Problem 179
Question
Find the equation for the tangent plane to the surface at the indicated point. \(z=\sin x+\sin y+\sin (x+y), P(0,0,0)\)
Step-by-Step Solution
Verified Answer
The tangent plane at P(0,0,0) is \( z = 2x + 2y \).
1Step 1: Identify the function and point
We are given the surface function as \( z = \sin x + \sin y + \sin (x+y) \), and the point \( P(0,0,0) \) where we need to find the equation of the tangent plane.
2Step 2: Calculate the Partial Derivatives
To find the tangent plane, first calculate the partial derivatives of \( z \) with respect to \( x \) and \( y \). The partial derivative with respect to \( x \) is \( \frac{\partial z}{\partial x} = \cos x + \cos (x+y) \). The partial derivative with respect to \( y \) is \( \frac{\partial z}{\partial y} = \cos y + \cos (x+y) \).
3Step 3: Evaluate the Partial Derivatives at Point P
Evaluate the partial derivatives at the point \( P(0,0,0) \). Substitute \( x = 0 \) and \( y = 0 \) into the partial derivatives: \( \frac{\partial z}{\partial x} (0,0) = \cos 0 + \cos 0 = 2 \) and \( \frac{\partial z}{\partial y} (0,0) = \cos 0 + \cos 0 = 2 \).
4Step 4: Find the Tangent Plane Equation
The equation for the tangent plane at a point \((x_0, y_0, z_0)\) is given by: \[z - z_0 = \frac{\partial z}{\partial x} (x_0, y_0)(x - x_0) + \frac{\partial z}{\partial y} (x_0, y_0)(y - y_0)\]Substitute \( (x_0, y_0, z_0) = (0,0,0) \) and the evaluated partial derivatives: \[z = 2(x - 0) + 2(y - 0) = 2x + 2y\]Thus, the equation for the tangent plane is \( z = 2x + 2y \).
Key Concepts
Partial DerivativesSurface FunctionTangent Plane Equation
Partial Derivatives
When working with functions of multiple variables, the concept of partial derivatives is crucial. A partial derivative measures the rate at which the function changes as one of the variables changes, while keeping the other variables constant. In simpler terms, it's a bit like looking at a slice of multi-dimensional data.
For the given surface function, you have:
For the given surface function, you have:
- The partial derivative with respect to \( x \), denoted as \( \frac{\partial z}{\partial x} \), shows how \( z \) changes if you slightly vary \( x \) and keep \( y \) constant.
- Similarly, \( \frac{\partial z}{\partial y} \) represents the change in \( z \) as \( y \) varies, holding \( x \) fixed.
Surface Function
A surface function describes a surface in a three-dimensional space using a variable equation, often in the form \( z = f(x,y) \). In our example, the surface is defined by \( z = \sin x + \sin y + \sin (x+y) \). This equation represents a wave-like surface, combining sinusoidal variations due to \( x \), \( y \), and the sum \( x+y \).
Understanding surface functions involves recognizing how changes in \( x \) and \( y \) affect \( z \). These relationships can be visualized as ripples on a water surface, where each point on the surface holds a specific \( z \) value directly related to its \( x \) and \( y \) coordinates.
Understanding surface functions involves recognizing how changes in \( x \) and \( y \) affect \( z \). These relationships can be visualized as ripples on a water surface, where each point on the surface holds a specific \( z \) value directly related to its \( x \) and \( y \) coordinates.
- When \( x \) increases, certain parts of the surface rise or fall due to the \( \sin x \) component.
- The same happens with the \( \sin y \) and \( \sin(x+y) \). Each part adds a layer of complexity to the shape.
Tangent Plane Equation
The concept of a tangent plane is an extension of the tangent line idea from two-dimensional calculus to three dimensions. While a tangent line just touches a curve at a point, a tangent plane just "kisses" a surface at a given point.
To find the tangent plane equation, you use the partial derivatives you've calculated. These partials represent slopes in the \( x \) and \( y \) directions.
The general formula for the tangent plane equation is: \[ z - z_0 = \frac{\partial z}{\partial x} (x_0, y_0)(x - x_0) + \frac{\partial z}{\partial y} (x_0, y_0)(y - y_0) \] This equation tells you exactly how the plane is oriented at point \((x_0, y_0, z_0)\).
To find the tangent plane equation, you use the partial derivatives you've calculated. These partials represent slopes in the \( x \) and \( y \) directions.
The general formula for the tangent plane equation is: \[ z - z_0 = \frac{\partial z}{\partial x} (x_0, y_0)(x - x_0) + \frac{\partial z}{\partial y} (x_0, y_0)(y - y_0) \] This equation tells you exactly how the plane is oriented at point \((x_0, y_0, z_0)\).
- The terms \( \frac{\partial z}{\partial x}(x - x_0) \) and \( \frac{\partial z}{\partial y}(y - y_0) \) define the tilt or slope of the plane.
- Plugging in our example's values at point \( (0,0,0) \), where both partials equal 2, the equation simplifies to \( z = 2x + 2y \). This shows a plane rising equally in the \( x \) and \( y \) direction.
Other exercises in this chapter
Problem 177
Find the equation for the tangent plane to the surface at the indicated point. \(x^{3}+y^{3}=3 x y z, P\left(1,2, \frac{3}{2}\right)\)
View solution Problem 178
Find the equation for the tangent plane to the surface at the indicated point. \(\quad z=\operatorname{axy}, P\left(1, \frac{1}{a}, 1\right)\)
View solution Problem 180
Find the equation for the tangent plane to the surface at the indicated point. \(h(x, y)=\ln \sqrt{x^{2}+y^{2}}, P(3,4)\)
View solution Problem 181
Find the equation for the tangent plane to the surface at the indicated point. \(z=x^{2}-2 x y+y^{2}, P(1,2,1)\)
View solution