Problem 18
Question
A raffle is organized so that the amount paid for each ticket is determined by the number on the ticket. The tickets are numbered with the consecutive odd whole numbers \(1,3,5,7, \ldots\). Each contestant pays as many cents as the number on the ticket drawn. How much money will the raffle take in if 1000 tickets are sold? \(\$ 10,000\)
Step-by-Step Solution
Verified Answer
The raffle will take in \$10,000 if 1000 tickets are sold.
1Step 1: Understand the Ticket Numbering
The tickets are numbered using consecutive odd numbers starting from 1. These numbers are: 1, 3, 5, 7, and so on.
2Step 2: Identify the N-th Odd Number
The n-th odd number can be found using the formula: \(2n-1\). Thus, the 1000th odd number would be \(2 \times 1000 - 1 = 1999\).
3Step 3: Calculate the Sum of Odd Numbers
To find the total amount collected, sum all odd numbers from 1 to 1999. The sum of the first n odd numbers is \(n^2\). For 1000 tickets, it is \(1000^2 = 1000000\) cents.
4Step 4: Convert Cents to Dollars
Since 1 dollar is 100 cents, the total amount in dollars is \(1000000 \div 100 = 10000\).
Key Concepts
Odd NumbersArithmetic SequencesSummation of SeriesRaffle Problem Solving
Odd Numbers
Odd numbers are integers that are not divisible by 2. They have a remainder of 1 when divided by 2. Examples include 1, 3, 5, 7, etc. These numbers alternate with even numbers on the number line.
Properties of Odd Numbers:
- When you add two odd numbers, the result is even. For example, 3 + 5 = 8.
- Multiplying two odd numbers always results in another odd number. For instance, 3 × 5 = 15.
- Subtracting one odd number from another results in an even number.
Arithmetic Sequences
An arithmetic sequence is a sequence of numbers in which the difference between consecutive terms, called the 'common difference,' is constant. In our raffle problem, the tickets are numbered with odd numbers, which form an arithmetic sequence.Features of an Arithmetic Sequence:
- The formula for the n-th term of an arithmetic sequence is: \(a_n = a_1 + (n-1)d\), where \(a_1\) is the first term and \(d\) is the common difference.
- For consecutive odd numbers, the common difference \(d\) is 2, since each number differs from the previous by 2.
Summation of Series
Summation of series involves adding up the terms in a sequence. In the raffle example, we need to sum the prices of all tickets, given by consecutive odd numbers from 1 to 1999. Understanding Series Summation:
- The sum of the first \(n\) odd numbers is \(n^2\). For example, if \(n = 7\), the sum is \(1 + 3 + 5 + 7 + 9 + 11 + 13 = 49\), or \(7^2\).
- This property can be used for quick calculations. It saves time compared to adding each number individually in contexts like finding the total raffle income.
- Summation techniques are a powerful tool for evaluating large series efficiently, especially when the series involves simple patterns.
Raffle Problem Solving
Raffle problem solving often involves finding creative ways to interpret and calculate scenarios based on given rules. In this exercise, the ticket pricing is determined by a numerical sequence.Steps to Solve Raffle Problems:
- Identify the series or pattern involved. This ensures you correctly interpret each ticket's cost.
- Use arithmetic sequence formulas to determine the number range and sum them if necessary. For odd numbered tickets, apply the fact that their sum is \(n^2\) for \(n\) tickets.
- Always convert results as needed, such as turning cents into dollars to get a practical financial total.
Other exercises in this chapter
Problem 18
Find the sum of the infinite geometric sequence for which \(a_{n}=2\left(\frac{1}{3}\right)^{n+1} \cdot \frac{1}{3}\)
View solution Problem 18
If the 8th term of an arithmetic sequence is 37 and the 13 th term is 57 . find the 20 th term. 85
View solution Problem 18
\text { The 8th term of }-1,-\frac{3}{2},-\frac{9}{4},-\frac{27}{8}, \ldots-\frac{2187}{128}
View solution Problem 18
$$ 4,2,0,-2,-4, \ldots \quad-2 n+6 $$
View solution