Problem 18
Question
\(15-20\) Identify the curve by finding a Cartesian equation for the curve. $$r=2 \sin \theta+2 \cos \theta$$
Step-by-Step Solution
Verified Answer
The curve is a circle centered at (1,1) with radius \(\sqrt{2}\).
1Step 1: Express sine and cosine in Cartesian coordinates
First, we'll use the relationships between polar and Cartesian coordinates: \(x = r \cos \theta\) and \(y = r \sin \theta\). Also, know that \(\sin \theta = \frac{y}{r}\) and \(\cos \theta = \frac{x}{r}\). Substitute \(r=2\sin\theta + 2\cos\theta\) into these relationships.
2Step 2: Substitute polar relations into the given equation
Substitute the sine and cosine expressions into the given polar equation. You have: \[r = 2\left(\frac{y}{r}\right) + 2\left(\frac{x}{r}\right)\]Multiply through by \(r\) to clear the fractions:\[r^2 = 2y + 2x\]
3Step 3: Express \(r^2\) in terms of \(x\) and \(y\)
Recall the polar to Cartesian conversion where \(r^2 = x^2 + y^2\). Replace \(r^2\) with \(x^2 + y^2\) in the equation:\[x^2 + y^2 = 2x + 2y\]
4Step 4: Rearrange into standard form
Rearrange the equation into the standard form by completing the square for \(x\) and \(y\).\[(x^2 - 2x) + (y^2 - 2y) = 0\]
5Step 5: Complete the square
Complete the square for both \(x\) and \(y\):- For \(x:\) \((x^2 - 2x) + 1 = (x - 1)^2\)- For \(y:\) \((y^2 - 2y) + 1 = (y - 1)^2\)So, the equation becomes:\[(x-1)^2 + (y-1)^2 = 2\]
6Step 6: Identify the type of curve
The equation \((x - 1)^2 + (y - 1)^2 = 2\) represents a circle with center at \((1, 1)\) and radius \(\sqrt{2}\).
Key Concepts
Cartesian coordinatesPolar coordinatesCircle equationTrigonometric identities
Cartesian coordinates
In mathematics, Cartesian coordinates allow us to pinpoint a location in a two-dimensional plane using two values: usually represented as \((x, y)\). These coordinates describe a point's horizontal and vertical positions from an origin, where the horizontal axis is the x-axis, and the vertical axis is the y-axis.
- Given any point, \(x\) indicates the distance along the x-axis.
- The \(y\) coordinate specifies the distance along the y-axis.
Polar coordinates
Polar coordinates, unlike Cartesian coordinates, describe a point's position based on its distance and direction from a fixed point, known as the origin. Here, a point is represented by \((r, \theta)\), where:
- \(r\) is the radius or distance from the origin.
- \(\theta\) is the angle with respect to the positive x-axis.
- \(x = r \cos \theta\)
- \(y = r \sin \theta\)
Circle equation
A circle is a special kind of curve in a plane, defined by all points equidistant from a center point. In Cartesian coordinates, a circle's equation typically follows the format:\[(x - h)^2 + (y - k)^2 = r^2\]where \((h, k)\) is the center of the circle, and \(r\) is its radius.When the center is located at the origin \((0, 0)\), the equation simplifies to:\[x^2 + y^2 = r^2\]In this exercise, we discovered that our polar equation translated into the Cartesian form representing a circle:\[(x - 1)^2 + (y - 1)^2 = 2\]Here, the circle is centered at \((1, 1)\) with a radius \(\sqrt{2}\). Identifying and manipulating these equations is fundamental in geometry, allowing us to visualize and interpret circular shapes.
Trigonometric identities
Trigonometric identities are fundamental relationships between trig functions that hold true for all angles. They help simplify complex expressions in both pure and applied mathematics, including polar to Cartesian conversions.Two crucial identities we often rely on during conversions are:
- \(\sin^2 \theta + \cos^2 \theta = 1\)
- \(\tan \theta = \frac{\sin \theta}{\cos \theta}\)
- \(\sin \theta = \frac{y}{r}\)
- \(\cos \theta = \frac{x}{r}\)
Other exercises in this chapter
Problem 18
Find the points on the curve where the tangent is horizontal or vertical. If you have a graphing device, graph the curve to check your work. $$x=2 t^{3}+3 t^{2}
View solution Problem 18
\(17-21\) Find the area of the region enclosed by one loop of the curve. $$ r=4 \sin 3 \theta $$
View solution Problem 18
(a) Eliminate the parameter to find a Cartesian equation of the curve. (b) Sketch the curve and indicate with an arrow the direction in which the curve is trace
View solution Problem 19
Graph the conics \(r=e /(1-e \cos \theta)\) with \(e=0.4,0.6\) . \(0.8,\) and 1.0 on a common screen. How does the value of \(e\) affect the shape of the curve?
View solution