Problem 18
Question
A watt is a measure of power (the rate of energy change) equal to \(1 \mathrm{~J} / \mathrm{s}\). (a) Calculate the number of joules in a kilowatt- hour. (b) An adult person radiates heat to the surroundings at about the same rate as a 100 -watt electric incandescent lightbulb. What is the total amount of energy in kcal radiated to the surroundings by an adult in 24 hours?
Step-by-Step Solution
Verified Answer
(a) There are 3.6 million joules in a kilowatt-hour. (b) An adult person radiates approximately 2064.81 kilocalories of energy to the surroundings in a 24-hour period.
1Step 1: Convert kilowatt-hours to watt-seconds
To convert kilowatt-hours to watt-seconds, we first need to convert kilowatts to watts. There are 1000 watts in 1 kilowatt, and there are 3600 seconds in 1 hour. So, 1 kilowatt-hour is equal to 1000 watts x 3600 seconds.
1 kilowatt-hour = 1000 watts × 3600 seconds
2Step 2: Convert watt-seconds to joules
Given that 1 watt is equal to 1 joule/second, we can use this relationship to convert watt-seconds to joules. Since 1 watt = 1 joule/second, 1 watt-second = 1 joule.
1 kilowatt-hour = 1000 watts × 3600 seconds × 1 joule/watt-second
3Step 3: Calculate the number of joules
We can now calculate the number of joules in a kilowatt-hour.
1 kilowatt-hour = 1000 × 3600 joules
1 kilowatt-hour = 3,600,000 joules
So, there are 3.6 million joules in a kilowatt-hour.
#b# Part (b): Calculate Energy in kcal radiated by an Adult in 24 Hours
4Step 1: Calculate energy in joules
The problem states that an adult person radiates heat at the rate of a 100-watt lightbulb. We are asked to calculate the total energy radiated in a 24-hour period. First, let's find out how many joules of energy are radiated in 24 hours:
100 watts × 24 hours × 3600 seconds/hour = 8,640,000 joules
5Step 2: Convert joules to kilocalories
Now, we need to convert joules to kilocalories. 1 kilocalorie is equal to 4184 joules. Therefore, we can use this conversion factor to calculate the energy in kilocalories:
8,640,000 joules × \( \frac{1 kcal}{4184 J} \)
6Step 3: Calculate the total energy in kcal
Finally, we can calculate the total energy in kilocalories:
\( \frac{8,640,000}{4184} \) kcal ≈ 2064.81 kcal
So, an adult person radiates approximately 2064.81 kilocalories of energy to the surroundings in a 24-hour period.
Key Concepts
Joules to Kilowatt-HoursPower MeasurementHeat Radiation by Humans
Joules to Kilowatt-Hours
Energy can be measured in various units, one of which is joules. When trying to understand larger scales of energy, such as those used typically in household power consumption, kilowatt-hours (kWh) are often used. To convert from joules to kilowatt-hours, we need to know that 1 kilowatt-hour equals 3.6 million joules. This comes from the fact that 1 kilowatt is 1,000 watts, and there are 3,600 seconds in one hour. So:
- 1 kilowatt-hour = 1,000 watts × 3,600 seconds
- = 3,600,000 joules
Power Measurement
Power is the rate at which energy is used or transferred, often measured in watts. A watt is equal to one joule per second (J/s). Understanding power is essential for calculating energy consumption over time, which is calculated by multiplying the power rating (wattage) by time. For example, if an appliance has a power rating of 100 watts and it runs for 24 hours, you can calculate the total energy used by:
- 100 watts × 24 hours = 2,400 watt-hours
- = 2,400 × 3,600 seconds = 8,640,000 joules
Heat Radiation by Humans
Humans naturally radiate heat to their surroundings, similar to a lightbulb distributing light and heat. An adult person usually radiates heat at a rate comparable to 100 watts. Over a span of 24 hours, the total energy radiated by a person can be calculated.
- 100 watts × 24 hours = 2,400 watt-hours
- = 8,640,000 joules (since 1 watt = 1 joule/second)
Other exercises in this chapter
Problem 15
(a) Calculate the kinetic energy in joules of a \(1200-\mathrm{kg}\) automobile moving at \(18 \mathrm{~m} / \mathrm{s}\). (b) Convert this energy to calories.
View solution Problem 16
(a) A baseball weighs 5.13 oz. What is the kinetic energy in joules of this baseball when it is thrown by a major-league pitcher at \(95.0 \mathrm{mph}\) ? (b)
View solution Problem 19
(a) What is meant by the term system in thermodynamics? (b) What is a closed system? (c) What do we call the part of the universe that is not part of the system
View solution Problem 20
In a thermodynamic study a scientist focuses on the properties of a solution in an apparatus as illustrated. A solution is continuously flowing into the apparat
View solution