 = v_3 - \text{proj}_{u_1}(v_3) - \text{proj}_{u_2}(v_3) \) to complete the orthogonalization.
4Step 4: Normalize the Orthogonal Basis
Finally, normalize each of the orthogonal vectors \( u_1, u_2, \) and \( u_3 \) to form an orthonormal basis. Divide each vector by its norm calculated as \( \|u_i\| = \sqrt{(u_i, u_i)} \) for \( i = 1, 2, 3 \). This yields the orthonormal basis \( B' \).
Key Concepts
Inner Product SpaceOrthogonal BasisVector SpacePolynomial Vector Space
Inner Product Space
An inner product space is an abstract mathematical structure that extends the idea of the dot product to more complex, infinite-dimensional vector spaces. The core idea of an inner product space is that it allows us to define and calculate products between vectors, which provides a notion of angle and length.
In our exercise, the vector space we're looking at is the polynomial vector space, denoted by \( P_2 \). Here, the vectors are polynomials, and the specific inner product is defined as \( (p, q) = \int_{-1}^{1} p(x) q(x) \, dx \).
This operation isn't multiplication as we know it in basic arithmetic; it's an integration operation that combines two functions over a specified interval to generate a single number. This number can then be used to understand geometrical and analytical properties of shapes formed by these polynomials.
In our exercise, the vector space we're looking at is the polynomial vector space, denoted by \( P_2 \). Here, the vectors are polynomials, and the specific inner product is defined as \( (p, q) = \int_{-1}^{1} p(x) q(x) \, dx \).
This operation isn't multiplication as we know it in basic arithmetic; it's an integration operation that combines two functions over a specified interval to generate a single number. This number can then be used to understand geometrical and analytical properties of shapes formed by these polynomials.
Orthogonal Basis
An orthogonal basis in a vector space is a set of basis vectors that are all orthogonal to each other. In simpler terms, each pair of different basis vectors is perpendicular.
Orthogonality is a useful property because it simplifies many calculations. For instance, when dealing with an orthogonal basis, the projection of a vector onto a subspace can be computed easily by considering single components one at a time.
Orthogonality is a useful property because it simplifies many calculations. For instance, when dealing with an orthogonal basis, the projection of a vector onto a subspace can be computed easily by considering single components one at a time.
- Orthogonality is confirmed when the inner product of the vectors equals zero, i.e., \( (v_i, v_j) = 0 \), where \( i eq j \).
- To obtain an orthogonal basis from a regular set of basis vectors, we use the Gram-Schmidt process.
Vector Space
A vector space is a fundamental concept in linear algebra and mathematics in general. It is a set equipped with two operations: vector addition and scalar multiplication. These operations must follow certain rules and axioms, such as commutativity and associativity.
- Vectors in a vector space can be added together to obtain another vector within the same space.
- Vectors can be multiplied by scalars, which are numbers from an associated field, to scale them.
Polynomial Vector Space
Polynomial vector spaces are special types of vector spaces where the elements, or vectors, are polynomial functions.
In our exercise, \( P_2 \) is the space of polynomials with degrees less than or equal to 2. This includes polynomials like \( x^2 - x \), \( x^2 + 1 \), and \( 1 - x^2 \).
They conform to all the axioms of vector spaces, meaning they can be added and multiplied by scalars while remaining within the space. They form a structured and rich space that lends itself well to orthogonalization approaches like the Gram-Schmidt process. This is because it allows us to break down complex polynomial forms into simpler, non-redundant components.
In our exercise, \( P_2 \) is the space of polynomials with degrees less than or equal to 2. This includes polynomials like \( x^2 - x \), \( x^2 + 1 \), and \( 1 - x^2 \).
They conform to all the axioms of vector spaces, meaning they can be added and multiplied by scalars while remaining within the space. They form a structured and rich space that lends itself well to orthogonalization approaches like the Gram-Schmidt process. This is because it allows us to break down complex polynomial forms into simpler, non-redundant components.
Other exercises in this chapter
Problem 18
In Problems \(17-20\), determine whether the given set is a subspace of the indicated vector space. Polynomials \(p\) that are divisible by \(x-2 ; P_{2}\)
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In Problems, find symmetric equations for the line through the given points. $$ \left(\frac{5}{6},-\frac{1}{4}, \frac{1}{5}\right),\left(\frac{1}{3}, \frac{3}{8
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A rhombus is an oblique-angled parallelogram with all four sides equal. Use the dot product to show that the diagonals of a rhombus are perpendicular.
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Describe the locus of points \(P(x, y, z)\) that satisfy the given equation(s). $$ (x-2)(z-8)=0 $$
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