Problem 179
Question
On an interval of \([0,2 \pi),\) can the sine and cosine values of a radian measure ever be equal? If so, where?
Step-by-Step Solution
Verified Answer
Yes, \( \theta = \frac{\pi}{4} \) and \( \theta = \frac{5\pi}{4} \).
1Step 1: Set Up Equation
We want to determine if there are any angles \( \theta \) in the interval \([0, 2\pi)\) where \( \sin(\theta) = \cos(\theta) \). To find this, we set the equation \( \sin(\theta) = \cos(\theta) \).
2Step 2: Solve the Equation
To solve \( \sin(\theta) = \cos(\theta) \), divide both sides by \( \cos(\theta) \), assuming \( \cos(\theta) eq 0 \), to get \( \tan(\theta) = 1 \).
3Step 3: Find Solutions for Tangent
The equation \( \tan(\theta) = 1 \) is true when \( \theta = \frac{\pi}{4} + n\pi \) for integers \( n \). However, we want \( \theta \) in the interval \([0, 2\pi)\).
4Step 4: Determine Valid \( \theta \) in the Interval
Within the interval \([0, 2\pi)\), the solutions are \( \theta = \frac{\pi}{4} \) and \( \theta = \frac{5\pi}{4} \). These are the angles where \( \tan(\theta) = 1 \).
5Step 5: Verify Solutions
At \( \theta = \frac{\pi}{4} \): \( \sin(\theta) = \cos(\theta) = \frac{\sqrt{2}}{2} \). Similarly, at \( \theta = \frac{5\pi}{4} \), \( \sin(\theta) = \cos(\theta) = -\frac{\sqrt{2}}{2} \). Both values satisfy \( \sin(\theta) = \cos(\theta) \).
Key Concepts
Sine FunctionCosine FunctionTangent Function
Sine Function
The sine function is a fundamental concept in trigonometry, often abbreviated as "sin". It relates to the ratio of the opposite side to the hypotenuse in a right-angled triangle. When you think about the unit circle, the sine of an angle is the y-coordinate of the point on the circle corresponding to that angle.
The sine function is periodic, which means it repeats its values in regular intervals. Specifically, the sine function has a period of \( 2\pi \), meaning that \( \sin(\theta) = \sin(\theta + 2\pi) \) for any angle \( \theta \). This property of periodicity is crucial when analyzing the behavior of the sine function over various intervals.
The sine function is periodic, which means it repeats its values in regular intervals. Specifically, the sine function has a period of \( 2\pi \), meaning that \( \sin(\theta) = \sin(\theta + 2\pi) \) for any angle \( \theta \). This property of periodicity is crucial when analyzing the behavior of the sine function over various intervals.
- The sine function starts at 0 when \( \theta = 0 \), reaches its maximum value of 1 when \( \theta = \frac{\pi}{2} \), decreases back to 0 at \( \theta = \pi \), continues to -1 at \( \theta = \frac{3\pi}{2} \), and returns to 0 at \( \theta = 2\pi \).
- This pattern repeats for every subsequent \( 2\pi \) interval.
Cosine Function
The cosine function, abbreviated as "cos", is another pillar of trigonometry. Similar to the sine function, it also arises from the ratios in a right-angled triangle, but in this case, it is the ratio of the adjacent side to the hypotenuse. On the unit circle, the cosine of an angle is represented by the x-coordinate of the corresponding point on the circle.
The cosine function shares the same periodicity as the sine function, repeating every \( 2\pi \) interval, which makes it easy to analyze over any given range. This periodic nature means that \( \cos(\theta) = \cos(\theta + 2\pi) \), ensuring that the function's values are consistent every full circle around the unit circle.
The cosine function shares the same periodicity as the sine function, repeating every \( 2\pi \) interval, which makes it easy to analyze over any given range. This periodic nature means that \( \cos(\theta) = \cos(\theta + 2\pi) \), ensuring that the function's values are consistent every full circle around the unit circle.
- The cosine function reaches its maximum value of 1 at \( \theta = 0 \), decreases to 0 at \( \theta = \frac{\pi}{2} \), continues to a minimum of -1 at \( \theta = \pi \), goes back to 0 at \( \theta = \frac{3\pi}{2} \), and returns to 1 by the time \( \theta = 2\pi \).
- Because of its shape and pattern, it closely mirrors the behavior of the sine function, but is phase-shifted by \( \frac{\pi}{2} \).
Tangent Function
The tangent function, abbreviated as "tan", is another essential trigonometric function. It is typically defined as the ratio of the sine function to the cosine function, \( \tan(\theta) = \frac{\sin(\theta)}{\cos(\theta)} \). In the context of the unit circle, the tangent can be seen as the slope of the line that passes through the origin and the point on the circle.
Unlike the sine and cosine functions, the tangent function has a shorter period, repeating its values every \( \pi \) rather than \( 2\pi \). This difference arises because the function \( \tan(\theta) \) becomes undefined at angles where \( \cos(\theta) = 0 \), notably at \( \theta = \frac{\pi}{2} + n\pi \), where \( n \) is an integer.
Unlike the sine and cosine functions, the tangent function has a shorter period, repeating its values every \( \pi \) rather than \( 2\pi \). This difference arises because the function \( \tan(\theta) \) becomes undefined at angles where \( \cos(\theta) = 0 \), notably at \( \theta = \frac{\pi}{2} + n\pi \), where \( n \) is an integer.
- The tangent function is positive in the first and third quadrants, where sine and cosine share the same sign, and negative in the second and fourth quadrants, where they differ.
- Key angles occur at \( \theta = \frac{\pi}{4} \) and \( \theta = \frac{5\pi}{4} \) within the interval \([0, 2\pi)\), where \( \tan(\theta) = 1 \).
Other exercises in this chapter
Problem 177
For the following exercises, use this scenario: A child enters a carousel that takes one minute to revolve once around. The child enters at the point \((0,1),\)
View solution Problem 178
For the following exercises, use this scenario: A child enters a carousel that takes one minute to revolve once around. The child enters at the point \((0,1),\)
View solution Problem 181
For any angle in quadrant II, if you knew the sine of the angle, how could you determine the cosine of the angle?
View solution Problem 183
Tangent and cotangent have a period of \(\pi\) . What does this tell us about the output of these functions?
View solution