Problem 18
Question
\(15-18\) Find a vector equation and parametric equations for the line segment that joins \(P\) to \(Q .\) $$ P(-2,4,0), \quad Q(6,-1,2) $$
Step-by-Step Solution
Verified Answer
The vector equation is \( \vec{r}(t) = (-2, 4, 0) + t(8, -5, 2) \) and parametric equations are \( x = -2 + 8t, y = 4 - 5t, z = 2t \) for \( 0 \leq t \leq 1 \).
1Step 1: Determine the Direction Vector
First, we need to find the direction vector from point \( P \) to point \( Q \). This is done by subtracting the coordinates of \( P \) from \( Q \). The direction vector \( \vec{d} \) is \( Q - P = (6 - (-2), -1 - 4, 2 - 0) = (8, -5, 2).\)
2Step 2: Establish the Vector Equation of the Line
To find the vector equation of the line segment, we use the formula \( \vec{r}(t) = \vec{P} + t \cdot \vec{d} \) where \( \vec{P} \) is the position vector of point \( P \) and \( t \) is a parameter. The vector equation becomes \( \vec{r}(t) = (-2, 4, 0) + t(8, -5, 2).\)
3Step 3: Write the Parametric Equations
Extract the components from the vector equation to write the parametric equations. From \( \vec{r}(t) = (-2, 4, 0) + t(8, -5, 2) \), the parametric equations are: \[ x = -2 + 8t, \]\[ y = 4 - 5t, \]\[ z = 2t. \]
4Step 4: Specify the Parameter Range
Since the question asks for the line segment, the parameter \( t \) should vary between 0 and 1 to ensure the segment spans from \( P \) to \( Q \). Thus, the parameter range is \( 0 \leq t \leq 1 \).
Key Concepts
Parametric EquationsDirection VectorLine SegmentCoordinate Geometry
Parametric Equations
Parametric equations represent a way to describe a line or curve in space where each coordinate depends on a common parameter, usually denoted as \( t \). This makes it easier to define the position of points along a line or curve.
- Each coordinate in space (\( x \), \( y \), and \( z \) for three dimensions) is expressed as a function of \( t \).
- This helps in representing not just infinite lines, but also specific segments where the parameter \( t \) is restricted within certain values.
Direction Vector
The direction vector is crucial in defining the orientation and direction of a line in space.
This vector becomes part of the equation used to describe the line or segment in space.
- It tells us how the line extends from one point to another by highlighting the difference between the two points.
- To find the direction vector \( \vec{d} \) between two points \( P(-2,4,0) \) and \( Q(6,-1,2) \), you perform a simple subtraction: \( \vec{d} = Q - P = (6 - (-2), -1 - 4, 2 - 0) = (8, -5, 2) \).
This vector becomes part of the equation used to describe the line or segment in space.
Line Segment
A line segment is simply a part of a line that connects two points, without extending beyond them.
This restrained parameter reflects the finite nature of a line segment.
- It’s different from an infinite line as it has clear starting and ending points. In our case, these points are \( P(-2,4,0) \) and \( Q(6,-1,2) \).
- To describe this segment analytically, we use the derived parametric equations and restrict the parameter \( t \) such that it spans the desired endpoints.
This restrained parameter reflects the finite nature of a line segment.
Coordinate Geometry
Coordinate geometry, or analytic geometry, combines algebra and geometry to solve problems involving coordinates in space.
This field helps visualize and calculate geometric entities in two, three, or even higher-dimensional spaces.
- It provides a powerful framework to describe geometric shapes and forms, like lines, circles, and polygons, using algebraic equations.
- For lines and segments, it employs coordinates to express points and direction, allowing precise and analytical study of geometric problems.
This field helps visualize and calculate geometric entities in two, three, or even higher-dimensional spaces.
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