Problem 18
Question
A vector \(\vec{v}\) is given. Give two vectors that are orthogonal to \(\vec{v}\). \(\vec{v}=\langle-3,5\rangle\)
Step-by-Step Solution
Verified Answer
Two orthogonal vectors to \(\vec{v}\) are \(\langle 5, 3 \rangle\) and \(\langle -5, -3 \rangle\).
1Step 1: Understand the Problem
We need to find two vectors that are orthogonal (perpendicular) to a given vector \(\vec{v} = \langle -3, 5 \rangle\). In a 2D plane, a vector \(\langle a, b \rangle\) is orthogonal to \(\langle b, -a \rangle\) or its negative \(\langle -b, a \rangle\).
2Step 2: Identify Orthogonal Vectors
For a vector \(\vec{v} = \langle -3, 5 \rangle\), an orthogonal vector can be found by swapping its components and changing one sign. This gives us the vector \(\langle 5, 3 \rangle\). Another orthogonal vector by changing the other sign is \(\langle -5, -3 \rangle\).
3Step 3: Verify Orthogonality
Two vectors \(\langle a_1, b_1 \rangle\) and \(\langle a_2, b_2 \rangle\) are orthogonal if their dot product is zero: \(a_1 \cdot a_2 + b_1 \cdot b_2 = 0\). For our vectors: \(-3 \times 5 + 5 \times 3 = 0\) and \(-3 \times -5 + 5 \times -3 = 0\). Both give 0, confirming orthogonality.
Key Concepts
Dot Product2D VectorsVector Components
Dot Product
The dot product is a crucial concept when dealing with vectors. It helps determine whether two vectors are orthogonal, or perpendicular, to each other. To calculate the dot product of two vectors \(\vec{a} = \langle a_1, b_1 \rangle\)and \(\vec{b} = \langle a_2, b_2 \rangle\)in 2D space, we perform the operation: \(a_1 \cdot a_2 + b_1 \cdot b_2\).
- If the dot product is zero, it means the vectors are orthogonal.
- The calculation involves individual multiplication of corresponding components followed by their sum.
2D Vectors
In a 2D plane, vectors are represented by two components which show direction and magnitude. A vector \(\vec{v} = \langle a, b \rangle\)is essentially a directed line segment from the origin. It has two main properties:
Understanding vectors in 2D is fundamental, as many real-world phenomena find applications with these simple representations.
- The direction, typically determined by the angle with respect to a reference axis.
- The magnitude, which is the length of the vector calculated as \(\sqrt{a^2 + b^2}\).
Understanding vectors in 2D is fundamental, as many real-world phenomena find applications with these simple representations.
Vector Components
Vector components describe the individual contributions of each part of a vector in their respective orthogonal directions. In a 2D vector like \(\vec{v} = \langle -3, 5 \rangle\), the components \(a = -3\) and \(b = 5\) represent its projection along the x and y axes, respectively.
Considering vector components helps visualize and manipulate vectors, offering insight into their behavior and interaction, especially in identifying orthogonality.
- Each component indicates how much the vector moves in a specific direction.
- When working with orthogonal vectors, swapping components with one sign change creates a new vector that is perpendicular.
Considering vector components helps visualize and manipulate vectors, offering insight into their behavior and interaction, especially in identifying orthogonality.
Other exercises in this chapter
Problem 18
Give the equation of the described plane in standard and general forms. Contains the point (4,1,1) and is orthogonal to the line \(\ell(t)=\left\\{\begin{array}
View solution Problem 18
Determine if the described lines are the same line, parallel lines, intersecting or skew lines. If intersecting, give the point of intersection. $$ \begin{array
View solution Problem 18
Find \(\|\vec{u}\|,\|\vec{v}\|,\|\vec{u}+\vec{v}\|\) and \(\|\vec{u}-\vec{v}\|\) \(\vec{u}=\langle-3,2,2\rangle, \quad \vec{v}=\langle 1,-1,1\rangle\)
View solution Problem 19
Give the equation of the described plane in standard and general forms. Contains the point (-4,7,2) and is parallel to the plane \(3(x-2)+8(y+1)-10 z=0\)
View solution