Problem 178
Question
Prove that if \(X\) and \(Y\) are two independent random variables, then \(U=g(X)\) and \(V=h(Y)\) are also independent.
Step-by-Step Solution
Verified Answer
If \(X\) and \(Y\) are independent, then any functions of \(X\) and \(Y\), denoted as \(U = g(X)\) and \(V = h(Y)\), are also independent. This is confirmed by substituting \(U = g(X)\) and \(V = h(Y)\) into the independence formula to find that the joint probability mass (or density) function of \(U\) and \(V\) equals the product of their individual mass (or density) functions for all values, which is the definition of independence.
1Step 1: Define the Random Variables and Functions
Let \(X\) and \(Y\) be two independent random variables and \(g\) and \(h\) be any functions. Define \(U = g(X)\) and \(V = h(Y)\). The task is to prove that \(U\) and \(V\) are also independent.
2Step 2: Understand the Definition of Independence
Remember that, by definition, two random variables \(A\) and \(B\) are independent if the joint probability mass function is the product of their individual mass functions, that is, \(P(A, B) = P(A)P(B)\) for all values of \(A\) and \(B\). If the random variables are continuous, the same holds for their density functions.
3Step 3: Apply the Definition of Independence to the Functions
Apply the definition of independence to \(U\) and \(V\). By definition, \(U\) and \(V\) are independent if the joint probability mass (or density) function of \(U\) and \(V\) equals the product of their individual mass (or density) functions for all values.
4Step 4: Substitute \(U\) and \(V\) By Their Definitions
Substitute \(U = g(X)\) and \(V = h(Y)\) into the formula. Because \(X\) and \(Y\) are independent, their joint mass (or density) function equals the product of their individual mass (or density) functions. This confirms that the joint mass (or density) function of \(U\) and \(V\) equals the product of their individual mass (or density) functions for all values, proving that \(U\) and \(V\) are independent.
Key Concepts
Independent Random VariablesTransformation of VariablesJoint Probability Density Function
Independent Random Variables
Understanding the concept of independent random variables is fundamental in probability theory. Two random variables, say \(X\) and \(Y\), are considered independent if the probability of their joint occurrence is equivalent to the product of their individual probabilities. Mathematically, for all possible values of \(x\) and \(y\), this is expressed as:\[P(X = x, Y = y) = P(X = x) \cdot P(Y = y)\]This independence implies that the behavior or outcome of one random variable does not influence or alter the outcome of the other. In practice, this can be visualized as events happening simultaneously yet distinctly.
- Example: Rolling two dice: The result of the first die does not affect the result of the second.
- Significance: Independent variables simplify calculations of probabilities and expectations.
Transformation of Variables
Transformation of variables is a technique where we apply functions to random variables to create new variables. If \(X\) and \(Y\) are independent random variables, and we define \(U = g(X)\) and \(V = h(Y)\) where \(g\) and \(h\) are functions, the goal is to explore if \(U\) and \(V\) are also independent.The transformation leverages functions to map one set of values to another. Importantly, in probability, this concept is beneficial because it allows for generalizations where variables can be manipulated yet preserve properties like independence.
- Procedure: Choose functions \(g\) and \(h\) that map random variables \(X\) and \(Y\) to \(U\) and \(V\) respectively.
- Key Idea: Despite transformations, if \(X\) and \(Y\) are initially independent, \(U\) and \(V\) will typically remain independent.
Joint Probability Density Function
A joint probability density function (pdf) describes the likelihood of two continuous random variables occurring in tandem. For two random variables \(X\) and \(Y\), the joint pdf is denoted as \(f_{X,Y}(x, y)\).
- Continuous Variables: Used for continuous data as opposed to discrete data, which uses probability mass functions.
- Mathematical Expression: The joint pdf for independent variables is the product of their individual densities: \[f_{X,Y}(x, y) = f_X(x) \cdot f_Y(y)\]
Other exercises in this chapter
Problem 176
Suppose \(f_{X, Y}(x, y)=x y e^{-(x+y)}, x>0, y>0\). Prove for any real numbers \(a, b, c\), and \(d\) that $$ P(a
View solution Problem 177
Given the joint pdf \(f_{X, Y}(x, y)=2 x+y-2 x y\), \(0
View solution Problem 179
If two random variables \(X\) and \(Y\) are defined over a region in the \(X Y\)-plane that is not a rectangle (possibly infinite) with sides parallel to the co
View solution Problem 180
Write down the joint probability density function for a random sample of size \(n\) drawn from the exponential pdf, \(f_{X}(x)=(1 / \lambda) e^{-x / \lambda}, x
View solution